Question

In the following exercises, solve.

$\sqrt{5v-2}+5=0$

Short answer

$v=5.4$.

Step-by-step solution

Step 1. Given information.

An equation is given as$\sqrt{5v-2}+5=0$.

Step 2. Solution.

Isolate radical to one side, take square and simplify.

$$\begin{gathered} \sqrt{5v-2}+5=0 \\ \sqrt{5v-2}+5-5=0-5 \\ \sqrt{5v-2}=-5 \\ {\left(\sqrt{5v-2}\right)}^2={(-5)}^{2}5v-2=25 \\ 5v-2+2=25+2 \\ 5v=27 \\ \frac{5v}{5}=\frac{27}{5} \\ v=5.4 \end{gathered}$$