Find a second solution of Bessel's equation of order one by computing the
\(c_{n}\left(r_{2}\right)\) and \(a\) of Eq. ( 24) of Section 5.7 according to the
formulas ( 19) and ( 20) of that section. Some guidelines along the way of
this calculation are the following. First, use Eq. ( 24) of this section to
show that \(a_{1}(-1)\) and \(a_{1}^{\prime}(-1)\) are 0 . Then show that
\(c_{1}(-1)=0\) and, from the recurrence relation, that \(c_{n}(-1)=0\) for
\(n=3,5, \ldots .\) Finally, use Eq. (25) to show that
$$
a_{2 m}(r)=\frac{(-1)^{m} a_{0}}{(r+1)(r+3)^{2} \cdots(r+2 m-1)^{2}(r+2 m+1)}
$$
for \(m=1,2,3, \ldots,\) and calculate
$$
c_{2 m}(-1)=(-1)^{m+1}\left(H_{m}+H_{m-1}\right) / 2^{2 m} m !(m-1) !
$$