Question

Solve the quadratic equation using square root property.

$(y-5{)}^2=36$

Short answer

The solutions are$y=-1,11$.

Step-by-step solution

Given Information. 

The Given equation is$(y-5{)}^2=36$.

Use square root property. 

$y-5=\pm \sqrt{36}$

Solve radical.

$y-5=\pm 6$

Solve for y.

$y=\pm 6+5$

Rewrite to show two solutions

$$\begin{gathered} y=6+5 \\ y=11, \\ y=-6+5 \\ y=-1 \end{gathered}$$

Thus, the solutions are$y=-1,11$.