Chapter 10: Problem 28
A function is given on an interval \(0
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 10: Problem 28
A function is given on an interval \(0
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeSuppose that we wish to calculate values of the function \(g,\) where $$ g(x)=\sum_{n=1}^{\infty} \frac{(2 n-1)}{1+(2 n-1)^{2}} \sin (2 n-1) \pi x $$ It is possible to show that this series converges, albeit rather slowly. However, observe that for large \(n\) the terms in the series (i) are approximately equal to \([\sin (2 n-1) \pi x] /(2 n-1)\) and that the latter terms are similar to those in the example in the text, Eq. (6). (a) Show that $$ \sum_{n=1}^{\infty}[\sin (2 n-1) \pi x] /(2 n-1)=(\pi / 2)\left[f(x)-\frac{1}{2}\right] $$ where \(f\) is the square wave in the example with \(L=1\) (b) Subtract Eq. (ii) from Eq. (i) and show that $$ g(x)=\frac{\pi}{2}\left[f(x)-\frac{1}{2}\right]-\sum_{n=1}^{\infty} \frac{\sin (2 n-1) \pi x}{(2 n-1)\left[1+(2 n-1)^{2}\right]} $$ The series (iii) converges much faster than the series (i) and thus provides a better way to calculate values of \(g(x) .\)
Consider the wave equation
$$
a^{2} u_{x x}=u_{t t}
$$
in an infinite one-dimensional medium subject to the initial conditions
$$
u(x, 0)=0, \quad u_{t}(x, 0)=g(x), \quad-\infty
Consider the wave equation
$$
a^{2} u_{x x}=u_{t t}
$$
in an infinite one-dimensional medium subject to the initial conditions
$$
u(x, 0)=0, \quad u_{t}(x, 0)=g(x), \quad-\infty
Show that the wave equation $$ a^{2} u_{x x}=u_{t t} $$ can be reduced to the form \(u_{\xi \eta}=0\) by change of variables \(\xi=x-a t, \eta=x+a t .\) Show that \(u(x, t)\) can be written as $$ u(x, t)=\phi(x-a t)+\psi(x+a t) $$ where \(\phi\) and \(\psi\) are arbitrary functions.
Consider an elastic string of length \(L .\) The end \(x=0\) is held fixed while
the end \(x=L\) is free; thus the boundary conditions are \(u(0, t)=0\) and
\(u_{x}(L, t)=0 .\) The string is set in motion with no initial velocity from
the initial position \(u(x, 0)=f(x),\) where
$$
f(x)=\left\\{\begin{array}{ll}{1,} & {L / 2-1
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