Chapter 7: Problem 29
$$ \theta^{\prime \prime}+\sin \theta=0, \quad \theta(0)=0, \quad \theta^{\prime}(0)=2 ; \quad 0 \leq t \leq 20 . $$ This problem models pendulum motion when the pendulum is initially in the vertically downward position with an initial angular velocity of \(2 \mathrm{rad} / \mathrm{s}\). For this conservative system, it was shown in Chapter 6 that \(\left(\theta^{\prime}\right)^{2}-2 \cos \theta=2\). Therefore, the initial conditions have been chosen so that the pendulum will rotate upward in the positive (counterclockwise) direction, slowing down and approaching the vertically upward position as \(t \rightarrow \infty\). The phase-plane solution point is moving on the separatrix; thus, loosely speaking, the exact solution is "moving on a knife's edge." If the initial velocity is slightly less, the pendulum will not reach the upright position but will reach a maximum value less than \(\pi\) and then proceed to swing back and forth. If the initial velocity is slightly greater, the pendulum will pass through the vertically upright position and continue to rotate counterclockwise. What happens if we solve this problem numerically? Plot the numerical solutions for \(\theta(t)\) and \(\theta^{\prime}(t)\). Interpret in simple terms what the numerical solution is saying about the pendulum motion on the time interval considered. Does the numerical solution conserve energy?
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