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If the Wronskian \(W\) of \(f\) and \(g\) is \(3 e^{4 t}\), and if \(f(t)=e^{2 t},\) find \(g(t)\)

Short Answer

Expert verified
Question: Determine the function g(t) given that the Wronskian W of the functions f(t) and g(t) is 3e^(4t) and the function f(t) is e^(2t). Answer: g(t) = 3te^(2t) + Ce^(2t), where C is an arbitrary constant.

Step by step solution

01

Write down the given information

We are given the following: - Wronskian, \(W = 3e^{4t}\) - Function \(f(t) = e^{2t}\) Our task is to find the function \(g(t)\).
02

Compute the derivative of \(f(t)\)

In order to use the Wronskian formula, we need to find the derivative of \(f(t)\). Differentiating \(f(t) = e^{2t}\) with respect to \(t\), we get: \(f'(t) = 2e^{2t}\)
03

Write down the Wronskian formula and substitute the given information

We know that the Wronskian is given by the formula: \(W(f,g) = fg' - f'g\) Substitute the given information into the formula: \(3e^{4t} = (e^{2t})(g'(t)) - (2e^{2t})(g(t))\)
04

Solve the differential equation for \(g(t)\)

Now, we need to solve the differential equation for \(g(t)\). This is a first-order linear inhomogeneous differential equation. Let's first divide through by \(e^{2t}\): \(\frac{3e^{4t}}{e^{2t}}=g'(t)-2g(t)\) Simplify the equation: \(3e^{2t}=g'(t)-2g(t)\) Let's write it in the form of a first-order linear differential equation: \(g'(t) - 2g(t) = 3e^{2t}\)
05

Use the integrating factor method to solve the differential equation

We can solve this differential equation using the integrating factor method. First, we calculate the integrating factor (\(IF\)): \(IF = e^{\int -2dt} = e^{-2t}\) Now, multiply both sides of the differential equation by the integrating factor: \(e^{-2t}g'(t) - 2e^{-2t}g(t) = 3e^{2t}e^{-2t}\) This simplifies to: \((e^{-2t}g(t))' = 3\) Now, integrate both sides with respect to \(t\): \(\int(e^{-2t}g(t))' dt = \int 3 dt\) This gives: \(e^{-2t}g(t) = 3t + C\) Now, multiply both sides by the integrating factor's inverse, which is \(e^{2t}\): \(g(t) = 3te^{2t} + Ce^{2t}\) Here, \(g(t)\) is the function we were looking for, and \(C\) is an arbitrary constant.

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Most popular questions from this chapter

In the spring-mass system of Problem \(31,\) suppose that the spring force is not given by Hooke's law but instead satisfies the relation $$ F_{s}=-\left(k u+\epsilon u^{3}\right) $$ where \(k>0\) and \(\epsilon\) is small but may be of either sign. The spring is called a hardening spring if \(\epsilon>0\) and a softening spring if \(\epsilon<0 .\) Why are these terms appropriate? (a) Show that the displacement \(u(t)\) of the mass from its equilibrium position satisfies the differential equation $$ m u^{\prime \prime}+\gamma u^{\prime}+k u+\epsilon u^{3}=0 $$ Suppose that the initial conditions are $$ u(0)=0, \quad u^{\prime}(0)=1 $$ In the remainder of this problem assume that \(m=1, k=1,\) and \(\gamma=0\). (b) Find \(u(t)\) when \(\epsilon=0\) and also determine the amplitude and period of the motion. (c) Let \(\epsilon=0.1 .\) Plot (a numerical approximation to) the solution. Does the motion appear to be periodic? Estimate the amplitude and period. (d) Repeat part (c) for \(\epsilon=0.2\) and \(\epsilon=0.3\) (e) Plot your estimated values of the amplitude \(A\) and the period \(T\) versus \(\epsilon\). Describe the way in which \(A\) and \(T\), respectively, depend on \(\epsilon\). (f) Repeat parts (c), (d), and (e) for negative values of \(\epsilon .\)

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