Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The Wronskian of two functions is \(W(t)=t^{2}-4 .\) Are the functions linearly independent or linearly dependent? Why?

Short Answer

Expert verified
Answer: The functions are linearly independent.

Step by step solution

01

Check if the Wronskian is non-zero for any value of t.

We are given the Wronskian W(t) = t^2 - 4. To check if this is non-zero for any value of t, we can try to find the roots (if any) of the equation t^2 - 4 = 0.
02

Solve the equation t^2 - 4 = 0 for t.

To find the roots, we can use the quadratic formula or factoring. In this case, factoring is easier since this is a simple equation: t^2 - 4 = (t - 2)(t + 2) The equation has two roots, t = 2 and t = -2.
03

Determine if the Wronskian is non-zero for any value of t.

We found that the Wronskian has two roots, t = 2 and t = -2. This means that the Wronskian is zero at these points. However, for any other value of t, the Wronskian will be non-zero (for example, for t = 0, W(0) = 0^2 - 4 = -4).
04

Determine if the functions are linearly independent or dependent.

Since the Wronskian is non-zero for at least one point in its domain (t = 0), the functions are linearly independent. So, we conclude that the functions are linearly independent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

linear independence
Linear independence is a concept that helps determine whether a set of functions or vectors are dependent on each other. Imagine you have a set of functions; they are linearly independent if none of them can be expressed as a combination of the others. In other words, no function in the set can be "made" using the others.
When dealing with the Wronskian, it serves as a handy tool for checking linear independence in the context of differential equations.
  • If the Wronskian is non-zero for any point in the domain, the functions are linearly independent.
  • If the Wronskian is zero everywhere, the functions can potentially be linearly dependent.
In the given exercise, the Wronskian was non-zero at points like \(t = 0\), indicating that the functions are indeed linearly independent.
differential equations
Differential equations involve unknown functions and their derivatives. They are equations that describe how functions change and are pivotal in modeling real-world phenomena.
The Wronskian pops up often when discussing differential equations, especially when determining the relationship between solutions.
  • Solutions to differential equations can be expressed as a linear combination of functions.
  • The Wronskian helps check if these solutions are linearly independent—important for understanding the behavior of solutions over time.
For instance, in our exercise, the Wronskian of two solutions being non-zero at least somewhere ensures these solutions are linearly independent, an important criterion in solving linear differential equations.
roots of equations
Finding the roots of an equation means solving for the values that make the equation equal to zero. For a quadratic equation, like in the exercise \(t^2 - 4 = 0\), this involves finding the values of \(t\) that satisfy the equation.
There are multiple ways to find roots:
  • Factoring: breaking down the equation, as seen with \((t - 2)(t + 2) = 0\), yielding roots \(t = 2\) and \(t = -2\).
  • Quadratic Formula: another reliable method, especially for more complex quadratics.
Knowing where the roots of the Wronskian are is crucial, as these points can hint at whether functions related to it are linearly dependent, which helps in understanding the nature of solutions to differential equations further. In the exercise, identifying the roots showed where the Wronskian becomes zero, helping deduce the linear independence of the functions involved.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the vibrating system described by the initial value problem $$ u^{\prime \prime}+u=3 \cos \omega t, \quad u(0)=1, \quad u^{\prime}(0)=1 $$ (a) Find the solution for \(\omega \neq 1\). (b) Plot the solution \(u(t)\) versus \(t\) for \(\omega=0.7, \omega=0.8,\) and \(\omega=0.9 .\) Compare the results with those of Problem \(18,\) that is, describe the effect of the nonzero initial conditions.

In each of Problems 13 through 18 find the solution of the given initial value problem. $$ y^{\prime \prime}+y^{\prime}-2 y=2 t, \quad y(0)=0, \quad y^{\prime}(0)=1 $$

A series circuit has a capacitor of \(0.25 \times 10^{-6}\) farad, a resistor of \(5 \times 10^{3}\) ohms, and an inductor of 1 henry. The initial charge on the capacitor is zero. If a 12 -volt battery is connected to the circuit and the circuit is closed at \(t=0,\) determine the charge on the capacitor at \(t=0.001 \mathrm{sec},\) at \(t=0.01 \mathrm{sec},\) and at any time \(t .\) Also determine the limiting charge as \(t \rightarrow \infty\)

In the absence of damping the motion of a spring-mass system satisfies the initial value problem $$ m u^{\prime \prime}+k u=0, \quad u(0)=a, \quad u^{\prime}(0)=b $$ (a) Show that the kinetic energy initially imparted to the mass is \(m b^{2} / 2\) and that the potential energy initially stored in the spring is \(k a^{2} / 2,\) so that initially the total energy in the system is \(\left(k a^{2}+m b^{2}\right) / 2\). (b) Solve the given initial value problem. (c) Using the solution in part (b), determine the total energy in the system at any time \(t .\) Your result should confirm the principle of conservation of energy for this system.

(a) Determine a suitable form for \(Y(t)\) if the method of undetermined coefficients is to be used. (b) Use a computer algebra system to find a particular solution of the given equation. $$ y^{\prime \prime}+3 y^{\prime}+2 y=e^{f}\left(t^{2}+1\right) \sin 2 t+3 e^{-t} \cos t+4 e^{t} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free