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Find all singular points of the given equation and determine whether each one is regular or irregular. \(\left(x^{2}+x-2\right) y^{\prime \prime}+(x+1) y^{\prime}+2 y=0\)

Short Answer

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Answer: The singular points of the given equation are \(x=-2\) and \(x=1\), and both of these points are regular singular points.

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01

Find the singular points of the given equation

We are given the equation: \(\left(x^{2}+x-2\right) y^{\prime \prime}+(x+1) y^{\prime}+2 y=0\). A singular point occurs when the coefficient of the highest derivative (in this case \(y^{\prime \prime}\)) is zero. So, to find the singular points, we need to find when \(\left(x^{2}+x-2\right)=0\). We can factor the quadratic equation as follows: \((x + 2)(x - 1) = 0\) This gives us two singular points \(x = -2\) and \(x = 1\)
02

Determine if the singular points are regular or irregular

We need to check if the given equation remains a linear ODE with analytic coefficients when \(x=-2\) and \(x=1\). When \(x = -2\) and \(x = 1\), the given equation becomes: For \(x = -2\): \((-2 + 2)(-2 - 1) y^{\prime \prime}+(-2+1) y^{\prime}+2 y=0\) \(0\cdot y^{\prime\prime} - 1\cdot y^{\prime} + 2\cdot y = 0\) For \(x = 1\): \((1 + 1)(1 - 1) y^{\prime \prime}+(1+1) y^{\prime}+2 y=0\) \(0\cdot y^{\prime\prime} + 2\cdot y^{\prime} + 2\cdot y = 0\) In both cases, the given equation remains a linear ODE with analytic coefficients. Therefore, both singular points \(x=-2\) and \(x=1\) are regular singular points. #Conclusion# The singular points of the given equation are \(x=-2\) and \(x=1\), and both of these points are regular singular points.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regular Singular Points
When we delve into the study of ordinary differential equations (ODEs), the concept of singular points becomes pivotal as it provides insight into the behavior of solutions near certain values of the independent variable, typically denoted by 'x'. A singular point is a value for which the coefficient of the highest derivative becomes zero, thus potentially causing complications in finding solutions.

Now, there are two types of singular points: regular and irregular. A regular singular point is where the solutions to the differential equation have a very specific property: they can be expressed in terms of a power series expansion with possibly a logarithmic term up to a finite distance from the singular point. This predictability and structure make it possible to apply certain techniques, such as the method of Frobenius, to find the solutions.

In our case, the equation \(\left(x^{2}+x-2\right) y^{\prime \prime}+(x+1) y^{\prime}+2 y=0\) exhibits singular points at \(x = -2\) and \(x = 1\). These are determined as regular since the equation still exhibits linear behavior with analytic coefficients upon substituting these values (as outlined in the step by step solution). This implies that near these points, the solutions are less chaotic and adhere to certain well-behaved patterns.
Linear ODE with Analytic Coefficients
Linear ODEs are a class of differential equations where the unknown function and its derivatives appear to the first power and are not multiplied together. Such equations are often easier to solve and analyze due to their structure. Now, when these linear ODEs have analytic coefficients, it means the coefficients are given by convergent power series within a certain interval around a point.

Why does this matter? Because the presence of analytic coefficients suggests that we can manipulate the coefficients much like how we deal with ordinary power series – they can be differentiated and integrated term by term. This is a desirable property, particularly when dealing with singular points, as it allows for methods like power series solutions and Frobenius method to come into play for obtaining a solution.

In our textbook exercise, the condition that the linear ODE has analytic coefficients even after substituting the singular points underpins the conclusion that these singular points are regular. It's also reassuring for students, pointing to the fact that finding a solution in the vicinity of these points is not only possible but follows a structured approach.
Solving Second Order Differential Equations
Second-order differential equations, such as the one in our exercise, \(\left(x^{2}+x-2\right) y^{\prime \prime}+(x+1) y^{\prime}+2 y=0\), require us to find a function \(y\) which satisfies the relation involving \(y\), its first derivative \(y'\), and second derivative \(y''\). These equations are paramount across various scientific fields, including physics and engineering, where they often describe wave phenomena, oscillations, or forces in balance.

The approach to solving such equations varies depending on the nature of their coefficients and singular points, among other factors. There's the traditional method of finding general solutions via characteristic equations for constant coefficients, or when we've non-constant coefficients and regular singular points, employing the Frobenius method which leverages power series.

From an educational perspective, students should understand that the solutions to these equations are not always straightforward and may involve intricate patterns or series expansions. Being able to determine the type of singular points plays a crucial role in directing the method used in finding these solutions, as demonstrated in our original exercise. Additionally, grasping the concept of regularity in singular points offers a pathway to predict and manage potential complexities in the solutions.

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Most popular questions from this chapter

Find all the regular singular points of the given differential equation. Determine the indicial equation and the exponents at the singularity for each regular singular point. \((x+1)^{2} y^{\prime \prime}+3\left(x^{2}-1\right) y^{\prime}+3 y=0\)

First Order Equations. The series methods discussed in this section are directly applicable to the first order linear differential equation \(P(x) y^{\prime}+Q(x) y=0\) at a point \(x_{0}\), if the function \(p=Q / P\) has a Taylor series expansion about that point. Such a point is called an ordinary point, and further, the radius of convergence of the series \(y=\sum_{n=0}^{\infty} a_{n}\left(x-x_{0}\right)^{n}\) is at least as large as the radius of convergence of the series for \(Q / P .\) In each of Problems 16 through 21 solve the given differential equation by a series in powers of \(x\) and verify that \(a_{0}\) is arbitrary in each case. Problems 20 and 21 involve nonhomogeneous differential equations to which series methods can be easily extended. Where possible, compare the series solution with the solution obtained by using the methods of Chapter 2 . $$ y^{\prime}=e^{x^{2}} y, \quad \text { three terms only } $$

Find all values of \(\alpha\) for which all solutions of \(x^{2} y^{\prime \prime}+\alpha x y^{\prime}+(5 / 2) y=0\) approach zero as \(x \rightarrow 0\).

Determine the general solution of the given differential equation that is valid in any interval not including the singular point. \(x^{2} y^{\prime \prime}-5 x y^{\prime}+9 y=0\)

Show that the given differential equation has a regular singular point at \(x=0 .\) Determine the indicial equation, the recurrence relation, and the roots of the indicial equation. Find the series solution \((x>0)\) corresponding to the larger root. If the roots are unequal and do not differ by an integer, find the series solution corresponding to the smaller root also. \(x y^{\prime \prime}+(1-x) y^{\prime}-y=0\)

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