Question

Subtract$\frac{5v-2}{v+3}-4$.

Short answer

The result is$\frac{v-14}{v+3}$.

Step-by-step solution

Given Information.

The Given expression is$\frac{5v-2}{v+3}-4$.

Find the LCD of denominators.    

Since there is no denominator in second fraction.

The LCD is$(v+3)$.

Rewrite each fraction as an equivalent fraction with the LCD.    

$=\frac{5v-2}{v+3}-\frac{4(v+3)}{v+3}$

Simplify numerator.

$=\frac{5v-2}{v+3}-\frac{4v+12}{v+3}$

Subtract and simplify the numerator.   

Take common denominator.

$=\frac{5v-2-(4v+12)}{v+3}$

Simplify.

$=\frac{5v-2-4v-12}{v+3}$

$=\frac{v-14}{v+3}$