Chapter 6: Problem 23
Use Theorem \(6.2\) to decide whether the given system is a Hamiltonian system. If it is, find a Hamiltonian function for the system. $$ \begin{aligned} &x^{\prime}=-\sin (2 x y)-x \\ &y^{\prime}=\sin (2 x y)+y \end{aligned} $$
Short Answer
Expert verified
If so, find the Hamilton function.
The given system of differential equations is a Hamiltonian system with the Hamiltonian function:
$$
H(x, y) = -x^2 - xy + \frac{1}{2}y^2 + y\cos(2xy).
$$
Step by step solution
01
Compare equations to Hamiltonian system equations
Compare the given system of equations:
$$
\begin{aligned}
x' &= -\sin(2xy) - x, \\
y' &= \sin(2xy) + y,
\end{aligned}
$$
to the equations for a Hamiltonian system:
$$
\begin{aligned}
x' &= \frac{\partial H}{\partial y}, \\
y' &= -\frac{\partial H}{\partial x}.
\end{aligned}
$$
02
Find partial derivatives of the potential Hamiltonian function
From the comparison of equations in Step 1, we can determine the partial derivatives of the potential Hamiltonian function:
$$
\begin{aligned}
\frac{\partial H}{\partial y} &= -\sin(2xy) - x, \\
-\frac{\partial H}{\partial x} &= \sin(2xy) + y.
\end{aligned}
$$
Now, let's integrate these partial derivatives to find H(x, y).
03
Integrate partial derivatives to determine H(x, y)
First, let's integrate the first equation with respect to y:
$$
H(x, y) = \int (-\sin(2xy) - x)dy.
$$
Similarly, let's integrate the second equation with respect to x:
$$
H(x, y) = -\int (\sin(2xy) + y)dx.
$$
04
Find H(x, y) using integration results
The results of the integrations are:
$$
H(x, y) = x\cos(2xy) - xy + g(x),
$$
and
$$
H(x, y) = y\cos(2xy) + \frac{1}{2}y^2 + h(y).
$$
Comparing these expressions for H(x, y), we can deduce that:
$$
H(x, y) = -x^2 - xy + \frac{1}{2}y^2 + y\cos(2xy).
$$
05
Conclusion
The given system is a Hamiltonian system since we were able to find a Hamiltonian function H(x, y). The Hamiltonian function for the system is:
$$
H(x, y) = -x^2 - xy + \frac{1}{2}y^2 + y\cos(2xy).
$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hamiltonian Function
Hamiltonian systems are a special class of dynamical systems characterized by a Hamiltonian function, denoted as \( H(x, y) \). This function represents the total energy of the system. In general, a Hamiltonian system consists of equations of motion derived from the principle of stationary action, with time derivatives expressed in terms of partial derivatives of \( H \). In this context, energy conservation plays a pivotal role, as the Hamiltonian function combines potential and kinetic energy terms.
Hamiltonian Mechanics offers an elegant framework with the equations defined as:
Hamiltonian Mechanics offers an elegant framework with the equations defined as:
- \( x' = \frac{\partial H}{\partial y} \)
- \( y' = -\frac{\partial H}{\partial x} \)
Partial Derivatives
When dealing with Hamiltonian systems, partial derivatives come into play as key tools. These derivatives measure how a multivariable function changes when one of its variables changes, keeping others constant. For a Hamiltonian function \( H(x, y) \), partial derivatives are used to express the system’s dynamics:
- \( \frac{\partial H}{\partial y} \) and \( \frac{\partial H}{\partial x} \)
Integration
Integration is a powerful mathematical tool used to find a function given its derivative. In Hamiltonian systems, integration plays a crucial role in constructing the Hamiltonian function \( H(x, y) \) from known partial derivatives. Once the partial derivatives \( \frac{\partial H}{\partial y} \) and \( -\frac{\partial H}{\partial x} \) have been identified, integration helps us to determine the full Hamiltonian function.
To perform integration:
To perform integration:
- Integrate \( \frac{\partial H}{\partial y} \) with respect to \( y \)
- Integrate \( -\frac{\partial H}{\partial x} \) with respect to \( x \)
Differential Equations
Differential equations are foundational in describing how a system evolves over time. In the context of Hamiltonian systems, differential equations come in pairs, derived from the partial derivatives of the Hamiltonian function \( H(x, y) \). Solving these equations yields insights into the system's trajectory through its phase space.
The specific form of differential equations we encounter:
The specific form of differential equations we encounter:
- \( x' = \frac{\partial H}{\partial y} \)
- \( y' = -\frac{\partial H}{\partial x} \)