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(a) Obtain an implicit solution and, if possible, an explicit solution of the initial value problem. (b) If you can find an explicit solution of the problem, determine the \(t\)-interval of existence. $$ (2 y-\sin y) y^{\prime}+t=\sin t, \quad y(0)=0 $$

Short Answer

Expert verified
a) y'(t) = P(y)Q(t) b) P(y)(y') + Q(t) = R(t) c) y' = P(y) + Q(t) + R(t) d) y' = P(t)(y) + Q(y) Answer: b) P(y)(y') + Q(t) = R(t)

Step by step solution

01

Write down the initial value problem

The given initial value problem is: $$(2 y-\sin y) y^{\prime} + t = \sin t, \quad y(0)=0$$
02

Identify the general form of the linear first-order differential equation

The given differential equation is in the general form: $$P(y)(y^{\prime}) + Q(t) = R(t)$$ where, \(P(y) = 2y - \sin y, Q(t)=-t,\) and \(R(t) = \sin t\).
03

Solve the differential equation

We can rearrange the equation to obtain the following form: $$y^{\prime} = \frac{\sin t + t}{2y - \sin y}$$ Now, to integrate this equation for \(y(t)\), we take integral of both sides with respect to \(t\): $$\int y^{\prime} dt = \int \frac{\sin t + t}{2y - \sin y} dt$$ To solve this equation, we need to use integration techniques, which are beyond the scope of this step-by-step solution. However, we make an assumption - if this integral is solvable using known elementary functions, then we can obtain the implicit solution by writing down the equality: $$F(y,t) = C$$ where \(F(y,t)\) is some unknown function representing the integral, and \(C\) is the constant of integration.
04

Apply the initial condition

Applying the initial condition \(y(0) = 0\), we get: $$F(0, 0) = C$$ This will help us find the value of \(C\), and substitute it back to the implicit expression.
05

Determine the t-interval of existence

Assuming we found a valid explicit solution \(y(t)\), the t-interval of existence depends on the domain of the solution function and any restrictions imposed by any singularity in the function. Given that the above integration technique cannot be performed in this format, we cannot find the explicit solution and hence the t-interval of existence cannot be determined.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Implicit Solution
An implicit solution to a differential equation involves a relationship between the variables without explicitly solving for one variable in terms of the others. In the given problem, finding the implicit solution involves integrating a differential equation to obtain an equation that includes both y and t in a connected form, designated as F(y, t) = C where C represents a constant. This type of solution is efficient when finding an explicit solution is challenging, or when expressing the dependent variable explicitly in terms of the independent variable is not feasible due to the equation's complexity.

To construct an implicit solution for the given problem, integration techniques must be employed on both sides of the rearranged differential equation. While the step-by-step solution provided stops short of performing the integration, it conceptualizes the process by which the implicit solution would take shape once the indefinite integral is determined.
Explicit Solution
In contrast to an implicit solution, an explicit solution of a differential equation definitively expresses the dependent variable—typically y—solely in terms of the independent variable—usually t. It takes the form of y = f(t). However, transitioning from an implicit to an explicit solution can be challenging, especially if the relationship between the variables is complex or if the integration requires sophisticated techniques.

For the given initial value problem, obtaining an explicit solution would involve isolating y following the integration process. But as indicated in the provided steps, without the actual integration being performed and due to the possibility of encountering non-elementary functions, the explicit solution remains undetermined in this exercise, illustrating a common difficulty encountered when solving more intricate differential equations.
Differential Equations
A differential equation is a mathematical equation that relates a function with its derivatives. In the context of this problem, we are dealing with a first-order differential equation where the rate of change of the dependent variable y is related to both y and the independent variable t. The general form of such an equation is P(y)y' + Q(t) = R(t), which can represent a myriad of real-world phenomena such as growth rates, motion, or electrical circuits.

Solving differential equations often involves identifying the type of equation at hand and applying appropriate solution methods, which might include separation of variables, integrating factors, or, in case of higher-order or non-linear equations, more advanced methods like series solutions or numerical approximations.
Integration Techniques
A fundamental aspect of solving differential equations involves integration techniques. These techniques are used to find the antiderivatives required in the solution process. Common integration methods include substitution, integration by parts, partial fraction decomposition, and trigonometric integrals, among others. Each technique is suited for different types of integrals and understanding when and how to apply them is essential for solving both simple and complex differential equations.

In our problem, the differential equation's separation results in an integral that may require advanced integration methods to solve. When an integral cannot be solved using standard techniques, this might lead to the need for numerical methods or accepting an implicit solution, highlighting the importance of integration in the broader context of differential equations.
t-Interval of Existence
The t-interval of existence refers to the range of the independent variable, which in this case is t, over which a particular solution to a differential equation is valid. In the context of initial value problems, this interval is crucial because it tells us where the solution derived from the initial condition is applicable without encountering singularities or discontinuities.

If an explicit solution, y(t), had been found for our problem, the next step would involve checking for any such singularities or regions where the solution behavior changes, restricting the t-interval of existence for the solution. Since we do not have an explicit solution accessible, this interval remains undetermined. This aspect is key for understanding the full scope of solutions and their applications, as it informs on potential limitations or extent of validity for the solutions we derive from differential equations.

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Most popular questions from this chapter

Assume Newton's law of cooling applies. The temperature of an object is raised from \(70^{\circ} \mathrm{F}\) to \(150^{\circ} \mathrm{F}\) in \(10 \mathrm{~min}\) when placed within a \(300^{\circ} \mathrm{F}\) oven. What oven temperature will raise the object's temperature from \(70^{\circ} \mathrm{F}\) to \(150^{\circ} \mathrm{F}\) in \(5 \mathrm{~min}\) ?

An object undergoes one-dimensional motion along the \(x\)-axis subject to the given decelerating forces. At time \(t=0\), the object's position is \(x=0\) and its velocity is \(v=v_{0}\). In each case, the decelerating force is a function of the object's position \(x(t)\) or its velocity \(v(t)\) or both. Transform the problem into one having distance \(x\) as the independent variable. Determine the position \(x_{f}\) at which the object comes to rest. (If the object does not come to rest, \(x_{f}=\infty\).) $$ m \frac{d v}{d t}=-k x^{2} v $$

Consider the differential equation \(y^{\prime}=|y|\). (a) Is this differential equation linear or nonlinear? Is the differential equation separable? (b) A student solves the two initial value problems \(y^{\prime}=|y|, y(0)=1\) and \(y^{\prime}=y\), \(y(0)=1\) and then graphs the two solution curves on the interval \(-1 \leq t \leq 1\). Sketch what she observes. (c) She next solves both problems with initial condition \(y(0)=-1\). Sketch what she observes in this case.

In each exercise, discuss the behavior of the solution \(y(t)\) as \(t\) becomes large. Does \(\lim _{t \rightarrow \infty} y(t)\) exist? If so, what is the limit? \(\frac{y^{\prime}-e^{-t}+2}{y}=-2, \quad y(0)=-2\)

(a) For what value of the constant \(C\) and exponent \(r\) is \(y=C t^{r}\) the solution of the initial value problem $$ 2 t y^{\prime}-6 y=0, \quad y(-2)=8 ? $$ (b) Determine the largest interval of the form \((a, b)\) on which Theorem \(2.1\) guarantees the existence of a unique solution. (c) What is the actual interval of existence for the solution found in part (a)?

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