Question

Solve the quadratic equation using square root property.

$(y-4{)}^2+10=9$

Short answer

The equation has no real solution.

Step-by-step solution

Given Information.    

The Given equation is$(y-4{)}^2+10=9$.

Isolate the binomial term. 

$$\begin{gathered} (y-4{)}^2=9-10 \\ (y-4{)}^2=-1 \end{gathered}$$

Use the Square Root Property.  

$y-4=\pm \sqrt{-1}$

Since $\sqrt{-1}$is not a real number.

Therefore, the equation has no real solution.