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If \(\mathbf{A}=\left(\begin{array}{rrr}{3} & {2} & {-1} \\ {2} & {-1} & {2} \\\ {1} & {2} & {1}\end{array}\right)\) and \(\mathbf{B}=\left(\begin{array}{rrr}{2} & {1} & {-1} \\ {-2} & {3} & {3} \\\ {1} & {0} & {2}\end{array}\right),\) verify that \(2(\mathbf{A}+\mathbf{B})=2 \mathbf{A}+2 \mathbf{B}\)

Short Answer

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Answer: Yes

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01

Understand the given matrices and equation

We have two matrices A and B: \(\mathbf{A}=\left(\begin{array}{rrr} {3} & {2} & {-1} \\ {2} & {-1} & {2} \\ {1} & {2} & {1} \end{array}\right)\) and \(\mathbf{B}=\left(\begin{array}{rrr} {2} & {1} & {-1} \\ {-2} & {3} & {3} \\ {1} & {0} & {2} \end{array}\right)\) We have to verify the following equation treating both sides as separate calculations: \(2(\mathbf{A}+\mathbf{B})=2 \mathbf{A}+2 \mathbf{B}\)
02

Calculate \(\mathbf{A}+\mathbf{B}\)

To add two matrices, we add the corresponding elements in each matrix: $\mathbf{A}+\mathbf{B}=\left(\begin{array}{rrr} {3+2} & {2+1} & {-1+(-1)} \\ {2+(-2)} & {-1+3} & {2+3} \\ {1+1} & {2+0} & {1+2} \end{array}\right) =\left(\begin{array}{rrr} {5} & {3} & {-2} \\ {0} & {2} & {5} \\ {2} & {2} & {3} \end{array}\right)$
03

Calculate \(2(\mathbf{A}+\mathbf{B})\)

To perform scalar multiplication, we multiply each element of the given matrix by the scalar value: $2(\mathbf{A}+\mathbf{B})=2\left(\begin{array}{rrr} {5} & {3} & {-2} \\ {0} & {2} & {5} \\ {2} & {2} & {3} \end{array}\right) =\left(\begin{array}{rrr} {10} & {6} & {-4} \\ {0} & {4} & {...

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Addition
Matrix addition is a fundamental concept in matrix algebra. It involves adding two matrices by summing the corresponding elements from each matrix. This is only possible when the matrices being added are of the same size, meaning they have the same number of rows and columns.
  • Each element in the resulting matrix is the sum of the elements from the two matrices in the same position.
  • For instance, if you have two matrices, \( \mathbf{A} \) and \( \mathbf{B} \) with dimensions \( m \times n \), their sum \( \mathbf{A} + \mathbf{B} \), will also be \( m \times n \).
This concept is crucial as it forms the basis for more complex matrix operations.
Scalar Multiplication
Scalar multiplication is another vital operation in linear algebra, especially in the context of matrix operations. It involves multiplying each element of a matrix by the same scalar value.

This operation is straightforward but powerful as it allows you to scale a matrix, effectively changing its values uniformly. For example, if you have a matrix \( \mathbf{C} \) and a scalar \( k \), the product \( k \mathbf{C} \) results in a new matrix where each element of \( \mathbf{C} \) is multiplied by \( k \).
  • If \( k = 2 \) and \( \mathbf{C} \) is a matrix, each element of \( \mathbf{C} \) will be doubled in \( 2\mathbf{C} \).
  • Scalar multiplication does not change the size or shape of a matrix, only its values.
This process is a building block for solving equations involving matrices and for performing other matrix operations efficiently.
Matrix Operations
Matrix operations encompass a variety of procedures that can be carried out on matrices. These operations include addition, subtraction, multiplication, and more advanced functions like finding inverses or determinants.

In the context of the exercise, we deal with addition and scalar multiplication which are relatively straightforward. However, understanding these simple operations is key to grasping more complex matrix algebra tasks.
  • Matrix multiplication involves combining two matrices to form a new matrix, observing specific rules related to the arrangement and multiplication of row and column elements.
  • The original problem showcases the use of both addition and scalar multiplication to break down and verify expressions.
Matrix operations create a framework that is essential for applications in engineering, physics, computer science, and more.
Linear Algebra
Linear algebra is a branch of mathematics focusing on vector spaces and the linear mappings between them. It uses matrices extensively to represent and solve linear systems of equations.

  • Linear algebra is foundational for many areas including computer graphics, machine learning, and optimization, where matrices play a critical role.
  • Matrices in linear algebra can be used to transform data, model relationships, and perform calculations that would be difficult or impossible by direct manual computation.
The exercise you are tackling is part of linear algebra's focus on matrix operations, emphasizing the rules that govern how matrices interact. By mastering basic operations like addition and scalar multiplication, students can easily transition to more complex concepts like eigenvectors and transformations, which are vital for higher-level applications.

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Most popular questions from this chapter

Consider the system $$ \mathbf{x}^{\prime}=\mathbf{A x}=\left(\begin{array}{rrr}{5} & {-3} & {-2} \\\ {8} & {-5} & {-2} \\ {-4} & {-5} & {-4} \\ {-4} & {3} & {3}\end{array}\right) \mathbf{x} $$ (a) Show that \(r=1\) is a triple eigenvalue of the coefficient matrix \(\mathbf{A},\) and that there are only two linearly independent eigenvectors, which we may take as $$ \xi^{(1)}=\left(\begin{array}{l}{1} \\ {0} \\ {2}\end{array}\right), \quad \xi^{(2)}=\left(\begin{array}{r}{0} \\ {2} \\ {-3}\end{array}\right) $$ Find two linearly independent solutions \(\mathbf{x}^{(1)}(t)\) and \(\mathbf{x}^{(2)}(t)\) of Eq. (i). (b) To find a third solution assume that \(\mathbf{x}=\xi t e^{t}+\mathbf{\eta} e^{\lambda} ;\) thow that \(\xi\) and \(\eta\) must satisfy $$ (\mathbf{A}-\mathbf{1}) \xi=0 $$ \((\mathbf{A}-\mathbf{I}) \mathbf{\eta}=\mathbf{\xi}\) (c) Show that \(\xi=c_{1} \xi^{(1)}+c_{2} \mathbf{\xi}^{(2)},\) where \(c_{1}\) and \(c_{2}\) are arbitrary constants, is the most general solution of Eq. (iii). Show that in order to solve Eq. (iv) it is necessary that \(c_{1}=c_{2}\) (d) It is convenient to choose \(c_{1}=c_{2}=2 .\) For this choice show that $$ \xi=\left(\begin{array}{r}{2} \\ {4} \\ {-2}\end{array}\right), \quad \mathbf{\eta}=\left(\begin{array}{r}{0} \\ {0} \\ {-1}\end{array}\right) $$ where we have dropped the multiples of \(\xi^{(1)}\) and \(\xi^{(2)}\) that appear in \(\eta\). Use the results given in Eqs. (v) to find a third linearly independent solution \(\mathbf{x}^{(3)}\) of Eq. (i). (e) Write down a fundamental matrix \(\Psi(t)\) for the system (i). (f) Form a matrix T with the cigenvector \(\xi^{(1)}\) in the first column and with the eigenvector \(\xi\) and the generalized eigenvector \(\eta\) from Eqs. (v) in the other two columns. Find \(\mathbf{T}^{-1}\) and form the product \(\mathbf{J}=\mathbf{T}^{-1} \mathbf{A} \mathbf{T}\). The matrix \(\mathbf{J}\) is the Jordan form of \(\mathbf{A} .\)

Find the solution of the given initial value problem. Draw the trajectory of the solution in the \(x_{1} x_{2}-\) plane and also the graph of \(x_{1}\) versus \(t .\) $$ \mathbf{x}^{\prime}=\left(\begin{array}{ll}{1} & {-4} \\ {4} & {-7}\end{array}\right) \mathbf{x}, \quad \mathbf{x}(0)=\left(\begin{array}{l}{3} \\ {2}\end{array}\right) $$

Show that if \(\lambda_{1}\) and \(\lambda_{2}\) are eigenvalues of a Hermitian matrix \(\mathbf{A},\) and if \(\lambda_{1} \neq \lambda_{2},\) then the corresponding eigenvectors \(\mathbf{x}^{(1)}\) and \(\mathbf{x}^{(2)}\) are orthogonal. Hint: Use the results of Problems 31 and 32 to show that \(\left(\lambda_{1}-\lambda_{2}\right)\left(\mathbf{x}^{(1)}, \mathbf{x}^{(1)}\right)=0\)

Solve the given system of equations in each of Problems 20 through 23. Assume that \(t>0 .\) $$ t \mathbf{x}^{\prime}=\left(\begin{array}{rr}{5} & {-1} \\ {3} & {1}\end{array}\right) \mathbf{x} $$

find a fundamental matrix for the given system of equations. In each case also find the fundamental matrix \(\mathbf{\Phi}(t)\) satisfying \(\Phi(0)=\mathbf{1}\) $$ \mathbf{x}^{\prime}=\left(\begin{array}{ll}{3} & {-2} \\ {2} & {-2}\end{array}\right) \mathbf{x} $$

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