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z Scores LeBron James, one of the most successful basketball players of all time, has a height of 6 feet 8 inches, or 203 cm. Based on statistics from Data Set 1 “Body Data” in Appendix B, his height converts to the z score of 4.07. How many standard deviations is his height above the mean?

Short Answer

Expert verified

The given height equal to 203 cm is 4.07 standard deviations above the mean height.

Step by step solution

01

Given information

The given data shows the heights of a population of 300 males and females measured in cm.

02

Z-score

Thez-scoreprovides an idea of how many standard deviations a data value is above or below the mean value. For a given sample, it has the following expression:

Z=x-x¯s

Here,

x is any data value.

x¯ is the sample mean.

s is the sample standard deviation.

For example, a sample consists of time durations taken by a group of employees to complete a given task. The average time is equal to 14 minutes, and the standard deviation is equal to 5.4 minutes.

The z-score of a time duration equal to 7 minutes is equal to -1.29. Thus, it can be said that the time duration equal to 7 minutes is 1.29 standard deviations below the mean value.

03

Interpretation of z-score

The z-score value for a given value of height equal to 203 cm is obtained as 4.07.

This implies that the value of the height is4.07 standard deviations above the mean.

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Most popular questions from this chapter

In Exercises 13–16, use z scores to compare the given values.

Oscars In the 87th Academy Awards, Eddie Redmayne won for best actor at the age of 33 and Julianne Moore won for best actress at the age of 54. For all best actors, the mean age is 44.1 years and the standard deviation is 8.9 years. For all best actresses, the mean age is 36.2 years and the standard deviation is 11.5 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the Oscar: Eddie Redmayne or Julianne Moore? Explain.

In Exercises 5–20, find the range, variance, and standard deviation for the given sample data. Include appropriate units (such as “minutes”) in your results. (The same data were used in Section 3-1, where we found measures of center. Herewe find measures of variation.) Then answer the given questions.

Cell Phone Radiation Listed below are the measured radiation absorption rates (in W/kg) corresponding to these cell phones: iPhone 5S, BlackBerry Z30, Sanyo Vero, Optimus V, Droid Razr, Nokia N97, Samsung Vibrant, Sony Z750a, Kyocera Kona, LG G2, and Virgin Mobile Supreme. The data are from the Federal Communications Commission. If one of each model of cell phone is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use?

1.18 1.41 1.49 1.04 1.45 0.74 0.89 1.42 1.45 0.51 1.38

In Exercises 5–8, express all z scores with two decimal places.

ATL Data Speeds For the Verizon airport data speeds (Mbps) listed in Data Set 32 “Airport Data Speeds” in Appendix B, the highest speed of 77.8 Mbps was measured at Atlanta’s (ATL) international airport. The complete list of 50 Verizon data speeds has a mean of x = 17.60 Mbps and a standard deviation of s = 16.02 Mbps

a. What is the difference between Verizon’s data speed at Atlanta’s international airport and the mean of all of Verizon’s data speeds?

b. How many standard deviations is that [the difference found in part (a)]?

c. Convert Verizon’s data speed at Atlanta’s international airport to a z score.

d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is Verizon’s speed at Atlanta significant?

Variance The 20 subjects used in Data Set 8 “IQ and Brain Size” in Appendix B have weights with a standard deviation of 20.0414 kg. What is the variance of their weights? Be sure to include the appropriate units with the result.

In Exercises 29–32, find the mean of the data summarized in the frequency distribution. Also, compare the computed means to the actual means obtained by using the original list of data values, which are as follows: (Exercise 29) 36.2 years; (Exercise 30) 44.1 years; (Exercise 31) 224.3; (Exercise 32) 255.1..

Age (year) of Best Actor when Oscar was won

Frequency

20–29

1

30–39

28

40–49

36

50–59

15

60–69

6

70–79

1

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