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Formats of Confidence Intervals.

In Exercises 9–12, express the confidence interval using the indicated format. (The confidence intervals are based on the proportions of red, orange, yellow, and blue M&Ms in Data Set 27 “M&M Weights” in Appendix B.)

Orange M&Ms Express 0.179 < p < 0.321 in the form of p^±E.

Short Answer

Expert verified

The confidence interval of the format p^±Eis0.25±0.071.

Step by step solution

01

Given information

The confidence interval for p is0.179<p<0.321

02

Find the value of sample proportion

Formula for sample proportion is:

p^=upper confidence limit+lower confidence limit2

From the given confidence interval, thelower confidence limit is 0.179 and upper confidence limit is 0.321.

Substituting values,

p^=0.321+0.1792=0.25

Hence, the sample proportion is 0.25.

03

Find the value of margin of error

Formula for margin of error is:

E=upper confidence limit-lower confidence limit2=0.321-0.1792=0.071

Hence, the margin of error is 0.071.

04

Construct the confidence interval in the form of p^ ± E

The confidence interval in the form of p^±Eis given as:

p^-E<p<p^+E0.25-0.071<p<0.25+0.0710.179<p<0.321

Therefore, the confidence interval in the format p^±Eis 0.25±0.071.

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Most popular questions from this chapter

Finding Critical Values In constructing confidence intervals for σor σ2, Table A-4 can be used to find the critical values χL2and χR2only for select values of n up to 101, so the number of degrees of freedom is 100 or smaller. For larger numbers of degrees of freedom, we can approximate χL2andχR2 by using,

χ2=12±zα2+2k-12

where k is the number of degrees of freedom and zα2is the critical z score described in Section 7-1. Use this approximation to find the critical values χL2and χR2for Exercise 8 “Heights of Men,” where the sample size is 153 and the confidence level is 99%. How do the results compare to the actual critical values of χL2= 110.846 and χR2= 200.657?

Formats of Confidence Intervals. In Exercises 9–12, express the confidence interval using the indicated format. (The confidence intervals are based on the proportions of red, orange, yellow, and blue M&Ms in Data Set 27 “M&M Weights” in Appendix B.)

Blue M&Ms Express the confidence interval 0.270±0.073 in the form ofp^-E<p<p^+E

Critical Thinking. In Exercises 17–28, use the data and confidence level to construct a

confidence interval estimate of p, then address the given question. Fast Food AccuracyIn a study of the accuracy of fast food drive-through orders, Burger King had 264 accurate orders and 54 that were not accurate (based on data from QSRmagazine).

a.Construct a 99% confidence interval estimate of the percentageof orders that are not accurate.

b.Compare the result from part (a) to this 99% confidence interval for the percentage of orders that are not accurate at Wendy’s: 6.2%<p< 15.9%. What do you conclude?

Garlic for Reducing Cholesterol In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) had a mean of 0.4 and a standard deviation of 21.0 (based on data from “Effect of Raw Garlic vs Commercial Garlic Supplements on Plasma Lipid Concentrations in Adults with Moderate Hypercholesterolemia,” by Gardner et al., Archives of Internal Medicine, Vol. 167). Construct a 98% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?

Finite Population Correction Factor For Formulas 7-2 and 7-3 we assume that the population is infinite or very large and that we are sampling with replacement. When we sample without replacement from a relatively small population with size N, we modify E to include the finite population correction factor shown here, and we can solve for n to obtain the result given here. Use this result to repeat part (b) of Exercise 38, assuming that we limit our population to a county with 2500 women who have completed the time during which they can give birth.

E=zα2p^q^nN-nN-1

n=Np^q^zα22p^q^zα22+N-1E2

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