Question

Solve the quadratic equation using square root property.

$(x-6{)}^2+7=3$

Short answer

The equation has no real solution.

Step-by-step solution

Given Information.   

The Given equation is$(x-6{)}^2+7=3$.

Isolate the binomial term. 

$$\begin{gathered} (x-6{)}^2=3-7 \\ (x-6{)}^2=-4 \end{gathered}$$

Use the Square Root Property. 

$x-6=\pm \sqrt{-4}$

Since $\sqrt{-4}$is not a real number.

Therefore, the equation has no real solution.