Chapter 3: Problem 15
Find the solution of the initial value problem
$$
u^{\prime \prime}+u=F(t), \quad u(0)=0, \quad u^{\prime}(0)=0
$$
where
$$
F(t)=\left\\{\begin{array}{ll}{F_{0}(2 \pi-t),} & {0 \leq t \leq \pi} \\ {-0}
& {(2 \pi-t),} & {\pi
Short Answer
Expert verified
Question: Find the solution u(t) of the initial value problem for a second-order linear differential equation with a piecewise function F(t) given by,
$$u^{\prime \prime}(t) + u(t) = F(t)$$
with,
$$F(t)=\begin{cases}
F_{0}(2 \pi - t), & 0 \leq t \leq \pi\\
-F_{0}(2 \pi - t), & \pi< t \leq 2 \pi\\
0, & 2\pi < t
\end{cases}$$
and initial conditions \(u(0)=0\) and \(u'(0)=0\).
Step by step solution
01
Identify the intervals of F(t)
F(t) is defined as a piecewise function on three intervals:
1. \(0 \leq t \leq \pi\) : \(F(t)=F_{0}(2 \pi - t)\)
2. \(\pi< t \leq 2 \pi\) : \(F(t)=-F_{0}(2 \pi - t)\)
3. \(2\pi < t\): \(F(t)=0\)
Now, we will solve the differential equation separately for each interval.
02
Solve the differential equation for the first interval
On the interval \(0 \leq t \leq \pi\), we have \(F(t) = F_0(2\pi - t)\). So, the differential equation becomes:
$$u^{\prime \prime} + u = F_0(2\pi - t)$$
To solve this equation for \(u(t)\), we can use the method of variation of parameters. We first solve for the complementary solution \(u_c(t)\). The associated homogeneous equation is:
$$u_c^{\prime \prime} + u_c = 0$$
The generic solution for the homogeneous equation is:
$$u_c(t) = C_1 \sin(t) + C_2 \cos(t)$$
Then, we need to find the particular solution, \(u_p\), such that:
$$u(t) = u_c(t) + u_p(t)$$
For the particular solution, we can guess:
$$u_p(t) = AtB$$
From there, we can find A and B by taking the second and first derivatives of \(u_p\) and substituting them into the original differential equation. Finally, we will get the general solution for the first interval.
03
Solve the differential equation for the second interval
On the interval \(\pi< t \leq 2 \pi\), we have \(F(t) = -F_0(2\pi - t)\). So, the differential equation becomes:
$$u^{\prime \prime} + u = -F_0(2\pi - t)$$
Following the same procedure as in the first interval (using variation of parameters), we can find the general solution for the second interval.
04
Solve the differential equation for the third interval
On the interval \(2\pi < t\), we have \(F(t) = 0\). So, the differential equation becomes:
$$u^{\prime \prime} + u = 0$$
This is a homogeneous equation, so the general solution can be directly found as:
$$u(t) = C_3 \sin(t) + C_4 \cos(t)$$
05
Combine the solutions and apply initial conditions
Now that we have the general solutions for each interval, we can combine them into a single solution by enforcing the continuity condition on \(u\) and \(u'\) at the breakpoints of the intervals (\(t=\pi\) and \(t=2\pi\)). This will give us a system of equations to solve for the constants in our general solutions.
Finally, we apply the initial conditions \(u(0)=0\) and \(u'(0)=0\) to completely determine the solution of the initial value problem.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
A piecewise function is a type of function that is defined by multiple sub-functions.
Each sub-function applies to a certain interval of the main function's domain. In the context of the problem at hand, we have the piecewise function \(F(t)\):
In mathematical problems like this one, it is crucial to examine each piece and determine the solution separately before combining them.
Each sub-function applies to a certain interval of the main function's domain. In the context of the problem at hand, we have the piecewise function \(F(t)\):
- For \(0 \leq t \leq \pi\), \(F(t) = F_{0}(2\pi - t)\)
- For \(\pi < t \leq 2\pi\), \(F(t) = -F_{0}(2\pi - t)\)
- For \(t > 2\pi\), \(F(t) = 0\)
In mathematical problems like this one, it is crucial to examine each piece and determine the solution separately before combining them.
Variation of Parameters
Variation of parameters is a method used to find particular solutions to non-homogeneous differential equations.
Unlike other methods, it does not require a guess for the form of the solution. Instead, it involves using known solutions to the related homogeneous equation to construct a particular solution.
When applying the variation of parameters, we use the solutions from the homogeneous equation, which in this case is \(u^{\prime \prime} + u = 0\). These solutions, \(\sin(t)\) and \(\cos(t)\), help us form the general solution:
Unlike other methods, it does not require a guess for the form of the solution. Instead, it involves using known solutions to the related homogeneous equation to construct a particular solution.
When applying the variation of parameters, we use the solutions from the homogeneous equation, which in this case is \(u^{\prime \prime} + u = 0\). These solutions, \(\sin(t)\) and \(\cos(t)\), help us form the general solution:
- The complementary solution is \(u_c(t) = C_1 \sin(t) + C_2 \cos(t)\)
- Using variation of parameters, we find a particular solution \(u_p(t)\) for our non-homogeneous equation.
Homogeneous Equation
A homogeneous equation in the context of differential equations is when the equation is set to zero (i.e., \(u^{\prime \prime} + u = 0\)).
Solving this equation is crucial because its solutions form the basis for finding particular solutions to the more complex non-homogeneous variations.
The solutions of this basic form are called the complementary solutions, \(u_c(t)\), and are typically composed of terms like \(\sin(t)\) and \(\cos(t)\). These basic trigonometric functions arise from assuming exponential forms and the characteristic equation.
Solving this equation is crucial because its solutions form the basis for finding particular solutions to the more complex non-homogeneous variations.
The solutions of this basic form are called the complementary solutions, \(u_c(t)\), and are typically composed of terms like \(\sin(t)\) and \(\cos(t)\). These basic trigonometric functions arise from assuming exponential forms and the characteristic equation.
- The homogeneous equation gives the foundation onto which particular solutions due to external forces, like in \(F(t)\), are added.
- These form the basis for creating the variation of parameters technique.
Continuity Conditions
Continuity conditions ensure a smooth transition for piecewise solutions. This means both the function \(u(t)\) and its derivative \(u'(t)\) must not exhibit abrupt changes at the breakpoints (such as \(t = \pi\) and \(t = 2\pi\)). This is crucial for a function that mimics real-world scenarios where abrupt or non-smooth solutions do not realistically represent physical phenomena.
- Ensuring continuity means that at each breakpoint, the left-hand limit equals the right-hand limit for both \(u(t)\) and \(u'(t)\).
- These conditions can be understood as boundary conditions specific to transitions between intervals.
- Checking continuity imposes additional equations on the constants derived from the piecewise solutions, helping complete the overall solution.