Question

Solve the quadratic equation using square root property.

$m^2-4m+4=8$

Short answer

The solutions are$m=2+2\sqrt{2},m=2-2\sqrt{2}$.

Step-by-step solution

Given Information. 

The Given equation is $m^2-4m+4=8$.

Factor the trinomial.  

$$\begin{gathered} m^2-2\left(2\right)m+(2{)}^2=8 \\ (m-2{)}^2=8 \end{gathered}$$

Use square root property.

$$\begin{gathered} m-2=\pm \sqrt{8} \\ m-2=\pm 2\sqrt{2} \end{gathered}$$

Isolate the term.     

$m=2\pm 2\sqrt{2}$

Rewrite to show two solutions.

$$\begin{gathered} m=2+2\sqrt{2}, \\ m=2-2\sqrt{2} \end{gathered}$$