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Given that \(x=\phi(t), y=\psi(t)\) is a solution of the autonomous system $$ d x / d t=F(x, y), \quad d y / d t=G(x, y) $$ for \(\alpha

Short Answer

Expert verified
Question: Show that if x = φ(t) and y = ψ(t) are solutions for the autonomous system, \[ \frac{dx}{dt} = F(x, y) \] \[ \frac{dy}{dt} = G(x, y) \] for the range \(\alpha < t < \beta\), then x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) are also solutions for the autonomous system for the range \(\alpha + s < t < \beta + s\) for any real number s.

Step by step solution

01

Differentiate Φ(t) and Ψ(t) with respect to t

Now, we will find the derivatives \(\frac{dΦ}{dt}\) and \(\frac{dΨ}{dt}\) using the chain rule. \[ \frac{dΦ}{dt} = \frac{d\phi(t-s)}{dt} = \phi'(t-s)\frac{d(t-s)}{dt} = \phi'(t-s) \] \[ \frac{dΨ}{dt} = \frac{d\psi(t-s)}{dt} = \psi'(t-s)\frac{d(t-s)}{dt} = \psi'(t-s) \]
02

Rewrite F and G in terms of Φ and Ψ

Using the initial information, we can write the following equations: \[ \frac{dx}{dt} = F(x, y) \Rightarrow \frac{d\phi}{dt} = F(\phi(t), \psi(t)) \] \[ \frac{dy}{dt} = G(x, y) \Rightarrow \frac{d\psi}{dt} = G(\phi(t), \psi(t)) \] Now we need to rewrite the functions F and G in terms of Φ(t) and Ψ(t): \[ F(x, y) = F(\Phi(t), \Psi(t)) = F(\phi(t-s), \psi(t-s)) \] \[ G(x, y) = G(\Phi(t), \Psi(t)) = G(\phi(t-s), \psi(t-s)) \]
03

Check if the new functions satisfy the autonomous system

In this step, we will compare the derivatives we found in Step 1 with rewritten F and G functions from Step 2. We have: \[ \frac{dΦ}{dt} = \phi'(t-s) = F(\phi(t-s), \psi(t-s)) = F(\Phi(t), \Psi(t)) \] \[ \frac{dΨ}{dt} = \psi'(t-s) = G(\phi(t-s), \psi(t-s)) = G(\Phi(t), \Psi(t)) \] So, x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) satisfy the autonomous system.
04

Verify if the new solutions work for the given range of t

The original range of t is given by \(\alpha < t < \beta\). We need to show that the new solutions x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) satisfy the range \(\alpha + s < t < \beta + s\). Since φ(t) and ψ(t) are initially defined for the range \(\alpha < t < \beta\), we can rewrite the range for Φ(t) and Ψ(t) as follows: \[ \alpha < t - s < \beta \Rightarrow \alpha + s < t < \beta + s \] With this, we have shown that x = Φ(t) = φ(t - s) and y = Ψ(t) = ψ(t - s) is a solution for the given autonomous system for the range \(\alpha + s < t < \beta + s\) for any real number s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a vital concept in calculus used for differentiating composite functions. It helps us understand how changes in one variable affect another through a linked sequence of functions. In simpler terms, the chain rule allows us to take the derivative of a function that is defined in terms of another function.

Here's how it works: If you have a function that depends on another function—say, if \( y = f(g(x)) \)—the derivative of \( y \) with respect to \( x \) is found by multiplying the derivative of \( y \) with respect to \( g \) by the derivative of \( g \) with respect to \( x \). Mathematically, this is expressed as:
\[\frac{dy}{dx} = \frac{dy}{dg} \cdot \frac{dg}{dx}\]

In the context of the given problem, this rule is applied to find \( \frac{d\Phi}{dt} \) and \( \frac{d\Psi}{dt} \) by differentiating \( \phi(t-s) \) and \( \psi(t-s) \) with respect to \( t \).
  • Since \( t-s \) is a straightforward subtraction, its derivative with respect to \( t \) is 1.
  • The result is a simpler derivative that matches the functions \( F \) and \( G \).
Differential Equations
Differential equations are mathematical equations that relate some function with its derivatives. Essentially, they capture how a particular quantity changes over time or space.

In the problem at hand, we're dealing with an autonomous differential system:
  • Autonomous systems have functions \( F(x, y) \) and \( G(x, y) \) that depend only on the variables \( x \) and \( y \), and not explicitly on time \( t \).
  • This property implies that the system's behavior depends only on its current state and not on how it arrived there.
By working with the differential equations \( \frac{dx}{dt} = F(x, y) \) and \( \frac{dy}{dt} = G(x, y) \), we seek to find functions \( \phi(t) \) and \( \psi(t) \) that describe the evolution of \( x \) and \( y \) over time. The solution \( x = \phi(t-s) \) and \( y = \psi(t-s) \) demonstrates how these equations hold true even after a horizontal shift in time, ensuring they continue to satisfy the system.
Time Translation Invariance
Time translation invariance is a key feature of autonomous systems, where the equations governing the system's behavior do not change over time. This means the system behaves the same way, irrespective of the time reference we choose.

In practical terms, this invariance allows us to shift the solution of a differential equation system in time without altering its correctness. For instance:
  • Original solutions are given by \( x = \phi(t) \) and \( y = \psi(t) \).
  • By shifting the time reference to \( t-s \), we produce new solutions \( x = \Phi(t) = \phi(t-s) \) and \( y = \Psi(t) = \psi(t-s) \).
  • Even with this shift, the structure of the equations remains unchanged as \( \frac{dx}{dt} = F(x, y) \) and \( \frac{dy}{dt} = G(x, y) \) continue to hold true.
This property simplifies the analysis of systems over different time intervals, ensuring consistency across shifts.

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Most popular questions from this chapter

Consider the linear system $$ d x / d t=a_{11} x+a_{12} y, \quad d y / d t=a_{21} x+a_{22} y $$ where \(a_{11}, \ldots, a_{22}\) are real constants. Let \(p=a_{11}+a_{22}, q=a_{11} a_{22}-a_{12} a_{21},\) and \(\Delta=\) \(p^{2}-4 q\). Show that the critical point \((0,0)\) is a (a) Node if \(q>0\) and \(\Delta \geq 0\) (b) Saddle point if \(q<0\); (c) Spiral point if \(p \neq 0\) and \(\Delta<0\); (d) Center if \(p=0\) and \(q>0\). Hint: These conclusions can be obtained by studying the eigenvalues \(r_{1}\) and \(r_{2}\). It may also be helpful to establish, and then to use, the relations \(r_{1} r_{2}=q\) and \(r_{1}+r_{2}=p\).

We will prove part of Theorem 9.3 .2 : If the critical point \((0,0)\) of the almost linear system $$ d x / d t=a_{11} x+a_{12} y+F_{1}(x, y), \quad d y / d t=a_{21} x+a_{22} y+G_{1}(x, y) $$ is an asymptotically stable critical point of the corresponding linear system $$ d x / d t=a_{11} x+a_{12} y, \quad d y / d t=a_{21} x+a_{22} y $$ then it is an asymptotically stable critical point of the almost linear system (i). Problem 12 deals with the corresponding result for instability. Consider the linear system (ii). (a) Since \((0,0)\) is an asymptotically stable critical point, show that \(a_{11}+a_{22}<0\) and \(\left.a_{11} a_{22}-a_{12} a_{21}>0 . \text { (See Problem } 21 \text { of Section } 9.1 .\right)\) (b) Construct a Liapunov function \(V(x, y)=A x^{2}+B x y+C y^{2}\) such that \(V\) is positive definite and \(\hat{V}\) is negative definite. One way to ensure that \(\hat{V}\) is negative definite is to choose \(A, B,\) and \(C\) so that \(\hat{V}(x, y)=-x^{2}-y^{2} .\) Show that this leads to the result $$ \begin{array}{l}{A=-\frac{a_{21}^{2}+a_{22}^{2}+\left(a_{11} a_{22}-a_{12} a_{21}\right)}{2 \Delta}, \quad B=\frac{a_{12} a_{22}+a_{11} a_{21}}{\Delta}} \\\ {C=-\frac{a_{11}^{2}+a_{12}^{2}+\left(a_{11} a_{22}-a_{12} a_{21}\right)}{2 \Delta}}\end{array} $$ where \(\Delta=\left(a_{11}+a_{22}\right)\left(a_{11} a_{22}-a_{12} a_{21}\right)\) (c) Using the result of part (a) show that \(A>0\) and then show (several steps of algebra are required) that $$ 4 A C-B^{2}=\frac{\left(a_{11}^{2}+a_{12}^{2}+a_{21}^{2}+a_{22}^{2}\right)\left(a_{11} a_{22}-a_{12} a_{21}\right)+2\left(a_{11} a_{22}-a_{12} a_{21}\right)^{2}}{\Delta^{2}}>0 $$ Thus by Theorem 9.6.4, \(V\) is positive definite.

(a) Find all the critical points (equilibrium solutions). (b) Use a computer to draw a direction field and portrait for the system. (c) From the plot(s) in part (b) determine whether each critical point is asymptotically stable, stable, or unstable, and classify it as to type. $$ d x / d t=(2+x)(y-x), \quad d y / d t=(4-x)(y+x) $$

(a) Show that the system $$ d x / d t=-y+x f(r) / r, \quad d y / d t=x+y f(r) / r $$ has periodic solutions corresponding to the zeros of \(f(r) .\) What is the direction of motion on the closed trajectories in the phase plane? (b) Let \(f(r)=r(r-2)^{2}\left(r^{2}-4 r+3\right)\). Determine all periodic solutions and determine their stability characteristics.

(a) Find the eigenvalues and eigenvectors. (b) Classify the critical point \((0,0)\) as to type and determine whether it is stable, asymptotically stable, or unstable. (c) Sketch several trajectories in the phase plane and also sketch some typical graphs of \(x_{1}\) versus \(t .\) (d) Use a computer to plot accurately the curves requested in part (c). \(\frac{d \mathbf{x}}{d t}=\left(\begin{array}{cc}{2} & {-\frac{5}{2}} \\\ {\frac{9}{5}} & {-1}\end{array}\right) \mathbf{x}\)

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