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Obtain a formula for the local truncation error for the Euler method in terms of \(t\) and the solution \(\phi\) $$ y^{\prime}=t^{2}+y^{2}, \quad y(0)=1 $$

Short Answer

Expert verified
The local truncation error formula for this differential equation using the Euler method is given by: \(T = \frac{h^2}{2} (2t + 2y(t^2 + y^2))\), where \(T\) represents the local truncation error, \(h\) is the step size, \(t\) represents the time variable, and \(y\) is the approximate solution at time \(t\).

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01

Understand the Euler method

Euler's method is a numerical method used to approximate the solution of an ordinary differential equation (ODE) with a given initial value. For a given ODE in the form of $$ \frac{dy}{dt} = f(t, y), $$ Euler's method approximates the solution by iteratively updating the function value as $$ y_{n+1} = y_n + h f(t_n, y_n), $$ where \(h\) is the step size, and \((t_n, y_n)\) are the values of \(t\) and \(y\) at the \(n^{th}\) step.
02

Express the given equation in the form for Euler's Method

For our given ODE $$ y^{\prime} = t^{2} + y^{2}, \quad y(0) = 1, $$ we have \(f(t, y) = t^2 + y^2\).
03

Calculate the error term

The error term is the difference between the true solution \(\phi\) and the approximate solution \(y\) after one step using the Euler's method. To find it, we can first find the second derivative: $$ \frac{d^2y}{dt^2} = \frac{d}{dt}(t^2 + y^2) = 2t + 2y \frac{dy}{dt}, $$ where we plug in the first derivative for \(\frac{dy}{dt}\), getting $$ \frac{d^2y}{dt^2} = 2t + 2y(t^2 + y^2). $$
04

Obtain the local truncation error formula

The local truncation error is given by $$ T = \frac{h^2}{2!}\cdot\frac{d^2y}{dt^2}, $$ which in our case becomes, $$ T = \frac{h^2}{2} (2t + 2y(t^2 + y^2)). $$ This represents the local truncation error for the Euler method in terms of \(t\), \(y\), and the step size \(h\) for our given ODE.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Methods for ODEs
Solving an ordinary differential equation (ODE) often requires the application of numerical methods when an analytical solution is difficult or impossible to obtain. Numerical methods like the Euler method, the midpoint method, and the Runge-Kutta methods provide ways to approximate solutions to these equations.

The Euler method, one of the simplest and oldest approaches, approximates the solution of an ODE by iterating over discrete time steps. Given the general form of an ODE as \( \frac{dy}{dt} = f(t, y) \), the Euler method creates a sequence of values that start from an initial condition and advances step by step. The method relies on the linear approximation that the change in \( y \) over a small time step \( h \) can be estimated by \( h \) times the derivative value at the beginning of the step.

Despite its simplicity, the Euler method can be inaccurate if the step size \( h \) is not small enough, leading to an error known as truncation error. The local truncation error reflects the error made in a single step, whereas the global truncation error accumulates over many steps. For students to effectively use the Euler method, understanding the magnitude of this error and how it is influenced by step size is vital for achieving acceptable approximations.
Ordinary Differential Equations
Ordinary differential equations (ODEs) are equations involving functions and their derivatives. They play a central role in mathematics and its applications across engineering, physics, and other sciences. An ODE describes the relationship between a function and its derivatives, representing the rates of change within a system.

For instance, the equation \( y' = t^2 + y^2 \) from the provided exercise is an ODE where the rate of change of the function \( y \) with respect to the independent variable \( t \) depends on both \( t \) and the current value of \( y \). Such equations often arise in the modeling of dynamic systems, including population growth, heat transfer, and motion. Finding the function \( y(t) \) that satisfies the ODE and the initial condition \( y(0)=1 \) gives insight into the behavior of the system. In practice, exact solutions are not always available, which is why numerical approximation methods become necessary.

Students should strive to understand how solutions to ODEs correspond to physical processes and how various conditions affect the system's behavior, which can give context to the mathematical models they are working with.
Numerical Approximation
The concept of numerical approximation is fundamental to understanding the solutions provided by numerical methods for ODEs. This process is about finding an approximate solution to a mathematical problem that is not amenable to exact analytic solutions. The goal is to get as close as possible to the true solution within a tolerable error margin.

The Euler method, as an example of a numerical approximation method, produces a sequence of approximate solution values across the domain of the independent variable, which are determined by using the function's derivative and an arbitrary step size \( h \).

However, with each step, there is a certain amount of error introduced known as truncation error. The existence and analysis of this error is crucial for the practical application of the Euler method. By acknowledging the presence of this error, which stems from truncating an infinite process to a finite one, students can adjust their step size to balance the trade-off between computational complexity and the accuracy of their solutions. For equations like \( y' = t^2 + y^2 \) where direct integration is not straightforward, numerical approximation provides a powerful tool for estimation and analysis.

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Most popular questions from this chapter

Obtain a formula for the local truncation error for the Euler method in terms of \(t\) and the solution \(\phi\) $$ y^{\prime}=5 t-3 \sqrt{y}, \quad y(0)=2 $$

Consider the initial value problem $$ y^{\prime}=t^{2}+y^{2}, \quad y(0)=1 $$ (a) Draw a direction field for this equation. (b) Use the Runge-Kutta or other methods to find approximate values of the solution at \(t=0.8,0.9,\) and 0.95 . Choose a small enough step size so that you believe your results are accurate to at least four digits. (c) Try to extend the calculations in part (b) to obtain an accurate approximation to the solution at \(t=1\) If you encounter difficulties in doing this, explain why you think this happens. The direction field in part (a) may be helpful.

Using three terms in the Taylor series given in Eq. ( \(12)\) and taking \(h=0.1\), determine approximate values of the solution of the illustrative example \(y^{\prime}=1-t+4 y, y(0)=1\) at \(t=0.1\) and \(0.2 .\) Compare the results with those using the Euler method and with the exact values. Hint: If \(y^{\prime}=f(t, y),\) what is \(y^{\prime \prime \prime} ?\)

Consider the initial value problem $$ y^{\prime}=\cos 5 \pi t, \quad y(0)=1 $$ (a) Determine the solution \(y=\phi(t)\) and draw a graph of \(y=\phi(t)\) for \(0 \leq t \leq 1 .\) (b) Determine approximate values of \(\phi(t)\) at \(t=0.2,0.4,\) and 0.6 using the Euler method with \(h=0.2 .\) Draw a broken-line graph for the approximate solution and compare it with the graph of the exact solution. (c) Repeat the computation of part (b) for \(0 \leq t \leq 0.4,\) but take \(h=0.1 .\) (d) Show by computing the local truncation error that neither of these step sizes is sufftciently small. Determine a value of \(h\) to ensure that the local truncation error is less than 0.05 throughout the interval \(0 \leq t \leq 1 .\) That such a small value of \(h\) is required results from the fact max \(\left|\phi^{\prime \prime}(t)\right|\) is large.

To obtain some idea of the possible dangers of small errors in the initial conditions, such as those due to round-off, consider the initial value problem $$y^{\prime}=t+y-3, \quad y(0)=2$$ (a) Show that the solution is \(y=\phi_{1}(t)=2-t\) (b) Suppose that in the initial condition a mistake is made and 2.001 is used instead of \(2 .\) Determine the solution \(y=\phi_{2}(t)\) in this case, and compare the difference \(\phi_{2}(t)-\phi_{1}(t)\) at \(t=1\) and as \(t \rightarrow \infty\).

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