Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Finding Critical Values. In Exercises 5–8, find the critical value \[{{\rm{z}}_{{{\rm{\alpha }} \mathord{\left/

{\vphantom {{\rm{\alpha }} {\rm{2}}}} \right.

\kern-\nulldelimiterspace} {\rm{2}}}}}\]that corresponds to the given confidence level.

98%

Short Answer

Expert verified

The critical value \({z_{\frac{\alpha }{2}}}\)for 98% level of confidence is 2.33.

Step by step solution

01

Given information

The level of significance is 98%.

02

Describe the concept of critical value

A critical value is a point on the test distribution that is compared to the test statistics to determine whether to reject the null hypothesis. It is denoted by \({z_{\frac{\alpha }{2}}}\)which is equal to z score within the area of \[\frac{\alpha }{2}\]in the right tail of the standard normal distribution for\(\alpha \) level of significance.

03

Find the critical value

When finding a critical value\({z_{\frac{\alpha }{2}}}\)for a particular value of \[\alpha \], note that \[\frac{\alpha }{2}\] is the cumulative area to the right of\({z_{\frac{\alpha }{2}}}\)which implies that the cumulative area to the left of \({z_{\frac{\alpha }{2}}}\) must be\[1 - \frac{\alpha }{2}\].

Here, for 98% confidence level,

\(\begin{array}{c}\alpha = 0.02\\1 - \frac{\alpha }{2} = 0.99\end{array}\)

To find the z score corresponding to the area 0.9900,

In the standard normal table for positive z score, find the value closest to 0.9900, which is 0.9901, corresponding row value is 2.3 and column values is 0.03which corresponds to the z-score of 2.33.

Therefore, the critical value for 98% level of significance is 2.33.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Confidence Intervals. In Exercises 9–24, construct the confidence interval estimate of the mean.

In a study of speed dating conducted at Columbia University, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive; 10 = extremely attractive). Use a 99% confidence level. What do the results tell us about the mean attractiveness ratings made by the population of all adult females?

7 8 2 10 6 5 7 8 8 9 5 9

Confidence Intervals. In Exercises 9–24, construct the confidence interval estimate of the mean.

Birth Weights of Girls Use these summary statistics given in Exercise 8:n=205,x¯=30.4hg,s=7.1hg. Use a 95% confidence level. Are the results very different from those found in Example 2 with only 15 sample values?

Question:In Exercises 5–8, use the given information to find the number of degrees of freedom, the critical values X2 L and X2R, and the confidence interval estimate of σ. The samples are from Appendix B and it is reasonable to assume that a simple random sample has been selected from a population with a normal distribution.

Heights of Men 99% confidence;n= 153,s= 7.10 cm.

Celebrities and the Law Here is a 95% confidence interval estimate of the proportion of adults who say that the law goes easy on celebrities: 0.692 <p< 0.748 (based on data from a Rasmussen Reports survey). What is the best point estimate of the proportion of adults in the population who say that the law goes easy on celebrities?

Critical Thinking. In Exercises 17–28, use the data and confidence level to construct a

confidence interval estimate of p, then address the given question. Mendelian GeneticsOne of Mendel’s famous genetics experiments yielded 580 peas, with 428 of them green and 152 yellow.

a.Find a 99% confidence interval estimate of the percentageof green peas.

b.Based on his theory of genetics, Mendel expected that 75% of the offspring peas would be green. Given that the percentage of offspring green peas is not 75%, do the results contradict Mendel’s theory? Why or why not?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free