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Consider the system \(\mathbf{x}^{\prime}=\mathbf{A} \mathbf{x},\) and suppose that \(\mathbf{A}\) has one zero eigenvalue. (a) Show that \(\mathbf{x}=\mathbf{0}\) is a critical point, and that, in addition, every point on a certain straight line through the origin is also a critical point. (b) Let \(r_{1}=0\) and \(r_{2} \neq 0,\) and let \(\boldsymbol{\xi}^{(1)}\) and \(\boldsymbol{\xi}^{(2)}\) be corresponding eigenvectors. Show that the trajectories are as indicated in Figure \(9.1 .8 .\) What is the direction of motion on the trajectories?

Short Answer

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b) Describe the direction of motion on the trajectories of the system.

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01

Find the critical points

To find the critical points, we need to determine when \(\mathbf{x}^{\prime}=\mathbf{0}\). So we have \(\mathbf{A} \mathbf{x} = \mathbf{0}\). As the matrix \(\mathbf{A}\) has one zero eigenvalue, it means that there is one non-trivial solution to the equation \(\mathbf{A}\mathbf{x} = \mathbf{0}\). This implies that there is an eigenvector corresponding to the zero eigenvalue which makes the whole vector equation equal to zero. So the critical points will lie on a straight line through the origin. ##STEP 2: Find the eigenvectors and eigenvalues##
02

Find the eigenvectors and eigenvalues

We are given that \(r_1 = 0\) and \(r_2\neq0\), and corresponding eigenvectors \(\boldsymbol{\xi}^{(1)}\) and \(\boldsymbol{\xi}^{(2)}\). ##STEP 3: Characterize the direction of motion on the trajectories##
03

Characterize the direction of motion on the trajectories

Let's consider the system \(\mathbf{x}^{\prime}=\mathbf{A} \mathbf{x}\). Since \(\textbf{A}\boldsymbol{\xi}^{(1)}=0\), we have \(\boldsymbol{\xi}^{(1)}=constant\). Also, \(\textbf{A}\boldsymbol{\xi}^{(2)}=r_{2}\boldsymbol{\xi}^{(2)}\). Divide by \(r_2\), we have \(\frac{1}{r_2}\mathbf{A}\boldsymbol{\xi}^{(2)}=\boldsymbol{\xi}^{(2)}\) which indicates that \(\frac{d\boldsymbol{\xi}}{dt}=\frac{1}{r_2}\mathbf{A}\boldsymbol{\xi}^{(2)}\). Putting the two equations together, we have \(\frac{d\mathbf{x}}{dt}=c_1\boldsymbol{\xi}^{(1)}+c_2 \frac{1}{r_2}\mathbf{A}\boldsymbol{\xi}^{(2)}\), where \(c_1\) and \(c_2\) are constants depending on the initial condition. The trajectories will be a combination of the eigenvectors \(\boldsymbol{\xi}^{(1)}\) and \(\boldsymbol{\xi}^{(2)}\). If \(c_1\neq0\), the direction of motion will be parallel to \(\boldsymbol{\xi}^{(1)}\), and the trajectories will lie in the straight line formed by \(\boldsymbol{\xi}^{(1)}\). If \(c_1=0\), the direction of motion will be parallel to \(\boldsymbol{\xi}^{(2)}\), and the trajectories will be formed by exponentiating the contribution from eigenvector \(\boldsymbol{\xi}^{(2)}\).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues and Eigenvectors
Eigenvalues and eigenvectors are fundamental concepts in the study of linear algebra and are particularly important in the analysis of systems described by differential equations. When we encounter a linear system of equations like \( \mathbf{x}^{\prime} = \mathbf{A} \mathbf{x} \) where \( \mathbf{A} \) is a matrix, eigenvalues and eigenvectors give us crucial information about system dynamics.

Eigenvalues, denoted by \( r \), are scalars that result from solving the characteristic equation \( \det(\mathbf{A} - r \mathbf{I}) = 0 \), where \( \mathbf{I} \) is the identity matrix. Each eigenvalue has at least one associated eigenvector, which is a non-zero vector \( \boldsymbol{\xi} \) that satisfies the equation \( \mathbf{A}\boldsymbol{\xi} = r\boldsymbol{\xi} \).

The existence of a zero eigenvalue indicates that the matrix \( \mathbf{A} \) is not invertible and the system has infinitely many solutions along a certain line—the eigenvector corresponding to the zero eigenvalue. In the context of dynamical systems, an eigenvector provides a direction along which the dynamics are invariant. With these concepts in mind, we can begin to understand the nature of our system's critical points and their behavior.
Phase Portrait
A phase portrait is a geometric representation of the trajectories of a dynamical system in the phase plane. Each point in this plane corresponds to a state of the system, and the trajectories show how these states evolve over time.

When analyzing the phase portrait of the system \( \mathbf{x}^{\prime} = \mathbf{A} \mathbf{x} \) with one zero eigenvalue, we observe that trajectories tend to align with the eigenvectors of the matrix \( \mathbf{A} \). For instance, if we draw the phase portrait, we would see lines or curves that correspond to the eigenvectors \( \boldsymbol{\xi}^{(1)} \) and \( \boldsymbol{\xi}^{(2)} \), with the direction of the motion indicated by the sign of the corresponding non-zero eigenvalue.

The trajectory associated with the zero eigenvalue, \( \boldsymbol{\xi}^{(1)} \) in this case, will be a line passing through the origin. This line is a set of points where the system is in equilibrium, or a critical line. In contrast, the trajectory associated with the non-zero eigenvalue, \( \boldsymbol{\xi}^{(2)} \) here, will express how the system evolves over time away from equilibrium. By analyzing the phase portrait, one can predict the stability of the critical points and the long-term behavior of the system.
Dynamical Systems
Dynamical systems theory is concerned with how a particular system — described by a set of rules or equations — behaves over time. In the context of differential equations, a dynamical system can often be described by the evolution of a point in a geometric space, usually referred to as the 'state space' or 'phase space', with time.

In our exercise, the linear dynamical system is represented by \( \mathbf{x}^{\prime} = \mathbf{A} \mathbf{x} \), where \( \mathbf{x} \) is a vector that describes the state of the system and \( \mathbf{A} \) is a matrix that determines the system's rules. The critical points, or the states where the system does not change over time (i.e., \( \mathbf{x}^{\prime} = \mathbf{0} \)), play a vital role in understanding the system's behavior.

In this example, the line of critical points associated with a zero eigenvalue represents a continuous set of equilibrium states. This feature is a hallmark of certain dynamical systems, indicating that small disturbances in the direction of the zero eigenvalue will not move the system away from the critical line. However, the system's response to disturbances in other directions is determined by the other eigenvalues and eigenvectors, leading to either growth or decay — essential concepts for predicting the system's response over time.

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Most popular questions from this chapter

As mentioned in the text, one improvement in the predator-prey model is to modify the equation for the prey so that it has the form of a logistic equation in the absence of the predator. Thus in place of Eqs. ( 1 ) we consider the system $$ d x / d t=x(a-\sigma x-\alpha y), \quad d y / d t=y(-c+\gamma x) $$ where \(a, \sigma, \alpha, c,\) and \(\gamma\) are positive constants. Determine all critical points and discuss their nature and stability characteristics. Assume that \(a / \sigma \gg c / \gamma .\) What happens for initial data \(x \neq 0, y \neq 0 ?\)

The motion of a certain undamped pendulum is described by the equations $$ d x / d t=y, \quad d y / d t=-4 \sin x $$ If the pendulum is set in motion with an angular displacement \(A\) and no initial velocity, then the initial conditions are \(x(0)=A, y(0)=0\) (a) Let \(A=0.25\) and plot \(x\) versus \(t\). From the graph estimate the amplitude \(R\) and period \(T\) of the resulting motion of the pendulum. (b) Repeat part (a) for \(A=0.5,1.0,1.5,\) and \(2.0 .\) (c) How do the amplitude and period of the pendulum's motion depend on the initial position \(A^{7}\) Draw a graph to show each of these relationships. Can you say anything about the limiting value of the period as \(A \rightarrow 0 ?\) (d) Let \(A=4\) and plot \(x\) versus \(t\) Explain why this graph differs from those in parts (a) and (b). For what value of \(A\) does the transition take place?

Each of Problems I through 6 can be interpreted as describing the interaction of two species with populations \(x\) and \(y .\) In each of these problems carry out the following steps. $$ \begin{array}{l}{\text { (a) Draw a direction field and describe how solutions seem to behave. }} \\ {\text { (b) Find the critical points. }} \\ {\text { (c) For each critical point find the corresponding linear system. Find the eigenvalues and }} \\ {\text { eigenvectors of the linear system; classify each critical point as to type, and determine }} \\ {\text { whether it is asymptotically stable, stable, or unstable. }}\end{array} $$ $$ \begin{array}{l}{\text { (d) Sketch the trajectories in the neighborhood of each critical point. }} \\ {\text { (c) Compute and plot enough trajectories of the given system to show clearly the behavior of }} \\ {\text { the solutions. }} \\ {\text { (f) Determine the limiting behavior of } x \text { and } y \text { as } t \rightarrow \infty \text { and interpret the results in terms of }} \\ {\text { the populations of the two species. }}\end{array} $$ $$ \begin{array}{l}{d x / d t=x(1.5-0.5 x-y)} \\ {d y / d t=y(0.75-y-0.125 x)}\end{array} $$

(a) Find all the critical points (equilibrium solutions). (b) Use a computer to draw a direction field and portrait for the system. (c) From the plot(s) in part (b) determine whether each critical point is asymptotically stable, stable, or unstable, and classify it as to type. $$ d x / d t=(2+x)(y-x), \quad d y / d t=(4-x)(y+x) $$

Determine the periodic solutions, if any, of the system $$ \frac{d x}{d t}=y+\frac{x}{\sqrt{x^{2}+y^{2}}}\left(x^{2}+y^{2}-2\right), \quad \frac{d y}{d t}=-x+\frac{y}{\sqrt{x^{2}+y^{2}}}\left(x^{2}+y^{2}-2\right) $$

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