Question

Solve quadratic equation using the square root property:$\frac{4}{3}{v}^2+4=28$

Short answer

The required result is$v=3\sqrt{2}or-3\sqrt{2}$

Step-by-step solution

Given information 

The given expression is$\frac{4}{3}{v}^2+4=28$

 Simplifying the equation

First subtract 4 from both side of equation

$\frac{4}{3}{v}^2=24$

Simplify further ,

$v^2=18$

Square root property 

If $x^2=k$and $k\ge 0$then , $x=\sqrt{k}or-\sqrt{k}$

$18\ge 0$

$v=\sqrt{18}or-\sqrt{18}$

localid="1657720344280" $v=3\sqrt{2}or-3\sqrt{2}$