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Formats of Confidence Intervals. In Exercises 9–12, express the confidence interval using the indicated format. (The confidence intervals are based on the proportions of red, orange, yellow, and blue M&Ms in Data Set 27 “M&M Weights” in Appendix B.)

Yellow M&Ms Express the confidence interval (0.0169, 0.143) in the form ofp^-E<p<p^+E

Short Answer

Expert verified

The confidence interval is expressed as0.0169<p<0.143.

Step by step solution

01

Given information

The confidence interval for the proportion of yellow M&Ms has an upper confidence limit equal to 0.143 and a lower confidence limit equal to 0.0169.

02

Expression of the confidence interval

The confidence interval for the population proportion can be expressed as follows:

p^-E<p<p^+E

The lower limit of the confidence interval is equivalent to p^-Ewhile the upper limit of the confidence interval is equivalent to p^+E.

Therefore, the lower limit of the given confidence interval (0.0169) is equivalent to p^-Eand the upper limit (0.143) is equivalent to p^+E.

The expression of the confidence interval of the proportion of yellow M&Ms is equal to0.0169<p<0.143.

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Most popular questions from this chapter

Sample Size. In Exercises 29–36, find the sample size required to estimate the population mean.

Mean Age of Female Statistics Students Data Set 1 “Body Data” in Appendix B includes ages of 147 randomly selected adult females, and those ages have a standard deviation of 17.7 years. Assume that ages of female statistics students have less variation than ages of females in the general population, so let years for the sample size calculation. How many female statistics student ages must be obtained in order to estimate the mean age of all female statistics students? Assume that we want 95% confidence that the sample mean is within one-half year of the population mean. Does it seem reasonable to assume that ages of female statistics students have less variation than ages of females in the general population?

Sample Size. In Exercises 29–36, find the sample size required to estimate the population mean.

Mean Weight of Male Statistics Students Data Set 1 “Body Data” in Appendix B includes weights of 153 randomly selected adult males, and those weights have a standard deviation of 17.65 kg. Because it is reasonable to assume that weights of male statistics students have less variation than weights of the population of adult males, let σ=17.65kg. How many male statistics students must be weighed in order to estimate the mean weight of all male statistics students? Assume that we want 90% confidence that the sample mean is within 1.5 kg of the population mean. Does it seem reasonable to assume that weights of male statistics students have less variation than weights of the population of adult males?

Coping with No Success: According to the Rule of Three, when we have a sample size n with x = 0 successes, we have 95% confidence that the true population proportion has an upper bound of 3/n. (See “A Look at the Rule of Three,” by Jovanovic and Levy, American Statistician, Vol. 51, No. 2.)a. If n independent trials result in no successes, why can’t we find confidence interval limits by using the methods described in this section? b. If 40 couples use a method of gender selection and each couple has a baby girl, what is the 95% upper bound for p, the proportion of all babies who are boys?

In Exercises 9–16, assume that each sample is a simple

random sample obtained from a population with a normal distribution.

Comparing Waiting Lines

a. The values listed below are waiting times (in minutes) of customers at the Jefferson Valley Bank, where customers enter a single waiting line that feeds three teller windows. Construct a95% confidence interval for the population standard deviation .

6.5 6.6 6.7 6.8 7.1 7.3 7.4 7.7 7.7 7.7

b. The values listed below are waiting times (in minutes) of customers at the Bank of Providence, where customers may enter any one of three different lines that have formed at three teller windows. Construct a 95% confidence interval for the population standard deviation .

4.2 5.4 5.8 6.2 6.7 7.7 7.7 8.5 9.3 10.0

c. Interpret the results found in parts (a) and (b). Do the confidence intervals suggest a difference in the variation among waiting times? Which arrangement seems better: the single-line system or the multiple-line system?

Interpreting CIWrite a brief statement that correctly interprets the confidence interval given in Exercise 1 “Celebrities and the Law.”

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