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Given that \(x=\phi(t), y=\psi(t)\) is a solution of the autonomous system $$ d x / d t=F(x, y), \quad d y / d t=G(x, y) $$ for \(\alpha

Short Answer

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Question: Show that if x = φ(t) and y = ψ(t) are solutions for the autonomous system, \[ \frac{dx}{dt} = F(x, y) \] \[ \frac{dy}{dt} = G(x, y) \] for the range \(\alpha < t < \beta\), then x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) are also solutions for the autonomous system for the range \(\alpha + s < t < \beta + s\) for any real number s.

Step by step solution

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01

Differentiate Φ(t) and Ψ(t) with respect to t

Now, we will find the derivatives \(\frac{dΦ}{dt}\) and \(\frac{dΨ}{dt}\) using the chain rule. \[ \frac{dΦ}{dt} = \frac{d\phi(t-s)}{dt} = \phi'(t-s)\frac{d(t-s)}{dt} = \phi'(t-s) \] \[ \frac{dΨ}{dt} = \frac{d\psi(t-s)}{dt} = \psi'(t-s)\frac{d(t-s)}{dt} = \psi'(t-s) \]
02

Rewrite F and G in terms of Φ and Ψ

Using the initial information, we can write the following equations: \[ \frac{dx}{dt} = F(x, y) \Rightarrow \frac{d\phi}{dt} = F(\phi(t), \psi(t)) \] \[ \frac{dy}{dt} = G(x, y) \Rightarrow \frac{d\psi}{dt} = G(\phi(t), \psi(t)) \] Now we need to rewrite the functions F and G in terms of Φ(t) and Ψ(t): \[ F(x, y) = F(\Phi(t), \Psi(t)) = F(\phi(t-s), \psi(t-s)) \] \[ G(x, y) = G(\Phi(t), \Psi(t)) = G(\phi(t-s), \psi(t-s)) \]
03

Check if the new functions satisfy the autonomous system

In this step, we will compare the derivatives we found in Step 1 with rewritten F and G functions from Step 2. We have: \[ \frac{dΦ}{dt} = \phi'(t-s) = F(\phi(t-s), \psi(t-s)) = F(\Phi(t), \Psi(t)) \] \[ \frac{dΨ}{dt} = \psi'(t-s) = G(\phi(t-s), \psi(t-s)) = G(\Phi(t), \Psi(t)) \] So, x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) satisfy the autonomous system.
04

Verify if the new solutions work for the given range of t

The original range of t is given by \(\alpha < t < \beta\). We need to show that the new solutions x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) satisfy the range \(\alpha + s < t < \beta + s\). Since φ(t) and ψ(t) are initially defined for the range \(\alpha < t < \beta\), we can rewrite the range for Φ(t) and Ψ(t) as follows: \[ \alpha < t - s < \beta \Rightarrow \alpha + s < t < \beta + s \] With this, we have shown that x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) is a solution for the given autonomous system for the range \(\alpha + s < t < \beta + s\) for any real number s.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a vital concept in calculus used for differentiating composite functions. It helps us understand how changes in one variable affect another through a linked sequence of functions. In simpler terms, the chain rule allows us to take the derivative of a function that is defined in terms of another function.

Here's how it works: If you have a function that depends on another function—say, if \( y = f(g(x)) \)—the derivative of \( y \) with respect to \( x \) is found by multiplying the derivative of \( y \) with respect to \( g \) by the derivative of \( g \) with respect to \( x \). Mathematically, this is expressed as:
\[\frac{dy}{dx} = \frac{dy}{dg} \cdot \frac{dg}{dx}\]

In the context of the given problem, this rule is applied to find \( \frac{d\Phi}{dt} \) and \( \frac{d\Psi}{dt} \) by differentiating \( \phi(t-s) \) and \( \psi(t-s) \) with respect to \( t \).
  • Since \( t-s \) is a straightforward subtraction, its derivative with respect to \( t \) is 1.
  • The result is a simpler derivative that matches the functions \( F \) and \( G \).
Differential Equations
Differential equations are mathematical equations that relate some function with its derivatives. Essentially, they capture how a particular quantity changes over time or space.

In the problem at hand, we're dealing with an autonomous differential system:
  • Autonomous systems have functions \( F(x, y) \) and \( G(x, y) \) that depend only on the variables \( x \) and \( y \), and not explicitly on time \( t \).
  • This property implies that the system's behavior depends only on its current state and not on how it arrived there.
By working with the differential equations \( \frac{dx}{dt} = F(x, y) \) and \( \frac{dy}{dt} = G(x, y) \), we seek to find functions \( \phi(t) \) and \( \psi(t) \) that describe the evolution of \( x \) and \( y \) over time. The solution \( x = \phi(t-s) \) and \( y = \psi(t-s) \) demonstrates how these equations hold true even after a horizontal shift in time, ensuring they continue to satisfy the system.
Time Translation Invariance
Time translation invariance is a key feature of autonomous systems, where the equations governing the system's behavior do not change over time. This means the system behaves the same way, irrespective of the time reference we choose.

In practical terms, this invariance allows us to shift the solution of a differential equation system in time without altering its correctness. For instance:
  • Original solutions are given by \( x = \phi(t) \) and \( y = \psi(t) \).
  • By shifting the time reference to \( t-s \), we produce new solutions \( x = \Phi(t) = \phi(t-s) \) and \( y = \Psi(t) = \psi(t-s) \).
  • Even with this shift, the structure of the equations remains unchanged as \( \frac{dx}{dt} = F(x, y) \) and \( \frac{dy}{dt} = G(x, y) \) continue to hold true.
This property simplifies the analysis of systems over different time intervals, ensuring consistency across shifts.

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Most popular questions from this chapter

Consider the competition between bluegill and redear mentioned in Problem 6. Suppose that \(\epsilon_{2} / \alpha_{2}>\epsilon_{1} / \sigma_{1}\) and \(\epsilon_{1} / \alpha_{1}>\epsilon_{2} / \sigma_{2}\) so, as shown in the text, there is a stable equilibrium point at which both species can coexist. It is convenient to rewrite the equations of Problem 6 in terms of the carrying capacity of the pond for bluegill \(\left(B=\epsilon_{1} / \sigma_{1}\right)\) in the absence of redear and its carrying capacity for redear \(\left(R=\epsilon_{2} / \sigma_{2}\right)\) in the absence of bluegill. a. Show that the equations of Problem 6 take the form $$\frac{d x}{d t}=\epsilon_{1} x\left(1-\frac{1}{B} x-\frac{\gamma_{1}}{B} y\right), \frac{d y}{d t}=\epsilon_{2} y\left(1-\frac{1}{R} y-\frac{\gamma_{2}}{R} x\right)$$ where \(\gamma_{1}=\alpha_{1} / \sigma_{1}\) and \(\gamma_{2}=\alpha_{2} / \sigma_{2} .\) Determine the coexistence equilibrium point \((X, Y)\) in terms of \(B, R, \gamma_{1},\) and \(\gamma_{2}\) b. Now suppose that an angler fishes only for bluegill with the effect that \(B\) is reduced. What effect does this have on the equilibrium populations? Is it possible, by fishing, to reduce the population of bluegill to such a level that they will die out?

Can be interpreted as describing the interaction of two species with population densities \(x\) and \(y .\) In each of these problems carry out the following steps. (a) Draw a direction field and describe how solutions seem to behave. (b) Find the critical points. (c) For each critical point find the corresponding linear system. Find the eigenvalues and eigenvectors of the linear system; classify each critical point as to type, and determine whether it is asymptotically stable, or unstable. (d) Sketch the trajectories in the neighborhood of each critical point. (e) Draw a phase portrait for the system. (f) Determine the limiting behavior of \(x\) and \(y\) as \(t \rightarrow \infty\) and interpret the results in terms of the populations of the two species. $$ \begin{array}{l}{d x / d t=x\left(-1+2.5 x-0.3 y-x^{2}\right)} \\ {d y / d t=y(-1.5+x)}\end{array} $$

Construct a suitable Liapunov function of the form \(a x^{2}+c y^{2}\) where \(a\) and \(c\) are to be determined. Then show that the critical point at the origin is of the indicated type. $$ d x / d t=x^{3}-y^{3}, \quad d y / d t=2 x y^{2}+4 x^{2} y+2 y^{3} ; \quad \text { unstable } $$

(a) Determine all critical points of the given system of equations. (b) Find the corresponding linear system near each critical point. (c) Find the eigenalues of each linear system. What conclusions can you then draw about the nonlinear system? (d) Draw a phase portrait of the nonlinear system to confirm your conclusions, or to extend them in those cases where the linear system does not provide definite information about the nonlinear system. $$ d x / d t=x-y^{2}, \quad d y / d t=y-x^{2} $$

(a) Determine all critical points of the given system of equations. (b) Find the corresponding linear system near each critical point. (c) Find the eigenalues of each linear system. What conclusions can you then draw about the nonlinear system? (d) Draw a phase portrait of the nonlinear system to confirm your conclusions, or to extend them in those cases where the linear system does not provide definite information about the nonlinear system. $$ d x / d t=-(x-y)(1-x-y), \quad d y / d t=x(2+y) $$

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