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In Exercises 29–32, find the mean of the data summarized in the frequency distribution. Also, compare the computed means to the actual means obtained by using the original list of data values, which are as follows: (Exercise 29) 36.2 years; (Exercise 30) 44.1 years; (Exercise 31) 224.3; (Exercise 32) 255.1..

Age (year) of Best Actress when Oscar was won

Frequency

20–29

29

30–39

34

40–49

14

50–59

3

60–69

5

70–79

1

80–89

1

Short Answer

Expert verified

The mean value is computed as 36.2 years, which is equal to the actual value.

Step by step solution

01

Given information

The frequency distribution is given as follows:

Age (year) of Best Actress

when Oscar was won

Frequency

20–29

29

30–39

34

40–49

14

50–59

3

60–69

5

70–79

1

80–89

1

The actual measure of mean is 36.2 years.

02

Determine the midpoints of each class

The mean for the frequency distribution is obtained using the formula

x¯=f×xf, where fdenotes the frequencies and xrepresents the midpoints of the classes.

The midpoints x are computed for a class interval as follows:

x=Upperlimit+Lowerlimit2

Therefore, the values are tabulated as follows:

Age (in years) of Best Actress

when Oscar was Won

Frequency

(f)

Lower limit

Upper limit

Midpoint

(x)

20–29

29

20

29

24.5

30–39

34

30

39

34.5

40–49

14

40

49

44.5

50–59

3

50

59

54.5

60–69

5

60

69

64.5

70–79

1

70

79

74.5

80–89

1

80

89

84.5

03

The mean for the values is computed using the formula

The computation for the sum totals is done as follows:

Age (in years) of Best Actress

when Oscar was Won

Frequency

(f)

Midpoint

(x)

f×x

20–29

29

24.5

710.5

30–39

34

34.5

1173

40–49

14

44.5

623

50–59

3

54.5

163.5

60–69

5

64.5

322.5

70–79

1

74.5

74.5

80–89

1

84.5

84.5

Totals:

f=87

f×x=3151.5

Substituting the values in the formula, you get:

x¯=3151.587=36.2241

Thus, the mean age of the best actress when Oscar was won is 36.2 years.

04

Compare the mean value with the actual mean value

The actual mean value is the same as the one computed from the frequency distribution; that is, 36.2 years.

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Most popular questions from this chapter

In Exercises 37–40, refer to the frequency distribution in the given exercise and find the standard deviation by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviations to these standard deviations obtained by using Formula 3-4 with the original list of data values: (Exercise 37) 11.5 years; (Exercise 38) 8.9 years; (Exercise 39) 59.5; (Exercise 40) 65.4.

Standard deviation for frequency distribution

s=nf.x2-f.x2nn-1

Age (yr) of Best Actress When Oscar Was Won

Frequency

20-29

29

30-39

34

40-49

14

50-59

3

60-69

5

70-79

1

80-89

1

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In Exercises 37–40, refer to the frequency distribution in the given exercise and find the standard deviation by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviations to these standard deviations obtained by using Formula 3-4 with the original list of data values: (Exercise 37) 11.5 years; (Exercise 38) 8.9 years; (Exercise 39) 59.5; (Exercise 40) 65.4.

Standard deviation for frequency distribution

s=nf×x2-f×x2nn-1

Blood Platelet Count of Females

Frequency

100-199

25

200-299

92

300-399

28

400-499

0

500-599

2

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1800 1500 1200 1500 1400 1600 1500 950 1600 1150 1500 1750

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