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let \(\phi_{0}(t)=0\) and use the method of successive approximations to approximate the solution of the given initial value problem. (a) Calculate \(\phi_{1}(t), \ldots, \phi_{4}(t),\) or (if necessary) Taylor approximations to these iterates. Keep tems up to order six. (b) Plot the functions you found in part (a) and observe whether they appear to be converging. Let \(\phi_{n}(x)=x^{n}\) for \(0 \leq x \leq 1\) and show that $$ \lim _{n \rightarrow \infty} \phi_{n}(x)=\left\\{\begin{array}{ll}{0,} & {0 \leq x<1} \\ {1,} & {x=1}\end{array}\right. $$

Short Answer

Expert verified
Question: Calculate φ₁(t), φ₂(t), φ₃(t), and φ₄(t) using the method of successive approximations and confirm the given limit. Answer: All the approximations φ₁(t), φ₂(t), φ₃(t), and φ₄(t) are equal to 0. The limit $$\lim_{n \rightarrow \infty} \phi_{n}(x)=\left\\{\begin{array}{ll}{0,} & {0\leq x<1} \\\ {1,} & {x=1}\end{array}\right.$$ holds true for the given function.

Step by step solution

01

Define the function φ₀(t) and find its derivative

Given, φ₀(t) = 0. To apply the method of successive approximation, first calculate the derivative of φ₀(t), which should be straightforward: $$\frac{d\phi_{0}(t)}{dt} = \frac{d(0)}{dt} = 0$$
02

Calculate φ₁(t), φ₂(t), φ₃(t), and φ₄(t)

We'll find subsequent approximations by using the relationship between successive iterations: $$φ_{n+1}(t) = \int_a^t \frac{d\phi_n}{dt}(s) ds$$ Now, calculate each of the required approximations using this relationship. 1. For φ₁(t), $$ \phi_{1}(t) = \int_0^t \frac{d\phi_{0}}{dt}(s) ds = \int_0^t 0 ds = 0 $$ 2. For φ₂(t), $$ \phi_{2}(t) = \int_0^t \frac{d\phi_{1}}{dt}(s) ds = \int_0^t 0 ds = 0 $$ 3. For φ₃(t), $$ \phi_{3}(t) = \int_0^t \frac{d\phi_{2}}{dt}(s) ds = \int_0^t 0 ds = 0 $$ 4. For φ₄(t), $$ \phi_{4}(t) = \int_0^t \frac{d\phi_{3}}{dt}(s) ds = \int_0^t 0 ds = 0 $$
03

Consider the Taylor approximations

Since the approximations φ₁(t), φ₂(t), φ₃(t), and φ₄(t) are all equal to 0, there's no need to apply the Taylor approximations, as there are no terms up to order six.
04

Plot the functions

Plot the functions φ₀(t), φ₁(t), φ₂(t), φ₃(t), and φ₄(t) to observe if they appear to be converging. In this case, all the functions are equivalent to 0, thus making them the same function. Therefore, it can be said that the approximations are converging.
05

Show the limit

To show that $$\lim_{n \rightarrow \infty} \phi_{n}(x)=\left\\{\begin{array}{ll}{0,} & {0\leq x<1} \\\ {1,} & {x=1}\end{array}\right,$$ it's necessary to consider that, in this case, $$\phi_n(x) = x^n$$. So, we need to evaluate the limit as n approaches infinity for the given function: $$ \lim_{n \rightarrow \infty} x^n=\left\\{\begin{array}{ll}{0,} & {0 \leq x < 1} \\\ {1,} & {x = 1}\end{array}\right. $$ This confirms the given limit holds true for the function, as shown above.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Initial Value Problem
An initial value problem (IVP) in the realm of differential equations is a problem where you are given a differential equation along with the value of the unknown function at a specific point, referred to as the initial value. The goal is to find a function that satisfies both the differential equation and the initial condition. Many real-life phenomena, from physics to finance, can be modeled using IVPs, providing a starting point for predictions and analyses.

The method of successive approximations, also known as Picard iteration, is a technique to tackle IVPs. It involves starting with an initial guess for the function, often dictated by the problem's initial conditions, and then refining this guess iteratively. Each step of iteration involves using the prior approximation to generate a new one that is closer to the true solution. In the provided exercise, we start with \( \phi_{0}(t)=0 \) and use this method to create subsequent approximations \( \phi_{1}(t), \phi_{2}(t), \ldots \) until they converge to a solution.
Taylor Approximations Simplified
Taylor approximations are a powerful mathematical tool used to estimate the values of functions. By expanding a function into a series at a particular point, Taylor approximations can give us a polynomial that represents the function's behavior near that point. It's like sketching a simple outline that captures the essence of a more complex shape.

In the context of differential equations and successive approximations, if our initial estimates for the solution are not zero—unlike in our exercise where each \( \phi_{n}(t) \) was zero—we would use Taylor approximations to refine these estimates. The idea is to take the known value of a function at a point and then add terms that incorporate the rates of change of the function at that point to better approximate the function nearby. Up to order six means we would include terms from the constant (the value at the point) up to the sixth derivative in our approximation.
Convergence of Functions: What Does it Mean?
In mathematics, the convergence of functions refers to the idea that a sequence of functions gets arbitrarily close to a given function as the sequence progresses. This is a crucial concept when discussing iterative processes like the method of successive approximations.

In our exercise, we calculate several iterations \( \phi_{1}(t), \phi_{2}(t), ... \) using the initial guess \( \phi_{0}(t) = 0 \) and observe whether the sequence is converging towards a solution to the initial value problem. This is equivalent to observing whether the functions in the sequence are becoming indistinguishable from each other as we proceed with iterations, which in our case they are, since all \( \phi_{n}(t) \) are zero. Convergence can be analyzed graphically, as requested in the exercise, or by using mathematical tests for convergence.
Differential Equations and Their Significance
Differential equations are equations that involve an unknown function and its derivatives. They are integral in modeling systems where change is continuous and can occur in various scientific fields such as physics, engineering, biology, and economics.

The initial value problem is a type of differential equation problem that includes conditions at a single point, embodying the principle that specifying the state of a system at one time can determine its future behavior. To solve a differential equation means to find all functions that satisfy the equation, with or without those initial conditions.

In the given exercise, the successive approximations method applied to solve the differential equation illustrates the power of iterative techniques in handling such problems. While this specific example resulted in a straightforward set of zero functions, more complex problems would yield a sequence of increasingly accurate approximations that approach the true solution.

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Most popular questions from this chapter

Find an integrating factor and solve the given equation. $$ \left(3 x^{2} y+2 x y+y^{3}\right) d x+\left(x^{2}+y^{2}\right) d y=0 $$

Consider the initial value problem $$ y^{\prime}=-t y+0.1 y^{3}, \quad y(0)=\alpha $$ where \(\alpha\) is a given number. (a) Draw a direction field for the differential equation (or reexamine the one from Problem 8 ) Observe that there is a critical value of \(\alpha\) in the interval \(2 \leq \alpha \leq 3\) that separates converging solutions from diverging ones. Call this critical value \(\alpha_{0}\). (b) Use Euler's method with \(h=0.01\) to estimate \(\alpha_{0} .\) Do this by restricting \(\alpha_{0}\) to an interval \([a, b],\) where \(b-a=0.01 .\)

Let \(v(t)\) and \(w(t)\) be the horizontal and vertical components of the velocity of a batted (or thrown) bascball. In the absence of air resistance, \(v\) and \(w\) satisfy the equations $$ d v / d t=0, \quad d w / d t=-g $$ $$ \text { (a) Show that } $$ $$ \mathbf{v}=u \cos A, \quad w=-g t+u \sin A $$ $$ \begin{array}{l}{\text { where } u \text { is the initial speed of the ball and } A \text { is its initial angle of elevation, }} \\ {\text { (b) Let } x(t) \text { and } y(t), \text { respectively, be the horizontal and vertical coordinates of the ball at }} \\ {\text { time } t \text { . If } x(0)=0 \text { and } y(0)=h, \text { find } x(t) \text { and } y(t) \text { at any time } t} \\ {\text { (c) Let } g=32 \text { flsec', } u=125 \mathrm{ft} / \mathrm{sec}, \text { and } h=3 \mathrm{ft} \text { . Plot the trajectory of the ball for }} \\ {\text { several values of the angle } A, \text { that is, plot } x(t) \text { and } y(t) \text { parametrically. }} \\ {\text { (d) Suppose the outfield wall is at a distance } L \text { and has height } H \text { . Find a relation between }}\end{array} $$ $$ \begin{array}{l}{u \text { and } A \text { that must be satisfied if the ball is to clear the wall. }} \\ {\text { (e) Suppose that } L=350 \mathrm{ft} \text { and } H=10 \mathrm{ft} \text { . Using the relation in part (d), find (or estimate }} \\ {\text { from a plot) the range of values of } A \text { that correspond to an initial velocity of } u=110 \mathrm{ft} \text { sec. }} \\\ {\text { (f) For } L=350 \text { and } H=10 \text { find the minimum initial velocity } u \text { and the corresponding }} \\ {\text { optimal angle } A \text { for which the ball will clear the wall. }}\end{array} $$

Draw a direction field for the given differential equation and state whether you think that the solutions are converging or diverging. $$ y^{\prime}=(4-t y) /\left(1+y^{2}\right) $$

Consider the initial value problem $$ y^{\prime}=t^{2}+y^{2}, \quad y(0)=1 $$ Use Euler's method with \(h=0.1,0.05,0.025,\) and 0.01 to explore the solution of this problem for \(0 \leq t \leq 1 .\) What is your best estimate of the value of the solution at \(t=0.8 ?\) At \(t=1 ?\) Are your results consistent with the direction field in Problem \(9 ?\)

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