Chapter 4: Problem 4
Express the given complex number in the form \(R(\cos \theta+\) \(i \sin \theta)=R e^{i \theta}\) $$ -i $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Representation
A complex number like \(-i\) can be expressed as \(R (\cos \theta + i \sin \theta) = R e^{i \theta}\), where:
- \(R\) is the magnitude of the complex number (think of it as the distance from the origin to the point in the complex plane).
- \(\theta\) is the angle, measured in radians, from the positive real axis to the line connecting the origin and the point representing the complex number.
Magnitude of Complex Number
For a complex number represented as \(a + bi\), the formula for magnitude is:
- \(R = \sqrt{a^2 + b^2}\)
- \(R = \sqrt{0^2 + (-1)^2} = \sqrt{0 + 1} = \sqrt{1} = 1\)
Angle of Complex Number
For \(-i\), we have the real part \(a = 0\) and imaginary part \(b = -1\). Usually, \(\theta\) would be computed using:
- \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\)
Thus, knowing the geometry and using trigonometry, we determine:
- \(\theta = \frac{3\pi}{2}\) radians