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Sample Size. In Exercises 29–36, find the sample size required to estimate the population mean.

Mean IQ of Attorneys See the preceding exercise, in which we can assume that for the IQ scores. Attorneys are a group with IQ scores that vary less than the IQ scores of the general population. Find the sample size needed to estimate the mean IQ of attorneys, given that we want 98% confidence that the sample mean is within 3 IQ points of the population mean. Does the sample size appear to be practical?

Short Answer

Expert verified

The required sample size is 136. It does appear to be practical.

Step by step solution

01

Given information

The IQ test ofAttorneys has a standard deviation of σ=15. The level of confidence is 98%, and the sample mean lies within 3 IQ points of the true mean.

02

Describe the determination of sample size

The sample size n can be determined by using the following formula.

n=zα2×σE2...1

Here, E is the margin of error.

03

Find the critical value zα2

The zα2is a z-score that separates an area of α2in the right tail of the standard normal distribution.

The confidence level of 98% corresponds to α=0.02andα2=0.01.

The valuezα2has the cumulative area to its left as 1-α2.

Mathematically,

Pz<zα2=1-α2=0.99

From the standard normal table, the area of 0.99 is observed corresponding intersection of the row value 2.3 and column value 0.03, which implies zα2is 2.33.

04

Find the required sample size

The sample size is calculated by substituting the values of zα2,σ, and E in equation (1).

n=zα2×σE2=2.33×1532=135.722=136roundedup

Thus, with 136 samples values, you can be 98% confident that your sample mean lies within 3 IQ points of the true mean.

05

Conclude that the sample size appears to be practical

The sample size required to estimate the meanIQ test ofAttorneys is 136. Yes, the sample size does appear to be very practical.

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Most popular questions from this chapter

In Exercises 5–8, use the relatively small number of given bootstrap samples to construct the confidence interval. Freshman 15: Here is a sample of amounts of weight change (kg) of college students in their freshman year (from Data Set 6 “Freshman 15” in Appendix B): 11, 3, 0, -2, where -2 represents a loss of 2 kg and positive values represent weight gained. Here are ten bootstrap samples: {11, 11, 11, 0}, {11, -2, 0, 11}, {11, -2, 3, 0}, {3, -2, 0, 11}, {0, 0, 0, 3}, {3, -2, 3, -2}, {11, 3, -2, 0}, { -2, 3, -2, 3}, { -2, 0, -2, 3}, {3, 11, 11, 11}. a. Using only the ten given bootstrap samples, construct an 80% confidence interval estimate of the mean weight change for the population. b. Using only the ten given bootstrap samples, construct an 80% confidence interval estimate of the standard deviation of the weight changes for the population.

In Exercises 1–3, refer to the accompanying screen display that results from the Verizon airport data speeds (Mbps) from Data Set 32 “Airport Data Speeds” in Appendix B. The confidence level of 95% was used.

Degrees of Freedom

a. What is the number of degrees of freedom that should be used for finding the critical value tα2?

b. Find the critical value tα2corresponding to a 95% confidence level.

c. Give a brief general description of the number of degrees of freedom.

Constructing and Interpreting Confidence Intervals. In Exercises 13–16, use the given sample data and confidence level. In each case, (a) find the best point estimate of the population proportion p; (b) identify the value of the margin of error E; (c) construct the confidence interval; (d) write a statement that correctly interprets the confidence interval.

Survey Return Rate In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 5000 subjects randomly selected from an online group involved with ears. 717 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys.

Confidence Intervals. In Exercises 9–24, construct the confidence interval estimate of the mean. In Exercises 2-19,Mercury in SushiAn FDA guideline is that themercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in New York City. The study was sponsored by the New York Times, and the stores (in order) are D’Agostino, Eli’s Manhattan, Fairway, Food Emporium, Gourmet Garage, Grace’s Marketplace, and Whole Foods. Construct a 98% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi?

0.56 0.75 0.10 0.95 1.25 0.54 0.88

Constructing and Interpreting Confidence Intervals. In Exercises 13–16, use the given sample data and confidence level. In each case, (a) find the best point estimate of the population proportion p; (b) identify the value of the margin of error E; (c) construct the confidence interval; (d) write a statement that correctly interprets the confidence interval.

Medical Malpractice In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed (based on data from the Physicians Insurers Association of America). Construct a 95% confidence interval for the proportion of medical malpractice lawsuits that are dropped or dismissed.

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