Question

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Solve:$3\sqrt{6b+3}-25=50$

Short answer

Ans:$3\sqrt{6b+3}-25=50\Rightarrow b=103.67$

Step-by-step solution

Step 1. Given information.

given expression $3\sqrt{6b+3}-25=50$

Step 2. Isolate the radical.

$$\begin{gathered} 3\sqrt{6b+3}-25=50 \\ \Rightarrow 3\sqrt{6b+3}=50+25 \\ \Rightarrow 3\sqrt{6b+3}=75 \end{gathered}$$

Step 3. Square both sides of the equation.  

$$\begin{gathered} {(3\sqrt{6b+3})}^2={\left(75\right)}^2 \\ \Rightarrow 9(6b+3)=5625 \end{gathered}$$

Step 4. Simplify, then the new equation. 

$$\begin{gathered} 9(6b+3)=5625 \\ \Rightarrow 54b+27=5625 \\ \Rightarrow b=103.67 \end{gathered}$$

Therefore, the value of$b=103.67$