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Stocks and Sunspots. Listed below are annual high values of the Dow Jones Industrial Average (DJIA) and annual mean sunspot numbers for eight recent years. Use the data for Exercises 1–5. A sunspot number is a measure of sunspots or groups of sunspots on the surface of the sun. The DJIA is a commonly used index that is a weighted mean calculated from different stock values.

DJIA

14,198

13,338

10,606

11,625

12,929

13,589

16,577

18,054

Sunspot

Number

7.5

2.9

3.1

16.5

55.7

57.6

64.7

79.3

Correlation Use a 0.05 significance level to test for a linear correlation between the DJIA values and the sunspot numbers. Is the result as you expected? Should anyone consider investing in stocks based on sunspot numbers?

Short Answer

Expert verified

The value of r is 0.731.

Since the test statistic value is greater than the critical value, the null hypothesis is rejected. There is a significant linear correlation between the sunspot numbers and the stock indices.

The results are not what was expected.

Furthermore, no one should examine the sunspot count before investing because the correlation between them is meaningless.

Step by step solution

01

Given information

Data are given on two variables, “DJIA” and “Sunspot Number”.

02

Hypotheses

The null hypothesis is as follows:

There is no linear correlation between the variables “DJIA” and “Sunspot Number”.

The alternative hypothesis is as follows:

There is a linear correlation between the variables “DJIA” and “Sunspot Number”.

03

Correlation coefficient

Let x denote the DJIA.

Let y denote the sunspot numbers.

The formula for computing the correlation coefficient (r) between the values of DJIA and sunspot numbers is as follows:

\(r = \frac{{n\sum {xy} - \sum x \sum y }}{{\sqrt {n\sum {{x^2}} - {{\left( {\sum x } \right)}^2}} \sqrt {n\sum {{y^2}} - {{\left( {\sum y } \right)}^2}} }}\)

The following calculations are done to compute the value of r:

x

y

xy

\({x^2}\)

\({y^2}\)

14198

7.5

106485

201583204

56.25

13338

2.9

38680.2

177902244

8.41

10606

3.1

32878.6

112487236

9.61

11625

16.5

191812.5

135140625

272.25

12929

55.7

720145.3

167159041

3102.49

13589

57.6

782726.4

184660921

3317.76

16577

64.7

1072532

274796929

4186.09

18054

79.3

1431682

325946916

6288.49

\(\sum x \)=110916

\(\sum y \)=287.3

\(\sum {xy} \)=4376942

\(\sum {{x^2}} \)=1579677116

\(\sum {{y^2}} \)=17241.35

Substitute the above values to find r:

\(\begin{aligned} r &= \frac{{n\sum {xy} - \sum x \sum y }}{{\sqrt {n\sum {{x^2}} - {{\left( {\sum x } \right)}^2}} \sqrt {n\sum {{y^2}} - {{\left( {\sum y } \right)}^2}} }}\\ &= \frac{{8\left( {4376942} \right) - \left( {110916} \right)\left( {287.3} \right)}}{{\sqrt {8\left( {1579677116} \right) - {{\left( {110916} \right)}^2}} \sqrt {8\left( {17241.35} \right) - {{\left( {287.3} \right)}^2}} }}\\ &= 0.731\end{aligned}\)

Therefore, the value of r is 0.731.

04

Test statistic

The test statistic is computed as follows:

\(\begin{aligned} t &= \frac{r}{{\sqrt {\frac{{1 - {r^2}}}{{n - 2}}} }}\;\;\; \sim {t_{\left( {n - 2} \right)}}\\ &= \frac{{0.731}}{{\sqrt {\frac{{1 - {{0.731}^2}}}{{8 - 2}}} }}\\ &= 2.624\end{aligned}\)

Here, n=8.

The degrees of freedom of t are computed as follows:

\(\begin{aligned} df &= n - 2\\ &= 8 - 2\\ &= 6\end{aligned}\)

Using the t-table, the critical value of t for \(\alpha = 0.05\)and df = 6 is 2.4469.

The corresponding p-value is obtained as shown:

\(\begin{aligned} p{\rm{ - value}} &= 2P\left( {T > t} \right)\\ &= 2P\left( {T > 2.624} \right)\\ &= 0.039\end{aligned}\)

Since the test statistic value is greater than the critical value and the p-value is less than 0.05, the null hypothesis is rejected.

Therefore, the linear correlation between the sunspot numbers and DJIA is significant.

05

Discrepancy from reality

In reality, there is no correlation between stock indices and sunspot numbers.

But, according to the obtained value of r, the correlation comes out to be significant.

Thus, the results differ from what was expected.

Moreover, nobody should consider the sunspot numbers before investing as, in the real sense, the correlation between them does not hold any meaning.

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Most popular questions from this chapter

Testing for a Linear Correlation. In Exercises 13–28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Revised mpg Ratings Listed below are combined city-highway fuel economy ratings (in mi>gal) for different cars. The old ratings are based on tests used before 2008 and the new ratings are based on tests that went into effect in 2008. Is there sufficient evidence to conclude that there is a linear correlation between the old ratings and the new ratings? What do the data suggest about the old ratings?

Old

16

27

17

33

28

24

18

22

20

29

21

New

15

24

15

29

25

22

16

20

18

26

19

Testing for a Linear Correlation. In Exercises 13–28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

CSI Statistics Use the paired foot length and height data from the preceding exercise. Is there sufficient evidence to conclude that there is a linear correlation between foot lengths and heights of males? Based on these results, does it appear that police can use foot length to estimate the height of a male?

Shoe print(cm)

29.7

29.7

31.4

31.8

27.6

Foot length(cm)

25.7

25.4

27.9

26.7

25.1

Height (cm)

175.3

177.8

185.4

175.3

172.7

Confidence Intervals for a Regression Coefficients A confidence interval for the regression coefficient b1 is expressed

\(\begin{array}{l}{b_1} - E < {\beta _1} < {b_1} + E\\\end{array}\)

Where

\(E = {t_{\frac{\alpha }{2}}}{s_{{b_1}}}\)

The critical t score is found using n –(k+1) degrees of freedom, where k, n, and sb1 are described in Exercise 17. Using the sample data from Example 1, n = 153 and k = 2, so df = 150 and the critical t scores are \( \pm \)1.976 for a 95% confidence level. Use the sample data for Example 1, the Stat diskdisplay in Example 1 on page 513, and the Stat Crunchdisplay in Exercise 17 to construct 95% confidence interval estimates of \({\beta _1}\) (the coefficient for the variable representing height) and\({\beta _2}\) (the coefficient for the variable representing waist circumference). Does either confidence interval include 0, suggesting that the variable be eliminated from the regression equation?

Testing for a Linear Correlation. In Exercises 13–28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Tips Listed below are amounts of bills for dinner and the amounts of the tips that were left. The data were collected by students of the author. Is there sufficient evidence to conclude that there is a linear correlation between the bill amounts and the tip amounts? If everyone were to tip with the same percentage, what should be the value of r?

Bill(dollars)

33.46

50.68

87.92

98.84

63.6

107.34

Tip(dollars)

5.5

5

8.08

17

12

16

In exercise 10-1 12. Clusters Refer to the following Minitab-generated scatterplot. The four points in the lower left corner are measurements from women, and the four points in the upper right corner are from men.

a. Examine the pattern of the four points in the lower left corner (from women) only, and subjectively determine whether there appears to be a correlation between x and y for women.

b. Examine the pattern of the four points in the upper right corner (from men) only, and subjectively determine whether there appears to be a correlation between x and y for men.

c. Find the linear correlation coefficient using only the four points in the lower left corner (for women). Will the four points in the upper left corner (for men) have the same linear correlation coefficient?

d. Find the value of the linear correlation coefficient using all eight points. What does that value suggest about the relationship between x and y?

e. Based on the preceding results, what do you conclude? Should the data from women and the data from men be considered together, or do they appear to represent two different and distinct populations that should be analyzed separately?

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