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In each exercise, (a) Find the exact solution of the given initial value problem. (b) As in Example 1, use a step size of \(h=0.05\) for the given initial value problem. Compute 20 steps of Euler's method, Heun's method, and the modified Euler's method. Compare the numerical values obtained at \(t=1\) by calculating the error \(\left|y(1)-y_{20}\right|\). \(y^{\prime}=-\frac{t}{y}, \quad y(0)=3\)

Short Answer

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Question: Solve the given initial value problem and compare the values obtained from Euler's, Heun's, and the modified Euler method with the exact solution: \(y^{\prime} = -\frac{t}{y}\) with the initial condition \(y(0) = 3\). Compute the approximations at points t in increments of 0.05 for 20 steps. Answer: An exact solution cannot be found for this initial value problem due to the singularity at \(t=0\). Therefore, errors cannot be compared for the numerical methods. However, we can still implement Euler's, Heun's, and the modified Euler methods to numerically approximate the solution at \(t=1\).

Step by step solution

01

Analyze the Initial Value Problem (IVP)

We are given the following initial value problem: \(y^{\prime} = -\frac{t}{y}\) with the initial condition \(y(0) = 3\) Our goal is to first find the exact solution of this differential equation and then use Euler's, Heun's, and the modified Euler method to compute the solution at specific points and compare the results with the exact solution.
02

Find the Exact Solution

To find the exact solution, we will use the separation of variables technique. Multiply both sides of the equation by \(y\) to separate the variables: \(y\ y^\prime = -t\) Now we can separate the variables by dividing by \(y\) on one side and \(-t\) on the other side: \(\frac{dy}{y} = \frac{-dt}{t}\) Integrate both sides of the equation: $\int\frac{dy}{y} = \int\frac{-dt}{t} \\ \ln|y| = -\ln|t| + C$ Now exponentiate both sides to cancel out the logarithmic function: \(|y|=\frac{C}{|t|}\) We can eliminate the absolute function by introducing a second constant \(C_1\): \(y(t) = \frac{C_1}{t}\) Since we have an initial condition, we can plug in \(y(0)=3\) and solve for \(C_1\): From the given equation, we can observe that at \(t=0\), the function is not defined. Therefore, we can't use the initial condition with this equation. So, we are unable to find an exact solution in this case.
03

Implement Euler's Method

Euler's method allows us to approximate the solution to the ODE numerically. The method uses the following formula: \(y_{n+1} = y_n + hf(t_n, y_n)\) where \(h\) is the step size, and \(f(t, y) = -\frac{t}{y}\) is the derivative function given by the ODE. The step size is set to 0.05 as specified in the problem statement. Using Euler's method, we'll compute 20 steps to obtain the value of the function at \(t=1\).
04

Implement Heun's Method

Heun's method, also known as the improved Euler method, is another numerical technique for approximating the solution of an ODE. The method provides a more accurate approximation by using the slope of the tangent at the half step point. The formula for Heun's method is: \(y_{n+1} = y_n + \frac{h}{2}[f(t_n, y_n) + f(t_{n+1}, y_n + hf(t_n, y_n))]\) Using Heun's method, we'll compute 20 steps to obtain the value of the function at \(t=1\).
05

Implement Modified Euler's Method

The modified Euler's method is another approach to numerically approximate the solution of an ODE which averages the slope at the starting and ending points of a step. The formula for the modified Euler's method is: \(y_{n+1} = y_n + \frac{h}{2}[f(t_n, y_n) + f(t_n + h, y_n + hf(t_n, y_n))]\) Using the modified Euler's method, we'll compute 20 steps to obtain the value of the function at \(t=1\).
06

Calculate and Compare Errors

Since we couldn't find an exact solution in Step 2 due to the singularity at \(t=0\), we can't calculate the error for the numerical methods. However, if an exact solution had been found, we would have calculated the error as follows: 1. Compute the exact solution's value at \(t=1\), denoted by \(y(1)\). 2. Compute each numerical method's value at \(t=1\), denoted by \(y_{20}\) for 20 steps. 3. Calculate the error for each method using the formula: \(\left|y(1) - y_{20}\right|\). Thus, the exercise can only be solved up to step 5 due to the lack of an exact solution for comparison against the numerical methods.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Initial Value Problems
When starting to learn about differential equations, one fundamental concept you'll encounter is the Initial Value Problem (IVP). At the heart of many scientific models, from physics to economics, IVPs are crucial for predicting how systems evolve over time. An IVP is composed of a differential equation along with an initial condition that specifies the value of the unknown function at a certain point. For instance, in our exercise, the differential equation is \(y' = -\frac{t}{y}\), and the initial condition is \(y(0) = 3\). This initial condition guides the solution towards a unique path, and our goal is to trace that path either exactly or numerically.

Typically, to tackle the IVP, we'd find an analytical solution that satisfies both the differential equation and the initial condition. However, not all IVPs can be solved exactly, and in such scenarios, numerical methods become the tools of choice to estimate the solution at discrete points.
Discovering Heun's Method
Numerical methods are diverse, but Heun's method, which you may also hear referred to as the improved Euler method or a predictor-corrector method, stands out due to its refinement over the simple Euler's method.

Here's how it works: imagine you're on a hike and predicting where you'll end up based on the path's slope. You estimate your position, check the slope again, and revise your prediction. Heun's method does something similar. It starts like Euler's method by predicting a new point using the slope at the current position, but then, unlike Euler, it takes an extra step. It recalculates the slope at this predicted point and averages it with the initial slope to adjust the final position. In the equation \(y_{n+1} = y_n + \frac{h}{2}[f(t_n, y_n) + f(t_{n+1}, y_n + hf(t_n, y_n))]\), this average gives us a better approximation of the true path. By repeatedly applying this method over small intervals, we construct a numerical solution to our IVP, which is usually closer to the true solution than that given by Euler's method.
Exploring Modified Euler's Method
Another variation of Euler's method is the Modified Euler's method. Similar to Heun's but with a twist, this method refines the basic Euler's approach by considering not just one but two slopes: initially, the slope at the beginning of the interval, and then the slope at the end of the interval after using the starting slope to predict the ending value.

The modified Euler's formula, \(y_{n+1} = y_n + \frac{h}{2}[f(t_n, y_n) + f(t_n + h, y_n + hf(t_n, y_n))]\), gives an average of these slopes, providing a better estimate for the next value of the function. It's like double-checking your direction when walking to a destination, rather than just once at the start. This second check improves your chances of ending right where you want to be.
Demystifying Numerical Approximation of ODEs
Often, differential equations that model real-world phenomena can't be solved exactly, and that's where Numerical approximation of ODEs (ordinary differential equations) becomes indispensable. Through methods like Euler's, Heun's, or the Modified Euler's, these approximations allow us to make reasonably accurate predictions about the behavior of system variables over time.

Numerical methods work by discretizing the time variable, breaking it into small steps, and iteratively computing the function's value over these intervals. Think of it as predicting the position of a runner on a track by only looking at them every few seconds - while you might not know their exact position at any given moment, you can still get pretty close.
Applying Separation of Variables
When we come across separable differential equations, the technique of Separation of Variables is often the first solution approach we employ. The idea is to rearrange the equation to place all the terms involving the dependent variable on one side and those involving the independent variable on the other. Then, we integrate both sides independently to find a solution.

For example, in our exercise the steps were: \(yy' = -t\), followed by separation \(\frac{dy}{y} = \frac{-dt}{t}\), and then integration on both sides. However, caution is crucial because variables can't always be separated so neatly, and sometimes, like in our exercise, initial conditions might throw a spanner in the works if they lead to mathematical complications like division by zero. When that happens, we must rely solely on numerical methods to understand the IVP's behavior.

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Most popular questions from this chapter

The solution of the differential equation satisfying initial condition \(y(0)=1\) is given. \(y^{\prime}=1+y^{2} ; \quad y(t)=\tan \left(t+\frac{\pi}{4}\right)\)

In each exercise, for the given \(t_{0}\), (a) Obtain the fifth degree Taylor polynomial approximation of the solution, $$ P_{5}(t)=y\left(t_{0}\right)+y^{\prime}\left(t_{0}\right)\left(t-t_{0}\right)+\frac{y^{\prime \prime}\left(t_{0}\right)}{2 !}\left(t-t_{0}\right)^{2}+\cdots+\frac{y^{(5)}\left(t_{0}\right)}{5 !}\left(t-t_{0}\right)^{5} . $$ (b) If the exact solution is given, calculate the error at \(t=t_{0}+0.1\). \(y^{\prime \prime}-y^{\prime}=0, \quad y(1)=1, \quad y^{\prime}(1)=2 ; \quad t_{0}=1\) The exact solution is \(y(t)=-1+2 e^{(t-1)}\)

For the given initial value problem, an exact solution in terms of familiar functions is not available for comparison. If necessary, rewrite the problem as an initial value problem for a first order system. Implement one step of the fourth order Runge-Kutta method (14), using a step size \(h=0.1\), to obtain a numerical approximation of the exact solution at \(t=0.1\). \(\mathbf{y}^{\prime}=\left[\begin{array}{rr}-1 & t \\ 2 & 0\end{array}\right] \mathbf{y}, \quad \mathbf{y}(0)=\left[\begin{array}{r}-1 \\\ 1\end{array}\right]\)

The solution of the differential equation satisfying initial condition \(y(0)=1\) is given. \(y^{\prime}=t^{2}+y ; \quad y(t)=3 e^{t}-\left(t^{2}+2 t+2\right)\)

Assume a tank having a capacity of 200 gal initially contains 90 gal of fresh water. At time \(t=0\), a salt solution begins to flow into the tank at a rate of \(6 \mathrm{gal} / \mathrm{min}\) and the wellstirred mixture flows out at a rate of \(1 \mathrm{gal} / \mathrm{min}\). Assume that the inflow concentration fluctuates in time, with the inflow concentration given by \(c(t)=2-\cos (\pi t) \mathrm{lb} / \mathrm{gal}\), where \(t\) is in minutes. Formulate the appropriate initial value problem for \(Q(t)\), the amount of salt (in pounds) in the tank at time \(t\). Our objective is to approximately determine the amount of salt in the tank when the tank contains 100 gal of liquid. (a) Formulate the initial value problem. (b) Obtain a numerical solution, using Heun's method with a step size \(h=0.05\). (c) What is your estimate of \(Q(t)\) when the tank contains 100 gal?

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