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Determine whether the given functions form a fundamental set of solutions for the linear system. $$ \text { 4. } \mathbf{y}^{\prime}=\left[\begin{array}{cc} 0 & 1 \\ t^{-2} & -t^{-1} \end{array}\right] \mathbf{y}, \quad \mathbf{y}_{1}(t)=\left[\begin{array}{l} t \\ 1 \end{array}\right], \quad \mathbf{y}_{2}(t)=\left[\begin{array}{c} t^{-1} \\ -t^{-2} \end{array}\right], \quad 0

Short Answer

Expert verified
Short Answer: Yes, the given solutions form a fundamental set of solutions for the linear system, as the calculated Wronskian is nonzero for the given range of \(t\).

Step by step solution

01

Calculate the Wronskian

First, we will calculate the Wronskian (W) of the given solutions, \(\mathbf{y}_1\) and \(\mathbf{y}_2\). The Wronskian for a 2x2 system is given by the determinant of the matrix formed by these solutions: \[ W(\mathbf{y}_1,\mathbf{y}_2)=\left|\begin{array}{cc}y_{1,1} & y_{2,1}\\y_{1,2} & y_{2,2}\end{array}\right| \] In our case, the Wronskian is: \[ W(\mathbf{y}_1,\mathbf{y}_2)=\left|\begin{array}{cc}t & t^{-1}\\1 & -t^{-2}\end{array}\right| \]
02

Evaluate the determinant of the Wronskian matrix

Now, we will evaluate the determinant of the Wronskian matrix: \[ W(\mathbf{y}_1,\mathbf{y}_2)=t(-t^{-2})-(t^{-1})(1) = -t^{-1}-t^{-1} = -2t^{-1} \]
03

Check if the Wronskian is nonzero

We have found the Wronskian to be -2t^{-1}. Now, we need to check whether this function is nonzero for the given range of \(t\), which is 0<t<\(\infty\). Since \(t\) is always positive for the given range, it's clear that the Wronskian will also be nonzero for \(0<t<\infty\).
04

Conclusion

Since the Wronskian of the given solutions is nonzero for the given range of \(t\), the functions \(\mathbf{y}_1(t)\) and \(\mathbf{y}_2(t)\) form a fundamental set of solutions for the linear system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wronskian
The Wronskian is a key tool in the study of differential equations and provides information about the linear independence of a set of functions. When dealing with sets of solutions to a differential equation, the Wronskian can be utilized to determine whether the functions comprise a fundamental set of solutions. Formally, the Wronskian of two functions, let's say, \(f\) and \(g\), is defined as the determinant of the matrix that contains the functions and their derivatives:
\[ W(f,g)=\begin{vmatrix} f & g \ f' & g' \end{vmatrix} \].
For functions that are solutions to a linear system of differential equations, if the Wronskian is nonzero at some point within the interval of interest, it implies that the set of solutions is linearly independent. This linear independence in turn establishes that we have a fundamental set of solutions to the differential equation on that interval, laying the foundation for expressing the general solution as a linear combination of these fundamental solutions.
Linear Systems of Differential Equations
Linear systems of differential equations consist of multiple differential equations involving the same set of dependent variables. A system is said to be 'linear' if the dependent variables and their derivatives appear to the power of one and are not multiplied or composed with each other.

For instance, a two-dimensional linear system can be represented as:
\[ \begin{aligned}\frac{dy_1}{dt} &= a_{11}(t)y_1 + a_{12}(t)y_2, \frac{dy_2}{dt} &= a_{21}(t)y_1 + a_{22}(t)y_2, \end{aligned}\]
where \(a_{ij}(t)\) are functions of \(t\) but not of \(y_1\) or \(y_2\). Solutions to these systems are sought in the form of vector functions, and these solutions can be understood better through the concept of the fundamental set. If we can find a sufficient number of independent solutions to span the solution space, we can construct any solution to the system from these 'fundamental' solutions.
Determinant of a Matrix
The determinant of a matrix is a special scalar value that provides important information about the matrix and the linear transformations it represents. Typically denoted as \(\det(A)\) or \(|A|\), the determinant can tell us, for example, if a matrix is invertible or what the volume scaling factor of a linear transformation is.

In the context of the Wronskian and differential equations, the determinant is used to assess whether sets of solutions are linearly independent. For a 2x2 matrix \(A\), the determinant is found by:
\[ \det(A) = a_{11}a_{22} - a_{12}a_{21} \].
This corresponds to the computation we do when finding the Wronskian of two solution functions to a differential equation. If the determinant of their associated matrix (the Wronskian matrix) is non-zero, then the solutions are linearly independent and form a fundamental set for the system's general solution.
Homogeneous Equations
Homogeneous equations play a central role in the theory of linear differential equations and their systems. An equation is termed 'homogeneous' when all terms are a product of the dependent variable and its derivatives, and the equation equals zero.

For example, a homogenous linear differential equation of the second order would look like:
\[ ay'' + by' + cy = 0 \],
where \(a\), \(b\), and \(c\) are coefficients that may depend on the independent variable but not on \(y\) or its derivatives. In a system, the homogeneity implies that one can scale solutions and still obtain another solution, which is why the concept pairs well with the principles of linear superposition and independence. Furthermore, the solutions to homogeneous systems are particularly significant as they form the complementary part of the general solution, to which particular solutions of any non-homogeneous part can be added.

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Most popular questions from this chapter

For the problem in the exercise specified, (a) Write a program that carries out Euler's method. Use a step size of \(h=0.01\). (b) Run your program on the interval given.(c) Check your numerical solution by comparing the first two values, \(\mathbf{y}_{1}\) and \(\mathbf{y}_{2}\), with the hand calculations. (d) Plot the components of the numerical solution on a common graph over the time interval of interest.Exercise 4

In each exercise, assume that a numerical solution is desired on the interval \(t_{0} \leq t \leq t_{0}+T\), using a uniform step size \(h\). (a) As in equation (8), write the Euler's method algorithm in explicit form for the given initial value problem. Specify the starting values \(t_{0}\) and \(\mathbf{y}_{0}\). (b) Give a formula for the \(k\) th \(t\)-value, \(t_{k}\). What is the range of the index \(k\) if we choose \(h=0.01\) ? (c) Use a calculator to carry out two steps of Euler's method, finding \(\mathbf{y}_{1}\) and \(\mathbf{y}_{2}\). Use a step size of \(h=0.01\) for the given initial value problem. Hand calculations such as these are used to check the coding of a numerical algorithm.\(\mathbf{y}^{\prime}=\left[\begin{array}{ll}1 & 2 \\ 2 & 3\end{array}\right] \mathbf{y}+\left[\begin{array}{l}1 \\\ 1\end{array}\right], \quad \mathbf{y}(0)=\left[\begin{array}{r}-1 \\\ 1\end{array}\right], \quad 0 \leq t \leq 1\)

Determine all values \(t\) such that \(A(t)\) is invertible and, for those \(t\)-values, find \(A^{-1}(t)\) $$ A(t)=\left[\begin{array}{ll} e^{t} & e^{3 t} \\ e^{2 t} & e^{4 t} \end{array}\right] $$

Let \(A=\left[\begin{array}{ll}\lambda & 1 \\ 0 & \lambda\end{array}\right]\), and let \(E=\left[\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right] .\) Use mathematical induction or the binomial formula to show that \(A^{m}=\lambda^{m} I+m \lambda^{m-1} E\).

A Spring-Mass-Dashpot System with Variable Damping As we saw in Section \(3.6\), the differential equation modeling unforced damped motion of a mass suspended from a spring is \(m y^{\prime \prime}+\gamma y^{\prime}+k y=0\), where \(y(t)\) represents the downward displacement of the mass from its equilibrium position. Assume a mass \(m=1 \mathrm{~kg}\) and a spring constant \(k=4 \pi^{2} \mathrm{~N} / \mathrm{m}\). Also assume the damping coefficient \(\gamma\) is varying with time: $$ \gamma(t)=2 t e^{-t / 2} \mathrm{~kg} / \mathrm{sec} \text {. } $$ Assume, at time \(t=0\), the mass is pulled down \(20 \mathrm{~cm}\) and released. (a) Formulate the appropriate initial value problem for the second order scalar differential equation, and rewrite it as an equivalent initial value problem for a first order linear system. (b) Applying Euler's method, numerically solve this problem on the interval \(0 \leq t \leq 10 \mathrm{~min}\). Use a step size of \(h=0.005\). (c) Plot the numerical solution on the time interval \(0 \leq t \leq 10 \mathrm{~min}\). Explain, in qualitative terms, the effect of the variable damping upon the solution.

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