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The general solution of the nonhomogeneous differential equation y+αy+βy=g(t) is given, where c1 and c2 are arbitrary constants. Determine the constants α and β and the function g(t). y(t)=c1et+c2e2t+2e2t

Short Answer

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In summary, the given nonhomogeneous differential equation is: y(t)6y(t)+12y(t)=8 with the general solution: y(t)=c1et+c2e2t+2e2t

Step by step solution

01

Find the first and second derivatives of y(t)

To find the first derivative y'(t), we need to differentiate y(t) with respect to t: y(t)=ddt(c1et+c2e2t+2e2t) By applying the standard rules for derivatives, we obtain: y(t)=c1et+2c2e2t4e2t Next, we'll find the second derivative y''(t) by differentiating y'(t) with respect to t: y(t)=ddt(c1et+2c2e2t4e2t) By applying the standard rules for derivatives, we obtain: y(t)=c1et+4c2e2t+8e2t
02

Substitute y(t), y'(t), and y''(t) into the given differential equation

We can now substitute the expressions for y(t), y'(t), and y''(t) into the given differential equation: y(t)+αy(t)+βy(t)=g(t) Substituting, we get: (c1et+4c2e2t+8e2t)+α(c1et+2c2e2t4e2t)+β(c1et+c2e2t+2e2t)=g(t)
03

Collect terms and find α, β, and g(t)

By combining terms with the same exponential factor, we arrive at a new system of equations: (1+α+β)c1et+(2α+β)c2e2t+(α4)e2t+8e2t=g(t) To satisfy this equation, we can match the coefficients of each exponential term on both sides of the equation. By doing this, we can find the values for α, β, and g(t) as follows: For the term et: 1+α+β=0 For the term e2t: 2α+β=0 For the term e2t: α4=g(t) 8=g(t) Solving the system of equations, we get: α=6 β=12 g(t)=8 Therefore, the constants α and β are -6 and 12, respectively, and the function g(t) is 8.

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