Chapter 2: Problem 16
Solve the equation explicitly. $$ y^{\prime}=\frac{y^{2}+2 x y}{x^{2}} $$
Short Answer
Expert verified
In conclusion, the solution to the given differential equation $$y^{\prime}=\frac{y^{2}+2xy}{x^{2}}$$ is $$y(x) = \frac{e^{-\frac{1}{x} + C}}{1 + 2x} \operatorname{sgn}(1 + 2x)$$.
Step by step solution
01
Rearrange the Equation in a Separable Form
First, we need to rearrange the equation by multiplying both sides by \(x^{2}\) and then dividing by \((y^{2} + 2xy)\) to make it separable:
$$
\frac{y'(x)}{y^{2}+2xy} = \frac{1}{x^2}
$$
Now, it's in the form of \(\frac{dy}{y^2 + 2xy} = \frac{dx}{x^2}\), which separates the variables y and x.
02
Integrate Both Sides
Now that the equation is in the separable form, we'll integrate both sides:
$$
\int\frac{dy}{y^2 + 2xy} = \int\frac{dx}{x^2}
$$
For the left-hand side, we perform a substitution; let \(z = y(1 + 2x)\). Then, \(dz=(1+2x)dy+2ydx\). We have:
$$
\int\frac{dy}{y^2 + 2xy} = \int\frac{1+2x}{z}dz
$$
So the equation becomes:
$$
\int\frac{1+2x}{z}dz = \int\frac{dx}{x^2}
$$
03
Perform the Integration
Now we can perform the integration:
$$
\int\frac{1+2x}{z}dz = \ln|z| + C_1
$$
and
$$
\int\frac{dx}{x^2} = -\frac{1}{x} + C_2
$$
Now, we express the first equation in terms of y using our substitution \(z=y(1 + 2x)\):
$$
\ln|y(1+2x)| + C_1 = -\frac{1}{x} + C_2
$$
04
Solve for y(x)
In this final step, we'll rearrange the equation to solve explicitly for y(x). First, let \(C = C_2 - C_1\):
$$
\ln|y(1+2x)| = -\frac{1}{x} + C
$$
Now, take the exponential of both sides:
$$
|y(1+2x)| = e^{-\frac{1}{x} + C}
$$
Finally, isolate y(x):
$$
y(x) = \frac{e^{-\frac{1}{x} + C}}{1 + 2x} \operatorname{sgn}(1 + 2x)
$$
Thus, we have obtained the explicit solution for y(x) that satisfies the given differential equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Separable Equations
Separable equations are a special type of differential equations that can be broken down such that each variable can be separated on either side of the equation. This makes it possible to deal with one variable at a time, which simplifies solving the equation.
In our problem, we utilize separation by rearranging the equation by moving terms around. We arrive at:
In our problem, we utilize separation by rearranging the equation by moving terms around. We arrive at:
- \( \frac{dy}{y^2 + 2xy} = \frac{dx}{x^2} \)
Integration Techniques
Integration techniques come into play immediately after separating variables. In this scenario, after simplifying the differential equation, we proceed by integrating both sides separately.
For the right side, we have the simpler term:
Meanwhile, integrating the left side requires a substitution strategy. By letting \( z = y(1 + 2x) \), we make the integral manageable:
For the right side, we have the simpler term:
- \( \int \frac{dx}{x^2} \)
Meanwhile, integrating the left side requires a substitution strategy. By letting \( z = y(1 + 2x) \), we make the integral manageable:
- \( \int \frac{1+2x}{z}dz \)
Explicit Solutions
An explicit solution refers to directly expressing one variable entirely in terms of the other. After performing integrations for both sides, we need to solve for \( y \) explicitly.
From our integration results, we derive:
From our integration results, we derive:
- \( \ln|y(1+2x)| = -\frac{1}{x} + C \)
- \( |y(1+2x)| = e^{(-\frac{1}{x} + C)} \)
- \( y(x) = \frac{e^{(-\frac{1}{x} + C)}}{1 + 2x} \operatorname{sgn}(1 + 2x) \)
Variable Separation
Variable separation is an essential method for solving differential equations where you rearrange the equation so that one variable is on each side. This carries particular importance when approaching complex equations that might initially appear inseparable.
The main strategy involves manipulating the equation until each side includes only one of the variables along with its differential:
For our example, after appropriately rearranging and simplifying, we get:
The main strategy involves manipulating the equation until each side includes only one of the variables along with its differential:
For our example, after appropriately rearranging and simplifying, we get:
- \( \int \frac{dy}{y^2 + 2xy} = \int \frac{dx}{x^2} \)