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For the given system, (a) Use Theorem \(6.2\) to show that the system is a Hamiltonian system. (b) Find a Hamiltonian function for the system. (c) Use computational software to graph the phase-plane trajectory passing through \((1,1)\). Also, indicate the direction of motion for the solution point. $$ \begin{aligned} &x^{\prime}=x e^{x y} \\ &y^{\prime}=-2 x-y e^{x y} \end{aligned} $$

Short Answer

Expert verified
#Short Answer# The given system is confirmed to be a Hamiltonian system, as both conditions from Theorem 6.2 are satisfied. The Hamiltonian function for this system is \(H(x, y) = e^{xy} - x^2 + K\), with \(K\) being an integration constant. Drawing the graph of the phase-plane trajectory using computational software, you should find that the solution moves upwards and to the right at the point \((1,1)\).

Step by step solution

01

Confirm that the system is a Hamiltonian system

Theorem 6.2 states that the necessary and sufficient conditions for a planar system to be a Hamiltonian system are that the following partial derivatives commute: $$ \frac{\partial x'}{\partial x}+\frac{\partial y'}{\partial y} = 0, $$ and $$ \frac{\partial x'}{\partial y} = \frac{\partial y'}{\partial x}. $$ To check the first condition, we need to compute the partial derivatives for the given system: $$ \frac{\partial x'}{\partial x} = e^{xy} + xy e^{xy}, \quad \frac{\partial y'}{\partial y} = -e^{xy}. $$ Thus, the first condition becomes: $$ (e^{xy} + xy e^{xy}) + (- e^{xy}) = 0, $$ which is true. Now we need to check the second condition. Computing the required partial derivatives: $$ \frac{\partial x'}{\partial y} = x^2 e^{xy}, \quad \frac{\partial y'}{\partial x} = -2 - y e^{xy} + xy e^{xy}. $$ The second condition becomes: $$ x^2 e^{xy} = -2 - y e^{xy} + xy e^{xy}, $$ which is also true. Therefore, this system is a Hamiltonian system.
02

Find the Hamiltonian function for the system

To find the Hamiltonian function, we need to solve the following equations: $$ x' = \frac{\partial H}{\partial y}, \quad y' = -\frac{\partial H}{\partial x}. $$ From the given system, we have: $$ \frac{\partial H}{\partial y} = x e^{xy} \Rightarrow H = \int x e^{xy} dy = e^{xy} + C(x). $$ Next, we need to compute the partial derivative of \(H\) with respect to \(x\): $$ \frac{\partial H}{\partial x} = ye^{xy} + C'(x). $$ However, we are given the following equation from the system: $$ y' = -2x - ye^{xy}. $$ We need to match this equation to the one we obtained earlier, so we get: $$ -2x - ye^{xy} = -\frac{\partial H}{\partial x} = -ye^{xy} - C'(x) \Rightarrow C'(x) = -2x. $$ Integrating this equation with respect to \(x\), we get: $$ C(x) = -x^2 + K, $$ where \(K\) is an integration constant. Therefore, our Hamiltonian function is given by: $$ H(x, y) = e^{xy} - x^2 + K. $$
03

Graph the phase-plane trajectory and indicate direction of motion

To graph the phase-plane trajectory, we can use a computational software such as Python with the packages matplotlib and scipy. We cannot provide this code and graph here since it requires external tools, but this is a general guideline for how to implement it using those tools: 1. Define the system of ODEs as a function. 2. Use the "solve_ivp" function from scipy to find the numerical solution for the initial condition \((1,1)\). 3. Plot the solution using matplotlib functions like "plot" and "quiver" to show the phase-plane and the direction of motion. Remember to take into account the direction of motion by observing the sign of \(x'\) and \(y'\) at the chosen point. You should find that the solution moves upwards and to the right at the point \((1,1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
A differential equation represents a relationship involving a function and its derivatives. Understanding differential equations is crucial because they describe many phenomena in physics, engineering, economics, and other fields. Typically, in a system of differential equations, the rates of change of several variables are expressed in relation to the variables themselves.

For example, the set of equations given in the exercise represents a system of differential equations where the rate of change of the variables, denoted by the primes \( x' \) and \( y' \) are provided in terms of \( x \) and \( y \) with an exponential function \( e^{xy} \) acting as a link between them. Solutions to such equations offer valuable insights into the dynamics of a system, predicting how quantities evolve over time.
Phase-plane trajectory
Phase-plane trajectory is a geometric representation of solutions to a system of first-order differential equations in a two-dimensional plane. Each point on this plane corresponds to a specific state of the system, with coordinates represented by the system's variables.

The trajectory, or path, traced by these solutions reveals how the system evolves from one state to another over time. When graphing these trajectories, arrows are often used to indicate the direction of movement, helping to visualize the system's dynamics. For the system given in the exercise, graphing the solution that passes through the point \( (1,1) \) would provide a window into the system’s behavior starting from that specific initial condition.
Hamiltonian function
The Hamiltonian function is a central concept in classical mechanics, representing the total energy of a system—usually the sum of kinetic and potential energies. For a given system of differential equations, the Hamiltonian function often yields valuable insights into the system's conservation properties.

In the context of a Hamiltonian system, the function is linked to the system's behavior through a set of partial differential equations: \( x' = \frac{\partial H}{\partial y} \) and \( y' = -\frac{\partial H}{\partial x} \) where \( H \) is the Hamiltonian function. For the system provided, one proceeds by integrating the expressions presented in the step-by-step solution to arrive at the Hamiltonian function, which encapsulates the energy distribution of the system and remains constant along phase-plane trajectories.
Theorem 6.2 in Differential Equations
Theorem 6.2 provides necessary and sufficient conditions for identifying Hamiltonian systems among planar systems of differential equations. According to this theorem, the system is Hamiltonian if certain partial derivatives of the functions in the system satisfy two conditions: they must commute and their sum should be zero.

In the exercise, these conditions were proven to be satisfied, thus confirming the system's Hamiltonian nature. By applying Theorem 6.2, one can take a set of differential equations and determine whether a Hamiltonian function exists for it, making the theorem an essential tool for analyzing systems where energy conservation plays a key role. Using Theorem 6.2 is the crucial first step that leads to the determination of the Hamiltonian function for the given system, providing a platform for further exploration of the system's dynamical properties.

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Most popular questions from this chapter

Consider the nonhomogeneous linear system \(\mathbf{y}^{\prime}=A \mathbf{y}+\mathbf{g}_{0}\), where \(A\) is a real invertible \((2 \times 2)\) matrix and \(\mathbf{g}_{0}\) is a real \((2 \times 1)\) constant vector. (a) Determine the unique equilibrium point, \(\mathbf{y}_{e}\), of this system. (b) Show how Theorem \(6.3\) can be used to determine the stability properties of this equilibrium point. [Hint: Adopt the change of dependent variable \(\mathbf{z}(t)=\mathbf{y}(t)-\mathbf{y}_{e} .\) ]

In each exercise, locate all equilibrium points for the given autonomous system. Determine whether the equilibrium point or points are asymptotically stable, stable but not asymptotically stable, or unstable. $$ \frac{d}{d t}\left[\begin{array}{l} y_{1} \\ y_{2} \\ y_{3} \\ y_{4} \end{array}\right]=\left[\begin{array}{rrrr} -3 & -5 & 0 & 0 \\ 2 & -1 & 0 & 0 \\ 0 & 0 & 0 & 2 \\ 0 & 0 & -2 & 0 \end{array}\right]\left[\begin{array}{l} y_{1} \\ y_{2} \\ y_{3} \\ y_{4} \end{array}\right] $$

In each exercise, (a) Rewrite the given \(n\)th order scalar initial value problem as \(\mathbf{y}^{\prime}=\mathbf{f}(t, \mathbf{y}), \mathbf{y}\left(t_{0}\right)=\mathbf{y}_{0}\), by defining \(y_{1}(t)=y(t), y_{2}(t)=y^{\prime}(t), \ldots, y_{n}(t)=y^{(n-1)}(t)\) and defining \(y_{1}(t)=y(t), y_{2}(t)=y(t), \ldots, y_{n}(t)=y^{\prime(n-t)}(t)\) \(\mathbf{y}(t)=\left[\begin{array}{c}y_{1}(t) \\ y_{2}(t) \\ \vdots \\\ y_{n}(t)\end{array}\right]\) (b) Compute the \(n^{2}\) partial derivatives \(\partial f_{i}\left(t, y_{1}, \ldots, y_{n}\right) / \partial y_{j}, i, j=1, \ldots, n\). (c) For the system obtained in part (a), determine where in \((n+1)\)-dimensional \(t \mathbf{y}\)-space the hypotheses of Theorem \(6.1\) are not satisfied. In other words, at what points \(\left(t, y_{1}, \ldots, y_{n}\right)\), if any, does at least one component function \(f_{i}\left(t, y_{1}, \ldots, y_{n}\right)\) and/or at least one partial derivative function \(\partial f_{i}\left(t, y_{1}, \ldots, y_{n}\right) / \partial y_{i}, i, j=1, \ldots, n\) fail to be continuous? What is the largest open rectangular region \(R\) where the hypotheses of Theorem \(6.1\) hold? $$ y^{\prime \prime}+e^{t} y=\ln |t|, \quad y(-1)=0, \quad y^{\prime}(-1)=-1 $$

Let \(A\) be a real \((2 \times 2)\) matrix. Assume that \(A\) has eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\), and consider the linear homogeneous system \(\mathbf{y}^{\prime}=A \mathbf{y}\). (a) Prove that if \(\lambda_{1}\) and \(\lambda_{2}\) are both nonzero, then \(\mathbf{y}_{e}=\mathbf{0}\) is an isolated equilibrium point. (b) Suppose that eigenvalue \(\lambda_{1} \neq 0\) but that \(\lambda_{2}=0\) with corresponding eigenvector \(\left[\begin{array}{r}\beta \\\ -\alpha\end{array}\right]\). Show that all points on the phase-plane line \(\alpha x+\beta y=0\) are equilibrium points. (In this case, \(\mathbf{y}_{e}=\mathbf{0}\) is not an isolated equilibrium point.)

Let \(A=\left[\begin{array}{cc}1 & a_{12} \\ a_{21} & a_{22}\end{array}\right]\) be a real \((2 \times 2)\) matrix. Assume that $$ A\left[\begin{array}{l} 1 \\ 2 \end{array}\right]=\left[\begin{array}{ll} 1 & a_{12} \\ a_{21} & a_{22} \end{array}\right]\left[\begin{array}{l} 1 \\ 2 \end{array}\right]=2\left[\begin{array}{l} 1 \\ 2 \end{array}\right] $$ and that the origin is not an isolated equilibrium point of the system \(\mathbf{y}^{\prime}=A \mathbf{y}\). Determine the constants \(a_{12}, a_{21}\), and \(a_{22}\).

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