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In Exercises 5–20, conduct the hypothesis test and provide the test statistic and the P-value and, or critical value, and state the conclusion.

Kentucky Derby The table below lists the frequency of wins for different post positions through the 141st running of the Kentucky Derby horse race. A post position of 1 is closest to the inside rail, so the horse in that position has the shortest distance to run. (Because the number of horses varies from year to year, only the first 10 post positions are included.) Use a 0.05 significance level to test the claim that the likelihood of winning is the same for the different post positions. Based on the result, should bettors consider the post position of a horse racing in the Kentucky Derby?

Post Position

1

2

3

4

5

6

7

8

9

10

Wins

19

14

11

15

15

7

8

12

5

11

Short Answer

Expert verified

There is not enough evidence to conclude that the probability of winning is not the same for different post positions.

Since there is no significant difference in the frequency of wins for the different post positions, there isn’t a need for the bettors to consider the post position of a horse in the Kentucky Derby.

Step by step solution

01

Given information

The frequency of wins is provided for the different post positions in the 141 Kentucky Derby horse races.

02

Check the requirements of the test

Assume the experimental units are obtained by random sampling.

If the expected frequencies are larger than 5, the requirements of the test are fulfilled.

Let O denote the observed frequencies of the wins.

The following values are obtained:

\(\begin{aligned}{l}{O_1} = 19\\{O_2} = 14\\{O_3} = 11\\{O_4} = 15\end{aligned}\)

\(\begin{aligned}{l}{O_5} = 15\\{O_6} = 7\\{O_7} = 8\\{O_8} = 12\end{aligned}\)

\(\begin{aligned}{l}{O_9} = 5\\{O_{10}} = 11\end{aligned}\)

The sum of all observed frequencies is computed below:

\(\begin{aligned}{c}n = 19 + 14 + .... + 11\\ = 117\end{aligned}\)

Let E denote the expected frequencies.It is given that the number of wins is expected to be the same for all the positions.

The expected frequencies for each of the 10 positions are equal to:

\(\begin{aligned}{c}E = \frac{{117}}{{10}}\\ = 11.7\end{aligned}\)

Thus, the requirements of the test are satisfied.

03

State the hypotheses

The null hypothesis for conducting the given test is as follows:

\({H_0}:\)The probability of winning is the same for different post positions.

The alternative hypothesis is as follows:

\({H_a}:\)The probability of winning is not the same for different post positions.

04

Conduct the hypothesis test

The table below shows the necessary calculations:

Post Position

O

E

\(\left( {O - E} \right)\)

\({\left( {O - E} \right)^2}\)

\(\frac{{{{\left( {O - E} \right)}^2}}}{E}\)

1

19

11.7

7.3

53.29

4.5547

2

14

11.7

2.3

5.29

0.4521

3

11

11.7

-0.7

0.49

0.0419

4

15

11.7

3.3

10.89

0.9308

5

15

11.7

3.3

10.89

0.9308

6

7

11.7

-4.7

22.09

1.8880

7

8

11.7

-3.7

13.69

1.1701

8

12

11.7

0.3

0.09

0.0077

9

5

11.7

-6.7

44.89

3.8367

10

11

11.7

-0.7

0.49

0.0419

The value of the test statistic is equal to:

\(\begin{aligned}{c}{\chi ^2} = \sum {\frac{{{{\left( {O - E} \right)}^2}}}{E}} \;\;\\ = 4.5547 + 0.4521 + ... + 0.0419\\ = 13.855\end{aligned}\)

Thus,\({\chi ^2} = 13.855\).

Let k be the number of posts that are equal to 10.

The degrees of freedom for\({\chi ^2}\)is computed below:

\(\begin{aligned}{c}df = k - 1\\ = 10 - 1\\ = 9\end{aligned}\)

05

State the decision

The chi-square table is used to determine the critical value of\({\chi ^2}\)at\(\alpha = 0.05\)with 9 degrees of freedom as 16.919.

The p-value is equal to,

\(\begin{aligned}{c}p - value = P\left( {{\chi ^2} > 13.855} \right)\\ = 0.128\end{aligned}\)

Since the test statistic value is less than the critical value and the p-value is greater than 0.05, the null hypothesis is failed to be rejected.

06

Determine the conclusion

There is enough evidence to conclude that the probability of winning is same for different post positions.

Since there is no significant difference in the frequency of wins for the different post positions, there isn’t the need for the bettors to consider the post position of a horse in the Kentucky Derby.

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Most popular questions from this chapter

Questions 6–10 refer to the sample data in the following table, which describes the fate of the passengers and crew aboard the Titanic when it sank on April 15, 1912. Assume that the data are a sample from a large population and we want to use a 0.05 significance level to test the claim that surviving is independent of whether the person is a man, woman, boy, or girl.


Men

Women

Boys

Girls

Survived

332

318

29

27

Died

1360

104

35

18

Given that the P-value for the hypothesis test is 0.000 when rounded to three decimal places, what do you conclude? What do the results indicate about the rule that women and children should be the first to be saved?

The accompanying TI-83/84 Plus calculator display results from thehypothesis test described in Exercise 1. Assume that the hypothesis test requirements are allsatisfied. Identify the test statistic and the P-value (expressed in standard form and rounded tothree decimal places), and then state the conclusion about the null hypothesis.

Exercises 1–5 refer to the sample data in the following table, which summarizes the last digits of the heights (cm) of 300 randomly selected subjects (from Data Set 1 “Body Data” in Appendix B). Assume that we want to use a 0.05 significance level to test the claim that the data are from a population having the property that the last digits are all equally likely.

Last Digit

0

1

2

3

4

5

6

7

8

9

Frequency

30

35

24

25

35

36

37

27

27

24

Is the hypothesis test left-tailed, right-tailed, or two-tailed?

A study of seat belt users andnonusers yielded the randomly selected sample data summarized in the given table (based on data from “What Kinds of People Do Not Use Seat Belts?” by Helsing and Comstock, American Journal of Public Health,Vol. 67, No. 11). Test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke more are lessconcerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data?

Number of Cigarettes Smoked per Day

0

1-14

15-34

35 and over

Wear Seat Belts

175

20

42

6

Don't Wear Seat Belts

149

17

41

9

Do World War II Bomb Hits Fit a Poisson Distribution? In analyzing hits by V-1 buzz bombs in World War II, South London was subdivided into regions, each with an area of 0.25\(k{m^2}\). Shown below is a table of actual frequencies of hits and the frequencies expected with the Poisson distribution. (The Poisson distribution is described in Section 5-3.) Use the values listed and a 0.05 significance level to test the claim that the actual frequencies fit a Poisson distribution. Does the result prove that the data conform to the Poisson distribution?

Number of Bomb Hits

0

1

2

3

4

Actual Number of Regions

229

211

93

35

8

Expected Number of Regions

(from Poisson Distribution)

227.5

211.4

97.9

30.5

8.7

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