Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Probability Refer to the results from the 150 subjects in Cumulative Review Exercise 5.

a.Find the probability that if 1 of the 150 subjects is randomly selected, the result is a woman who spent the money.

b.Find the probability that if 1 of the 150 subjects is randomly selected, the result is a woman who spent the money or was given a single 100-yuan bill.

c.If two different women are randomly selected, find the probability that they both spent the money.

Short Answer

Expert verified

a. The probability of selecting a woman who spent the money is equal to 0.853.

b. The probability of selecting a woman who spent the money and received a single 100 Yuan bill is equal to 0.953.

c. The probability of selecting two different women who spent the money is equal to 0.727.

Step by step solution

01

Given information

A table is devised that shows the number of women who spent/kept the money depending on whether they received a single bill or smaller bills.

02

Probability

a.

The total number of women sampled is equal to 150.

The number of women who spent the money is equal to:

\(60 + 68 = 128\)

The probability of selecting a woman who spent the money is equal to:

\(\begin{aligned}{c}P = \frac{{{\rm{Number}}\;{\rm{of}}\;{\rm{women}}\;{\rm{who}}\;{\rm{spent}}\;{\rm{the}}\;{\rm{money}}}}{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{women}}}}\\ = \frac{{128}}{{150}}\\ = 0.853\end{aligned}\)

Thus, the probability of selecting a woman who spent the money is equal to 0.853.

b.

Let A be the event of selecting a woman who spent the money.

Let B be the event of selecting a woman who received a single 100 Yuan bill.

The probability of selecting a woman who spent the money or received a single 100 Yuan bill is denoted by:

\(P\left( {A\;or\;B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A\;and\;B} \right)\)

The probability of occurrence of event A is equal to:

\(\begin{aligned}{c}P\left( A \right) = \frac{{{\rm{Number}}\;{\rm{of}}\;{\rm{women}}\;{\rm{who}}\;{\rm{spent}}\;{\rm{the}}\;{\rm{money}}}}{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{women}}}}\\ = \frac{{128}}{{150}}\\ = 0.853\end{aligned}\)

The probability of occurrence of B is equal to:

\(\begin{aligned}{c}P\left( B \right) = \frac{{{\rm{Number}}\;{\rm{of}}\;{\rm{women}}\;{\rm{who}}\;{\rm{got}}\;{\rm{a}}\;{\rm{single}}\;{\rm{100}}\;{\rm{Yuan}}\;{\rm{bill}}}}{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{women}}}}\\ = \frac{{60 + 15}}{{150}}\\ = \frac{{75}}{{150}}\\ = 0.5\end{aligned}\)

The probability of occurrence of both A and B is equal to:

\(\begin{aligned}{c}P\left( {A\;{\rm{and}}\;B} \right) = \frac{{{\rm{Number}}\;{\rm{of}}\;{\rm{women}}\;{\rm{who}}\;{\rm{spent}}\;{\rm{the}}\;{\rm{money}}\;{\rm{and}}\;{\rm{got}}\;{\rm{a}}\;{\rm{single}}\;{\rm{100}}\;{\rm{Yuan}}\;{\rm{bill}}}}{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{women}}}}\\ = \frac{{60}}{{150}}\\ = 0.4\end{aligned}\)

Thus, the probability of occurrence of A or B is equal to:

\(\begin{aligned}{c}P\left( {A\;or\;B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A\;and\;B} \right)\\ = 0.853 + 0.5 - 0.4\\ = 0.953\end{aligned}\)

The probability of selecting a woman who spent the money and received a single 100 Yuan bill is equal to 0.953.

c.

It is given that two different women are to be randomly selected.

This implies that sampling is done without replacement.

Thus, the probability of selecting two different women who spent the money is equal to:

\(\begin{aligned}{c}P = \frac{{128}}{{150}} \times \frac{{127}}{{149}}\\ = 0.853 \times 0.852\\ = 0.727\end{aligned}\)

Therefore, the probability of selecting two different women who spent the money is equal to 0.727.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The table below includes results from polygraph (lie detector) experiments conducted by researchers Charles R. Honts (Boise State University) and Gordon H. Barland (Department of Defense Polygraph Institute). In each case, it was known if the subject lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truths and lies?

Did the subject Actually Lie?


No (Did Not Lie)

Yes (Lied)

Polygraph test indicates that the subject lied.


15

42

Polygraph test indicates that the subject did not lied.


32

9

Flat Tire and Missed Class A classic story involves four carpooling students who missed a test and gave as an excuse a flat tire. On the makeup test, the instructor asked the students to identify the particular tire that went flat. If they really didnโ€™t have a flat tire, would they be able to identify the same tire? The author asked 41 other students to identify the tire they would select. The results are listed in the following table (except for one student who selected the spare). Use a 0.05 significance level to test the authorโ€™s claim that the results fit a uniform distribution. What does the result suggest about the likelihood of four students identifying the same tire when they really didnโ€™t have a flat tire?

Tire

Left Front

Right Front

Left Rear

Right Rear

Number Selected

11

15

8

16

A case-control (or retrospective) study was conductedto investigate a relationship between the colors of helmets worn by motorcycle drivers andwhether they are injured or killed in a crash. Results are given in the table below (based on datafrom โ€œMotorcycle Rider Conspicuity and Crash Related Injury: Case-Control Study,โ€ by Wellset al., BMJ USA,Vol. 4). Test the claim that injuries are independent of helmet color. Shouldmotorcycle drivers choose helmets with a particular color? If so, which color appears best?

Color of helmet


Black

White

Yellow/Orange

Red

Blue

Controls (not injured)

491

377

31

170

55

Cases (injured or killed)

213

112

8

70

26

The accompanying table lists results of overtime football

games before and after the overtime rule was changed in the National Football League in 2011. Use a 0.05 significance level to test the claim of independence between winning an overtime game and whether playing under the old rule or the new rule. What do the results suggest about

the effectiveness of the rule change?

Before Rule Change

After Rule Change

Overtime Coin Toss Winner Won the Game

252

24

Overtime Coin Toss Winner Lost the Game

208

23

Motor Vehicle Fatalities The table below lists motor vehicle fatalities by day of the week for a recent year (based on data from the Insurance Institute for Highway Safety). Use a 0.01 significance level to test the claim that auto fatalities occur on the different days of the week with the same frequency. Provide an explanation for the results.

Day

Sun.

Mon.

Tues.

Wed.

Thurs.

Fri.

Sat.

Frequency

5304

4002

4082

4010

4268

5068

5985

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free