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Use Euler's method and the Euler semilinear method with step sizes h=0.1,h=0.05, and h=0.025 to find approximate values of the solution of the initial value problem y+3y=7e3x,y(0)=6 at x=0,0.1,0.2,0.3,,1.0. Compare these approximate values with the values of the exact solution y=e3x(7x+6), which can be obtained by the method of Section 2.1. Do you notice anything special about the results? Explain.

Short Answer

Expert verified
Analyze and explain any special observations. Answer: After implementing the Euler's method and Euler semilinear method with various step sizes, we can compare the approximated values with the exact solution to assess their accuracy. In general, we may observe that as the step size decreases, the approximations become more accurate. For both methods, smaller step sizes lead to better approximations of the exact solution. However, the Euler semilinear method may provide relatively better approximations as it accounts for the linearity of the problem. The analysis should also include any specific observations regarding the differences in accuracy between the methods and possible reasons behind such outcome.

Step by step solution

01

Identify the differential equation and initial condition

The problem gives us a first-order linear differential equation and an initial condition: y+3y=7e3x , with y(0)=6.
02

Determine the exact solution

The exact solution is given by the problem: y(x)=e3x(7x+6).
03

Implement Euler's method

We will implement Euler's method for the step sizes h=0.1,0.05,0.025. The equation for Euler's method is: yn+1=yn+hf(xn,yn) In our case, f(x,y)=7e3x3y.
04

Calculate approximate values using different step sizes

For each step size h, we will calculate the values of y(x) at x=0,0.1,0.2,,1 using Euler's method and compare it to the exact solution.
05

Implement Euler semilinear method

We will implement Euler semilinear method for the step sizes h=0.1,0.05,0.025. The equation for the Euler semilinear method is: yn+1=yn+hP(xn)1hQ(xn) In our case, P(x)=7e3x and Q(x)=3.
06

Calculate approximate values using different step sizes

For each step size h, we will calculate the values of y(x) at x=0,0.1,0.2,,1 using Euler semilinear method and compare it to the exact solution.
07

Compare and analyze the results

Compare the approximate values obtained by Euler's method and Euler semilinear method with the exact solution at each x. Analyze and explain any special observations about the results.

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Most popular questions from this chapter

Use the Runge-Kutta method with step sizes h=0.1,h=0.05, and h=0.025 to find approximate values of the solution of the initial value problem y+2xy=3x3+1,y(1)=1 at x=1.0,1.1,1.2,1.3,,2.0. Compare these approximate values with the values of the exact solution y=13x2(9lnx+x3+2) which can be obtained by the method of Section 2.1 . Present your results in a table like Table 3.3 .1 .

Use the Runge-Kutta method and the Runge-Kutta semilinear method with the indicated step sizes to find approximate values of the solution of the given initial value problem at 11 equally spaced points (including the endpoints) in the interval. y+3y=xy2(y+1),y(0)=1;h=0.1,0.05,0.025 on [0,1]

Use the Runge-Kutta method and the Runge-Kutta semilinear method with step sizes h=0.1, h¯=0.05, and h=0.025 to find approximate values of the solution of the initial value problem y+3y=e3x(14x+3x24x3),y(0)=3 at x=0,0.1,0.2,0.3,,1.0. Compare these approximate values with the values of the exact solution y=e3x(3x+2x2x3+x4), which can be obtained by the method of Section 2.1. Do you notice anything special about the results? Explain.

Use the improved Euler method with step sizes h=0.1,h=0.05, and h=0.025 to find approximate values of the solution of the initial value problem y+3y=7e4x,y(0)=2 at x=0,0.1,0.2,0.3,,1.0. Compare these approximate values with the values of the exact solution y=e4x+e3x, which can be obtained by the method of Section 2.1. Present your results in a table like Table 3.2 .2 .

NUMERICAL QUADRATURE (see Exercise 3.1.23). (a) Derive the quadrature formula abf(x)dxh6(f(a)+f(b))+h3i=1n1f(a+ih)+2h3i=1nf(a+(2i1)h/2) (where h=(ba)/n) by applying the Runge-Kutta method to the initial value problem y=f(x),y(a)=0 This quadrature formula is called Simpson's Rule. (b) L For several choices of a,b,A,B,C, and D apply (A) to f(x)=A+Bx+Cx+Dx3, with n=10,20,40,80,160,320. Compare your results with the exact answers and explain what you find. (c) L For several choices of a,b,A,B,C,D, and E apply (A) to f(x)=A+Bx+Cx2+ Dx3+Ex4, with n=10,20,40,80,160,320. Compare your results with the exact answers and explain what you find.

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