Question

Solve the quadratic equation by quadratic formula .$4c^2+4c+1=0$

Short answer

The required result is $c=\frac{-1}{2}$

Step-by-step solution

 Given Information 

The given equation is$4c^2+4c+1=0$

Write the quadratic equation in standard form and identify a,b,c

$4c^2+4c+1=0$

So ,

$a=4,b=4,c=1$

Substitute the values in quadratic formula. 

$$\begin{gathered} x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ c=\frac{-\left(4\right)\pm \sqrt{{\left(4\right)}^2-4\left(4\right)\left(1\right)}}{2\left(4\right)} \\ c=\frac{-4\pm \sqrt{16-16}}{8} \\ c=\frac{-4\pm 0}{8} \\ c=\frac{-4}{8} \\ c=\frac{-1}{2} \end{gathered}$$