Question

Subtract$\frac{3y-1}{y+4}-2$.

Short answer

The result is$\frac{y-9}{y+4}$.

Step-by-step solution

Given Information. 

The Given expression is$\frac{3y-1}{y+4}-2$.

Find the LCD of denominators.   

Since there is no denominator in second fraction.

The LCD is $(y+4)$.

Rewrite each fraction as an equivalent fraction with the LCD.     

$=\frac{3y-1}{y+4}-\frac{2(y+4)}{y+4}$

$=\frac{3y-1}{y+4}-\frac{2y+8}{y+4}$

Subtract and simplify the numerator.    

Take common denominator.

$=\frac{3y-1-(2y+8)}{y+4}$

Simplify the numerator.

$=\frac{3y-1-2y-8}{y+4}$

$=\frac{y-9}{y+4}$