Chapter 4: Problem 4
Express the given complex number in the form \(R(\cos \theta+\) \(i \sin \theta)=R e^{i \theta}\) $$ -i $$
Short Answer
Expert verified
Answer: The polar and exponential form for the complex number -i is 1e^(i(3π/2)).
Step by step solution
01
Find the magnitude (R)
Using the polar representation of complex numbers, R is the magnitude of the complex number. For the complex number, which is given as \(-i\), we can write it as \(0-1i.\) Now, use the formula \(R=\sqrt{a^2+b^2}\) where a is the real part, and b is the imaginary part.
In our case, a = 0 and b = -1.
So, $$R=\sqrt{(0)^2+(-1)^2} = \sqrt{0+1} = \sqrt{1} =1.$$
02
Find the angle (θ)
To find the angle (θ), we can use the formula \(\theta=\tan^{-1}\frac{b}{a}\), where a is the real part and b is the imaginary part. Keep in mind that we need to consider which quadrant the complex number lies in. Since our complex number is \(-i\), it is in the third quadrant (negative real axis and negative imaginary axis).
In our case, a = 0 and b = -1.
So, $$\theta=\tan^{-1}\frac{-1}{0}.$$
Since the division by zero is undefined and we know that the complex number is on the negative imaginary axis, we can determine that $$\theta=\frac{3\pi}{2}$$ using the knowledge of the coordinates system and trigonometry.
03
Write the complex number in the desired form
Now that we have the magnitude (R) and the angle (θ), we can write the complex number in the required form:
$$R(\cos\theta+\( \)i\sin\theta)=R e^{i\theta}.$$
For our case, R = 1 and θ = \(\frac{3\pi}{2}\).
So, $$1(\cos\frac{3\pi}{2} + i\sin\frac{3\pi}{2}) = 1e^{i\frac{3\pi}{2}}.$$
Thus, the desired form for the complex number \(-i\) is:
$$-i = 1e^{i\frac{3\pi}{2}}.$$
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Representation
Complex numbers can be understood more intuitively using polar representation, especially when dealing with multiplication, division, and roots. Polar representation expresses a complex number in terms of its magnitude and angle from the positive real axis.
A complex number like \(-i\) can be expressed as \(R (\cos \theta + i \sin \theta) = R e^{i \theta}\), where:
A complex number like \(-i\) can be expressed as \(R (\cos \theta + i \sin \theta) = R e^{i \theta}\), where:
- \(R\) is the magnitude of the complex number (think of it as the distance from the origin to the point in the complex plane).
- \(\theta\) is the angle, measured in radians, from the positive real axis to the line connecting the origin and the point representing the complex number.
Magnitude of Complex Number
The magnitude of a complex number represents its absolute value or "size" in the complex plane. It is symbolized by \(R\) and calculated using the Pythagorean theorem.
For a complex number represented as \(a + bi\), the formula for magnitude is:
For a complex number represented as \(a + bi\), the formula for magnitude is:
- \(R = \sqrt{a^2 + b^2}\)
- \(R = \sqrt{0^2 + (-1)^2} = \sqrt{0 + 1} = \sqrt{1} = 1\)
Angle of Complex Number
The angle of a complex number, often denoted as \(\theta\), describes its direction in the complex plane relative to the positive real axis. It is typically determined using the inverse tangent function, \(\tan^{-1}\), sometimes producing undefined results when the real part is zero.
For \(-i\), we have the real part \(a = 0\) and imaginary part \(b = -1\). Usually, \(\theta\) would be computed using:
Thus, knowing the geometry and using trigonometry, we determine:
For \(-i\), we have the real part \(a = 0\) and imaginary part \(b = -1\). Usually, \(\theta\) would be computed using:
- \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\)
Thus, knowing the geometry and using trigonometry, we determine:
- \(\theta = \frac{3\pi}{2}\) radians