Question

In the following exercises, solve.

$\sqrt{2n-1}-3=0$.

Short answer

$n=5$.

Step-by-step solution

Step 1. Given information.

To solve$\sqrt{2n-1}-3=0$.

Step 2. Solution.

Isolate radical to one side, take square and simplify.

$$\begin{gathered} \sqrt{2n-1}-3=0 \\ \sqrt{2n-1}-3+3=0+3 \\ \sqrt{2n-1}=3 \\ {\left(\sqrt{2n-1}\right)}^2=3^2 \\ 2n-1=9 \\ 2n-1+1=9+1 \\ 2n=10 \\ \frac{2n}{2}=\frac{10}{2} \\ n=5 \end{gathered}$$