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Determine whether the method of separation of variables can be used to replace the given partial differential equation by a pair of ordinary differential equations. If so, find the equations. $$ \left[p(x) u_{x}\right]_{x}-r(x) u_{t t}=0 $$

Short Answer

Expert verified
If so, find the ordinary differential equations resulting from the separation of variables. Answer: Yes, the method of separation of variables can be applied to the given partial differential equation. The resulting ordinary differential equations are: $$ p(x)X''(x) + p'(x)X'(x) = \lambda X(x) $$ and $$ r(x)T''(t) = \lambda T(t) $$

Step by step solution

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01

Substitute the Separation of Variables assumption

Using the assumption \(u(x, t) = X(x)T(t)\), compute the required derivatives: - \(u_x = X'(x)T(t)\) - \(u_{xx} = X''(x)T(t)\) - \(u_{tt} = X(x)T''(t)\) Substitute these expressions back into the given PDE: $$ [p(x)X'(x)T(t)]_x - r(x)X(x)T''(t) = 0 $$
02

Differentiate the Expression

Now, differentiate the term inside the brackets with respect to \(x\): $$ [p(x)X'(x)]_x = p'(x)X'(x) + p(x)X''(x) $$ Substitute this back into our PDE to obtain: $$ [p'(x)X'(x)T(t) + p(x)X''(x)T(t)] - r(x)X(x)T''(t) = 0 $$
03

Separate the Functions

Now, divide the equation by \(X(x)T(t)\): $$ \frac{p'(x)X'(x)}{X(x)} + \frac{p(x)X''(x)}{X(x)} - \frac{r(x)T''(t)}{T(t)} = 0 $$
04

Create the Ordinary Differential Equations

Observe that the terms on the left-hand side depend only on \(x\) and the term on the right-hand side depends only on \(t\). For the equation to hold true for all \(x\) and \(t\), both of these terms must be constant. Let's call this constant \(-\lambda\). Since both expressions are negative, we obtain the following ODEs: $$ \frac{p'(x)X'(x)}{X(x)} + \frac{p(x)X''(x)}{X(x)} = \lambda $$ and $$ \frac{r(x)T''(t)}{T(t)} = \lambda $$ Rearranging, we have the resulting ODEs: $$ p(x)X''(x) + p'(x)X'(x) = \lambda X(x) $$ and $$ r(x)T''(t) = \lambda T(t) $$ Thus, by using the separation of variables, we have replaced the given PDE with a pair of ODEs.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Differential Equations
Partial differential equations (PDEs) represent a class of equations used to describe a wide array of phenomena, such as sound, heat, electrostatics, electrodynamics, fluid flow, and many others. In essence, PDEs involve functions of multiple variables and their partial derivatives.

When we refer to a PDE, we're dealing with an equation that contains partial derivatives—derivatives with respect to one variable while holding the others constant. The PDE from our exercise, \[ \left[p(x) u_{x}\right]_{x}-r(x) u_{t t}=0 \], is an example. It tells us that a certain combination of the partial derivatives of a function, in this case, \( u(x, t) \), and the function itself, along with the functions \( p(x) \) and \( r(x) \) which may describe properties of a medium or space, results in zero.

Due to their complexity, solving PDEs is often a central challenge in applied mathematics and physics. Simplifying these equations through techniques such as separation of variables can transform PDEs into more manageable ordinary differential equations (ODEs), which offer a step towards finding a solution.
Ordinary Differential Equations
Ordinary differential equations (ODEs) are equations that relate a function to its derivatives; however, unlike PDEs, the functions in ODEs depend on a single independent variable. They serve as the cornerstone for classical mechanics, quantum mechanics, general relativity, and many other theoretical frameworks.

For a given ODE, the primary goal is often to find a function that satisfies the equation, which is known as the solution to the ODE. The process of solving involves integrating, which essentially is finding the antiderivative or the original function before differentiation occurred.

Take, for instance, the pair of ODEs we derived from the original PDE: \[ p(x)X''(x) + p'(x)X'(x) = \lambda X(x) \] and \[ r(x)T''(t) = \lambda T(t) \]. These equations are now in a form where traditional ODE-solving techniques, including characteristic equations, integrating factors, or in some cases, power series, can be applied to find explicit solutions \( X(x) \) and \( T(t) \), that are functions of a single variable \( x \) and \( t \), respectively.
Mathematical Methods for Differential Equations
Solving differential equations, be they partial or ordinary, requires a toolbox of mathematical methods. Some of the most common strategies include separation of variables, method of characteristics, integral transforms (like Fourier or Laplace transforms), and numerical methods (such as Euler's method or Runge-Kutta methods).

Separation of variables, the method we employed in the textbook exercise, is one effective strategy for solving equations where the solution can be separated into functions that each depend on only one of the variables. By carefully manipulating the equation, we can segregate the components involving different variables onto different sides of the equation, as we did when we obtained \[ \frac{p'(x)X'(x)}{X(x)} + \frac{p(x)X''(x)}{X(x)} = \lambda \] and \[ \frac{r(x)T''(t)}{T(t)} = \lambda \].

After separation, the challenge becomes solving the resultant ODEs for each variable independently. In some cases, these resulting ODEs can be standard forms for which known solutions exist, or they may require further inventive strategies to solve. For a student looking to grasp these topics, practicing these methods on various differential equations is invaluable, as it builds familiarity with the approaches and their applications to different types of problems.

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Most popular questions from this chapter

Dimensionless variables can be introduced into the wave equation \(a^{2} u_{x x}=u_{t t}\) in the following manner. Let \(s=x / L\) and show that the wave equation becomes $$ a^{2} u_{s s}=L^{2} u_{t t} $$ Then show that \(L / a\) has the dimensions of time, and thus can be used as the unit on the time scale. Finally, let \(\tau=a t / L\) and show the wave equation then reduces to $$u_{s s}=u_{\tau \tau}$$

Consider a rod of length 30 for which \(\alpha^{2}=1 .\) Suppose the initial temperature distribution is given by \(u(x, 0)=x(60-x) / 30\) and that the boundary conditions are \(u(0, t)=30\) and \(u(30, t)=0\) (a) Find the temperature in the rod as a function of position and time. (b) Plot \(u\) versus \(x\) for several values of \(t\). Also plot \(u\) versus \(t\) for several values of \(x\). (c) Plot \(u\) versus \(t\) for \(x=12\). Observe that \(u\) initially decreases, then increases for a while, and finally decreases to approach its steady-state value. Explain physically why this behavior occurs at this point.

indicate how they can be employed to solve initial value problems with periodic forcing terms. Find the formal solution of the initial value problem $$ y^{\prime \prime}+\omega^{2} y=f(t), \quad y(0)=0, \quad y^{\prime}(0)=0 $$ where \(f\) is periodic with period \(2 \pi\) and $$ f(t)=\left\\{\begin{aligned} 1, & 0

find the steady-state solution of the heat conduction equation \(\alpha^{2} u_{x x}=u_{t}\) that satisfies the given set of boundary conditions. $$ u(0, t)=30, \quad u(40, t)=-20 $$

How should \(f,\) originally defined on \([0, L],\) be extended so as to obtain a Fourier series involving only the functions \(\cos (\pi x / 2 L), \cos (3 \pi x / 2 L), \cos (5 \pi x / 2 L) \ldots .7\) Refer to Problems 38 and \(39 .\) If \(f(x)=x\) for \(0 \leq x \leq L,\) sketch the function to which the Fourier series converges for \(-4 L \leq x \leq 4 L .\)

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