Question

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

$q^2-6q$

Short answer

The result is$(q-3{)}^2$.

Step-by-step solution

Given Information. 

The Given expression is$q^2-6q$.

Identify b,the coefficient of term having power one. 

$q^2-6q$

The coefficient of $q$is $-6$.

So,$b=-6$.

Find 12b2.

Substitute $b=-6$

$$\begin{gathered} ={\left(\frac{1}{2}(-6)\right)}^2 \\ ={\left(-3\right)}^2 \\ =9 \end{gathered}$$

Add 9 to binomial expression to complete the square. 

$q^2-6q+9$

Rewrite as a binomial square.

$(q-3{)}^2$.