Question

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

$p^2-22p$

Short answer

The result is$(p-11{)}^2$.

Step-by-step solution

Given Information. 

The Given expression is$p^2-22p$.

Identify b , the coefficient of term having power one. 

$p^2-22p$

The coefficient of $p$is $-22$.

Therefore,$b=-22$.

Find 12b2.

Substitute $b=-22$.

$$\begin{gathered} ={\left(\frac{1}{2}(-22)\right)}^2 \\ ={\left(-11\right)}^2 \\ =121 \end{gathered}$$

Add 121 to binomial expression to complete the square. 

$p^2-22p+121$

Rewrite as a binomial square.

$(p-11{)}^2$