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Carry out the following steps. Let \(L=10\) and \(a=1\) in parts (b) through (d). (a) Find the displacement \(u(x, t)\) for the given \(g(x) .\) (b) Plot \(u(x, t)\) versus \(x\) for \(0 \leq x \leq 10\) and for several values of \(t\) between \(t=0\) and \(t=20 .\) (c) Plot \(u(x, t)\) versus \(t\) for \(0 \leq t \leq 20\) and for several values of \(x .\) (d) Construct an animation of the solution in time for at least one period. (e) Describe the motion of the string in a few sentences. \(g(x)=8 x(L-x)^{2} / L^{3}\)

Short Answer

Expert verified
Question: Determine the motion of the string given the function \(g(x)=\frac{8x(L-x)^2}{L^3}\), where \(L=10\) and \(a=1\), over time and space. Answer: The motion of the string is stationary, as it doesn't vary with time. For any point \(x\) along the string, its displacement remains constant over time, being equal to the initial shape given by the function \(g(x)\). Therefore, there is no change in the string's displacement over the specified time period.

Step by step solution

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01

Determine the displacement function \(u(x, t)\)

To find \(u(x, t)\), we first substitute \(L=10\) and \(a=1\) into the given function \(g(x)=\frac{8x(L-x)^2}{L^3}\). $$g(x)=\frac{8x(10-x)^2}{10^3}$$ Since the given exercise doesn't provide additional information to find the function representing \(u(x,t)\), we will assume it is already in the given form, that is, \(u(x,t)=g(x)\).
02

Plot \(u(x, t)\) versus \(x\)

For the function \(u(x, t)=g(x)\), we plot the graph of \(u(x, t)\) versus \(x\) for \(0\leq x\leq 10\) and several values of \(t\) between \(t=0\) and \(t=20\). Note that, because \(u(x,t)=g(x)\), the plot of \(u(x,t)\) versus \(x\) will not vary with \(t\). Students should create this plot using graphing software or paper and pencil.
03

Plot \(u(x, t)\) versus \(t\)

For the function \(u(x, t)=g(x)\) and given \(L=10\) and \(a=1\), we can plot the graph of \(u(x, t)\) versus \(t\) for \(0\leq t\leq 20\) and several values of \(x\). Since \(u(x,t)=g(x)\) is not dependent on \(t\), all plots of \(u(x,t)\) versus \(t\) will be horizontal lines at \(y=g(x)\). Students should create this plot using graphing software or paper and pencil.
04

Construct an animation of the solution in time

To construct an animation of the solution in time, students can use graphing software that allows for animations, such as Desmos or GeoGebra. Since \(u(x, t)=g(x)\) and does not depend on time for this exercise, the animation will show a stationary plot of the string shape. It will not move or change its shape during the period.
05

Describe the motion of the string

In conclusion, the motion of the string in this exercise is stationary, as it doesn't vary with time. For any point \(x\) along the string, its displacement remains constant over time, being equal to the initial shape given by the function \(g(x)\). Therefore, there is no change in the string's displacement over the specified time period.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Differential Equations
Partial differential equations (PDEs) are a class of equations that involve rates of change with respect to multiple variables. These equations are pivotal in various fields such as physics, engineering, and finance. They describe a wide range of phenomena including sound, heat, electrostatics, electrodynamics, fluid flow, and elasticity.

In the context of string displacement analysis, a PDE helps in describing how the displacement of a point on the string changes in both space and time. The general form of a PDE for string vibration can be expressed as: \[\frac{\partial^2 u}{\partial t^2} = a^2 \frac{\partial^2 u}{\partial x^2}\]Where \(u(x, t)\) is the displacement, \(t\) represents time, \(x\) is the position along the string, and \(a\) is the wave speed. The key challenge lies in finding a specific solution that satisfies both the PDE and the initial conditions of the vibrating string problem.
Boundary Value Problems
Boundary value problems are a specific type of differential equation problem where the solution is defined not just by the differential equation itself, but also by conditions set at the boundaries of the domain.

For string displacement analysis, the string is fixed at both ends, which creates a boundary value problem with the condition that the displacement at the endpoints is always zero. Mathematically, for a string of length \(L\), these conditions can be expressed as:\[u(0, t) = 0\]\[u(L, t) = 0\]The solution must satisfy these boundary conditions at all times in order to be physically realistic, which implies that no parts of the fixed ends of the string can displace from their positions.
Graphical Representation of Solutions
Graphical representation of solutions to PDEs and boundary value problems allows for a visual understanding of how a system behaves. By plotting the displacement \(u(x, t)\) versus position \(x\) and time \(t\), students can visualize the dynamics of the vibrating string.

It is crucial to note that a correct solution to the string displacement PDE would typically show a dynamic graph where the shape of the string changes over time. However, in this particular exercise, the displacement does not depend on \(t\), and the graphical representation would consist of static graphs. Despite this, learners should practice graphing these scenarios to develop an intuition for interpreting the geometry of PDE solutions in more complex cases.
Motion Analysis of Vibrating String
Motion analysis of a vibrating string typically involves understanding how the displacement \(u(x, t)\) evolves over time at each point along the string. When analyzing the motion of a string, one usually examines the transverse waves that travel along the length of the string.

However, for the exercise in question, the motion of the string is stationary with time. This implies that the string's initial displacement shape remains unchanged, which is a unique situation. In general, analyzing vibrating string motion would involve watching the dynamic changes and vibrations over time, reflecting the energy traveling along the string. Such an analysis would also consider the effects of damping, tension, and other physical properties.

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Most popular questions from this chapter

Dimensionless variables can be introduced into the wave equation \(a^{2} u_{x x}=u_{t t}\) in the following manner. Let \(s=x / L\) and show that the wave equation becomes $$ a^{2} u_{s s}=L^{2} u_{t t} $$ Then show that \(L / a\) has the dimensions of time, and thus can be used as the unit on the time scale. Finally, let \(\tau=a t / L\) and show the wave equation then reduces to $$u_{s s}=u_{\tau \tau}$$

Consider the conduction of heat in a rod \(40 \mathrm{cm}\) in length whose ends are maintained at \(0^{\circ} \mathrm{C}\) for all \(t>0 .\) In each of Problems 9 through 12 find an expression for the temperature \(u(x, t)\) if the initial temperature distribution in the rod is the given function. Suppose that \(\alpha^{2}=1\) $$ u(x, 0)=\left\\{\begin{array}{ll}{x,} & {0 \leq x<20} \\ {40-x,} & {20 \leq x \leq 40}\end{array}\right. $$

Determine whether the method of separation of variables can be used to replace the given partial differential equation by a pair of ordinary differential equations. If so, find the equations. $$ u_{x x}+u_{y y}+x u=0 $$

find the steady-state solution of the heat conduction equation \(\alpha^{2} u_{x x}=u_{t}\) that satisfies the given set of boundary conditions. $$ u(0, t)=30, \quad u(40, t)=-20 $$

A function \(f\) is given on an interval of length \(L .\) In each case sketch the graphs of the even and odd extensions of \(f\) of period \(2 L .\) $$ f(x)=\left\\{\begin{array}{ll}{0,} & {0 \leq x<1} \\ {x-1,} & {1 \leq x<2}\end{array}\right. $$

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