Question

Solve quadratic equation using the square root property:$t^2+18=0$

Short answer

The required result is roots are not defined .

Step-by-step solution

Given information 

The given expression is$t^2+18=0$

 Simplifying the equation

Subtract 18 from both side of equation .

$$\begin{gathered} t^2-18+18=0-18 \\ {t}^2=-18 \end{gathered}$$

Square root property 

If $x^2=k$and $k\ge 0$then $x=\sqrt{k}or-\sqrt{k}$

$-18\le 0$

Then , roots are not defined .$-18\le 0$