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Draw a direction field for the given differential equation and state whether you think that the solutions are converging or diverging. $$ y^{\prime}=t^{2}+y^{2} $$

Short Answer

Expert verified
Answer: To draw the direction field and analyze the behavior of the solutions, follow these steps: 1. Determine the slope at each lattice point by plugging the values of t and y in the given differential equation: $$ y' = t^2 + y^2 $$ 2. Draw a grid with horizontal axis representing time t and vertical axis representing the dependent variable y. Place many evenly spaced lattice points on this grid. 3. Place a vector-headed arrow at each lattice point, with its slope determined in step 1. The length of the arrow should be relatively short, as it represents a small time interval. 4. Study the overall behavior of the arrows in the grid. If the arrows are converging, then the solutions are converging. If the arrows are diverging, then the solutions are diverging. 5. After drawing the direction field, analyze the arrows and determine if the solutions are converging or diverging based on the behavior of the arrows on the grid.

Step by step solution

01

Determine the slope at each lattice point

To draw the direction field, start by determining the slope at each lattice point (t, y) by plugging the values of t and y in the given differential equation: $$ y' = t^2 + y^2 $$
02

Draw lattice points in the grid

Draw a grid with horizontal axis representing time t and vertical axis representing the dependent variable y. Place many evenly spaced lattice points on this grid.
03

Place arrows at each lattice point

Place a vector-headed arrow at each lattice point, with its slope determined in step 1. The length of the arrow should be relatively short, as it represents a small time interval.
04

Observe the overall behavior of the arrows

Study the overall behavior of the arrows in the grid. If the arrows are converging, then the solutions are converging. If the arrows are diverging, then the solutions are diverging.
05

Conclusion

After drawing the direction field, analyze the arrows and determine if the solutions are converging or diverging based on the behavior of the arrows on the grid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Differential Equations
Differential equations are mathematical equations that describe the relationship between a function and its derivatives. They play a pivotal role in modeling the rates of change in various scientific disciplines including physics, biology, and economics.

Consider a physical phenomenon governed by a differential equation such as the one presented in the exercise: \( y' = t^2 + y^2 \). This represents a relation between the rate of change of \( y \) with respect to time \( t \) and the values of \( y \) and \( t \). The power of a differential equation lies in its ability to capture the dynamic nature of change through mathematical expressions.

To delve deeper, interpreting the preliminary terms is essential. The highest derivative present, typically indicates the order of the differential equation; our example features a first-order differential equation because it involves the first derivative \( y' \). Also, the variables and their corresponding exponents can suggest the type of behavior to expect from its solutions, like steady growth, decay, oscillation, or more complex patterns. Understanding how to manipulate and solve these equations can unveil the underlying principles of the quantitative changes it describes.
Deciphering Slope Fields
A slope field, also known as a direction field, is a graphical representation of a differential equation. It consists of many small line segments or arrows, called vectors, which indicate the slope of solutions at various points in the plane.

The exercise provided illustrates how to construct a slope field for \( y' = t^2 + y^2 \). By evaluating the differential equation at multiple points \( (t, y) \), you can determine the slope at each of these points. Plotting vectors with these slopes at every selected point gives a visual cue of how solutions may behave. The vectors do not need to be long, as they represent the slope of the tangent to the solution curves only in a small vicinity around \( (t, y)\).

Methodical Construction

Creating a uniform grid allows visual consistency across the field, making it easier to see patterns. For the provided equation, step by step plotting creates a map of vector orientations, guiding us to visualize the potential solutions and their behaviors without actually solving the equation. This tool is invaluable in understanding the qualitative behavior of solutions to differential equations in various fields of study.
Assessing Solution Behavior
The behavior of solutions in the context of differential equations refers to how they evolve and change over time or space. When examining a slope field, one looks for trends that suggest either convergence or divergence of the solution curves.

Through the construction of the slope field for \( y' = t^2 + y^2 \), we infer the solution behavior. If the vectors seem to point towards each other or are getting closer as they move along the grid, this indicates converging solutions, hinting at a possible stable equilibrium or attractor within the system. Conversely, if they are moving apart, they suggest diverging solutions, which can imply instability or repelling nature in the system dynamics.

Final Observation

The last step involves analyzing the direction of the vectors. In the case of \( y' = t^2 + y^2\), the vectors would point outward as both \( t^2 \) and \( y^2 \) are always non-negative, indicating all solutions to the equation diverge as time progresses. This insight can be crucial for understanding the long-term tendencies of a system, whether it be a population model or a particle's motion in a force field. It showcases the power of differential equations in predicting future states based solely on local behavior captured by the slope field.

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Most popular questions from this chapter

Show that the equations are not exact, but become exact when multiplied by the given integrating factor. Then solve the equations. $$ (x+2) \sin y d x+x \cos y d y=0, \quad \mu(x, y)=x e^{x} $$

Chemical Reactions. A second order chemical reaction involves the interaction (collision) of one molecule of a substance \(P\) with one molecule of a substance \(Q\) to produce one molecule of a new substance \(X ;\) this is denoted by \(P+Q \rightarrow X\). Suppose that \(p\) and \(q\), where \(p \neq q,\) are the initial concentrations of \(P\) and \(Q,\) respectively, and let \(x(t)\) be the concentration of \(X\) at time \(t\). Then \(p-x(t)\) and \(q-x(t)\) are the concentrations of \(P\) and \(Q\) at time \(t,\) and the rate at which the reaction occurs is given by the equation $$ d x / d t=\alpha(p-x)(q-x) $$ where \(\alpha\) is a positive constant. (a) If \(x(0)=0\), determine the limiting value of \(x(t)\) as \(t \rightarrow \infty\) without solving the differential equation. Then solve the initial value problem and find \(x(t)\) for any \(l .\) (b) If the substances \(P\) and \(Q\) are the same, then \(p=q\) and \(\mathrm{Eq}\). (i) is replaced by $$ d x / d t=\alpha(p-x)^{2} $$ If \(x(0)=0,\) determine the limiting value of \(x(t)\) as \(t \rightarrow \infty\) without solving the differential equation. Then solve the initial value problem and determine \(x(t)\) for any \(t .\)

Determine whether or not each of the equations is exact. If it is exact, find the solution. $$ \left(e^{x} \sin y-2 y \sin x\right) d x+\left(e^{x} \cos y+2 \cos x\right) d y=0 $$

Consider the initial value problem $$ y^{\prime}=3 t^{2} /\left(3 y^{2}-4\right), \quad y(1)=0 $$ (a) Use the Euler formula ( 6) with \(h=0.1\) to obtain approximate values of the solution at \(t=1.2,1.4,1.6,\) and 1.8 . (b) Repeat part (a) with \(h=0.05\). (c) Compare the results of parts (a) and (b). Note that they are reasonably close for \(t=1.2,\) \(1.4,\) and 1.6 but are quite different for \(t=1.8\). Also note (from the differential equation) that the line tangent to the solution is parallel to the \(y\) -axis when \(y=\pm 2 / \sqrt{3} \cong \pm 1.155 .\) Explain how this might cause such a difference in the calculated values.

Involve equations of the form \(d y / d t=f(y)\). In each problem sketch the graph of \(f(y)\) versus \(y,\) determine the critical (equilibrium) points, and classify each one as asymptotically stable or unstable. $$ d y / d t=y(y-1)(y-2), \quad y_{0} \geq 0 $$

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