Question

Add$\frac{5}{6p^{2}q}+\frac{1}{4p}$.

Short answer

The sum is$\frac{10+3pq}{12p^{2}q}$.

Step-by-step solution

Given Information

The Given expression is$\frac{5}{6p^{2}q}+\frac{1}{4p}$.

Find the LCD of denominators.

Factor the denominators.

$6p^{2}q=2·3·p·p·q$

$4p=2·2·p$

LCD$=2·3·p·p·q·2$

LCD$=12p^{2}q$

Rewrite each fraction as an equivalent fraction with the LCD.

$=\frac{5·2}{6p^{2}q·2}+\frac{1·3pq}{4p·3pq}$

$=\frac{10}{12p^{2}q}+\frac{3pq}{12p^{2}q}$

Add

Take common denominator.

$=\frac{10+3pq}{12p^{2}q}$