Chapter 8: Problem 26
Let \(0=t_{0}
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 8: Problem 26
Let \(0=t_{0}
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeUse the Laplace transform to solve the initial value problem. \(y^{\prime \prime}+2 y^{\prime}+y=6 \sin t-4 \cos t, \quad y(0)=-1, y^{\prime}(0)=1\)
Show that if \(p(s)=a s^{2}+b s+c\) has complex conjugate zeros \(\lambda \pm i \omega\) then the solution of $$ a y^{\prime \prime}+b y^{\prime}+c y=f(t), \quad y(0)=k_{0}, \quad y^{\prime}(0)=k_{1} $$ is $$ \begin{aligned} y(t)=& e^{\lambda t}\left[k_{0}\left(\cos \omega t-\frac{\lambda}{\omega} \sin \omega t\right)+\frac{k_{1}}{\omega} \sin \omega t\right] \\ &+\frac{1}{a \omega} \int_{0}^{t} e^{\lambda t} f(t-\tau) \sin \omega \tau d \tau \end{aligned} $$
In Exercises \(1-20\) use the Laplace transform to solve the initial value problem. Where indicated by \(\mathrm{C} / \mathrm{G}\), graph the solution. $$ y^{\prime \prime}+9 y=\left\\{\begin{array}{ll} \cos t, & 0 \leq t<\frac{3 \pi}{2}, \\ \sin t, \quad t \geq \frac{3 \pi}{2} \end{array} \quad y(0)=0, y^{\prime}(0)=0\right. $$
Use the Laplace transform to solve the initial value problem. \(y^{\prime \prime}+3 y^{\prime}+2 y=2 e^{t}, \quad y(0)=0, \quad y^{\prime}(0)=-1\)
In Exercises \(1-20\) solve the initial value problem. Where indicated by \(\mathrm{C} / \mathrm{G}\), graph the solution. $$ y^{\prime \prime}+3 y^{\prime}+2 y=6 e^{2 t}+2 \delta(t-1), \quad y(0)=2, \quad y^{\prime}(0)=-6 $$
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