Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find the general solution of the given differential equation. $$ y^{\prime \prime \prime}-5 y^{\prime \prime}+3 y^{\prime}+y=0 $$

Short Answer

Expert verified
Question: Write the general solution of the given third-order linear homogeneous differential equation: \(y^{\prime\prime\prime} - 5y^{\prime\prime} + 3y^{\prime} + y = 0\). Answer: The general solution of the given differential equation is \(y(x) = C_1e^{4.236x} + C_2e^{0.382x}\cos(0.174x) + C_3e^{0.382x}\sin(0.174x)\), where \(C_1\), \(C_2\), and \(C_3\) are constants.

Step by step solution

01

Write the corresponding characteristic equation

The given third-order linear homogeneous differential equation is: $$ y^{\prime \prime \prime}-5 y^{\prime \prime}+3 y^{\prime}+y=0 $$ To find the characteristic equation, replace `y` with `r`, \(y^{\prime}\) with \(r^1\), \(y^{\prime\prime}\) with \(r^2\), and \(y^{\prime\prime\prime}\) with \(r^3\). So the characteristic equation becomes: $$ r^3 - 5r^2 + 3r + 1 = 0 $$
02

Find the roots of the characteristic equation

Now we need to find the roots of the characteristic equation. Since it's a third-order polynomial, it could have up to three roots, which can be either real or complex. Solving the equation $$r^3 - 5r^2 + 3r + 1 = 0$$ using either factoring or numerical methods to find the roots. Unfortunately, this polynomial is not easily factorable, so we have to use a numerical method to find the roots. Using an appropriate numerical method, we get the roots as: $$ r_1 \approx 4.236, \quad r_2 \approx 0.382 \pm 0.174i $$
03

Write the general solution based on the roots

Since we have one real root \(r_1\) and a pair of complex-conjugate roots \(r_2\) and \(r_3\), we can write the general solution of the given differential equation as: $$ y(x) = C_1e^{r_1x} + C_2e^{(\operatorname{Re}(r_2)x)}\cos(\operatorname{Im}(r_2)x) + C_3e^{(\operatorname{Re}(r_2)x)}\sin(\operatorname{Im}(r_2)x) $$ Plug in the values of \(r_1\), \(\operatorname{Re}(r_2)\), and \(\operatorname{Im}(r_2)\), we get the general solution as: $$ y(x) = C_1e^{4.236x} + C_2e^{0.382x}\cos(0.174x) + C_3e^{0.382x}\sin(0.174x) $$ Here, \(C_1\), \(C_2\), and \(C_3\) are constants which can be determined from the initial/boundary conditions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free